如何在angular2中使用多个路由器插座？

Question

我有一个主 router-outlet，用于显示登录屏幕 (/login) 和主要内容屏幕（登录后显示）(/main)。

一旦用户进入内容屏幕，我想在顶部显示一个导航栏，其中有 2 个选项（例如，'Overview'、'Insights'）。此导航栏在 OverviewComponent 和 InsightsComponent

中很常见

在此导航栏下方，我想显示另一个路由器插座，它会根据用户在导航栏中点击的内容加载 OverviewComponent 或 InsightsComponent。如果我将 '/overview' 和 /'insights' 作为路由，它会直接向我显示相应的组件，但不会显示导航栏。

以下是我当前的路由配置（这是不对的）：

const appRoutes: Routes = [
  { path: 'main', component:  MainComponent},
  { path: 'overview', component:  OverviewComponent},
  { path: 'insights', component: InsightsComponent },
  { path: 'login', component: LoginComponent },
  { path: '',
    redirectTo: '/login',
    pathMatch: 'full'
  },
  { path: '**', component: PageNotFoundComponent }
];

请告诉我我们是否可以在 angular2 angular4 中实现这一点。我正在使用以下版本：

"@angular/core": "^4.0.0"
"@angular/router": "^4.0.0"
"@angular/cli": "1.0.1"

******************尝试 2 - 仍然无效******************

const appRoutes: Routes = [
  { path: 'main',
    children: [
      { path: '', component: MainComponent },
      { path: 'overview', component:  OverviewComponent },
      { path: 'insights', component: InsightsComponent },
    ]

  },
  { path: 'login', component: LoginComponent },
  { path: '',
    redirectTo: '/login',
    pathMatch: 'full'
  },
  { path: '**', component: PageNotFoundComponent }
];

*******尝试 2 - 包含所有组件的 Sudo 代码 - 仍然无法正常工作*******

//app.component.html

<router-outlet></router-outlet>


//app.module.ts

const appRoutes: Routes = [
  { path: 'main',
    children: [
      { path: '', component: MainComponent },
      { path: 'overview', component:  OverviewComponent },
      { path: 'insights', component: InsightsComponent },
    ]

  },
  { path: 'login', component: LoginComponent },
  { path: '',
    redirectTo: '/login',
    pathMatch: 'full'
  },
  { path: '**', component: PageNotFoundComponent }
];

//login.component.html
<div class="text-center vertical-center">
    <form>
        <div class="horizontal">
            <label for="">Email</label>
            <input class="form-control" type="text" name="" value="">
        </div>
        <div class="horizontal">
            <label for="">Password</label>
            <input class="form-control" type="password" name="" value="">
        </div>
        <button class="btn btn-primary" (click)="navigate()">Login</button>
    </form>
</div>

//login.component.ts
navigate() {
    this.router.navigate(['./main']);
  }

//main.component.html

<app-header></app-header>
<router-outlet></router-outlet>


//app.header.html

<ul class="nav navbar-nav">
               <li class=""><a routerLink="/main/overview" routerLinkActive="active">OVERVIEW</a></li>
                <li class=""><a routerLink="/main/insights" routerLinkActive="active">INSIGHTS</a></li>
            </ul>

//overview.html
<p>This is overview section</p>

//insights.html
<p>This is insights section</p>

********尝试 3 - 工作**********

const appRoutes: Routes = [
  { path: 'main', component: MainComponent,
    children: [
      { path: '', component: MainComponent },
      { path: 'overview', component:  OverviewComponent },
      { path: 'insights', component: InsightsComponent },
    ]

  },
  { path: 'login', component: LoginComponent },
  { path: '',
    redirectTo: '/login',
    pathMatch: 'full'
  },
  { path: '**', component: PageNotFoundComponent }
];

Answer 1

我想我收集到了你想要达到的目标。我可以建议您使用变量来模拟某种状态更改，并将其分配给组件视图吗？让你的 app.component.html 只包含一个路由器插座。创建一个新的 main.component.html 来复制现有的 component.html

`<app-header></app-header>`

将 href 替换为 *(click)="handleChange(<linkValue>)'"

所以每个 link 看起来如下。

<ul class="nav navbar-nav"> <li class=""><a href="/main/overview">OVERVIEW</a></li>

handleChange方法：声明当前链接 - public currentLink string; // or public currentLink: string = '<a default value>'; public handleChange(link: string) { this.currentLink = link; }

创建 view.component。

示例选择器<view [link]='currentLink'></view>

给视图组件一个 @Input() public link: string;

back to view.component.html

<div id="overview" *ngIf="link = 'overview'">overview content</div> <div id="main" *ngIf="link = 'main'">overview content</div>

然后您可以将它们重构为单独的子组件。

概览：您正在使 app-header 成为处理 'link' 变量的全局组件。我会建议查看 ngRx 或一般的应用程序状态方法。因为这可能是管理 UI.

的好方法

Answer 2

因此，如果我答对了问题，您希望最初拥有登录屏幕，并且在用户登录后，您希望他看到显示导航的 /main。登录屏幕和主应用程序应该有不同的布局。

我们有一个类似的案例并使用 LayoutComponent。这是一个简化的例子。

// This is main component that get's bootstrapped that has 'top-level' router.
@Component({selector: 'app', template: '<router-outlet></router-outlet>'})
class AppComponent {}

// main router config
// Here AuthModule has router with login and logout configured and LoginGuard
// redirect the user to /auth/login when she is not authenticated.
// We're using lazy-loading but you can use direct component instead
export const APP_ROUTES: Routes = [
  {path: '', redirectTo: 'main', pathMatch: 'full'},
  {path: 'auth', loadChildren: '../modules/+auth/auth.module#AuthModule'},
  {
    path: '',
    component: LayoutComponent,
    canActivate: [LoginGuard],
    children: [
      {path: 'main', loadChildren: '../modules/+main/main.module#MainModule'}
    ]
  }
];

// AuthModule/LoginComponent has own template and it will be rendered
// into 'top-level' router-outlet.

// LayoutComponent
// Here you define your main application layout that can include navigation
// and anything else that are global to the app. It has another router-outlet
// that get rendered when the layout is accessible (which in this case when the user is authenticated).
@Component({
  selector: 'app-layout',
  template: `
    <div id="wrapper">
      <app-sidebar></app-sidebar>
      <div id="page-wrapper" class="gray-bg dashboard-1" adjust-content-height>
        <router-outlet></router-outlet>
      </div>
    </div>
    <notifications></notifications>
    <error-modal></error-modal>
  `
})
export class LayoutComponent {}

// Auth/LoginComponent can have its own template that will have different layout from the main application

所以流程是这样的：

当用户尝试加载 / 然后她重定向到 /main
如果用户未通过身份验证，她将重定向到 /auth/login，否则她将加载 /main

希望对您有所帮助。

编辑：使用示例应用程序更新了 sickelap/ng-starter 存储库：

延迟加载路由
布局
和其他东西

如何在angular2中使用多个路由器插座？

How to use multiple router-outlet in angular2?

router

angular-cli

router-outlet

angular