Oracle

Question

假设我有以下数据：

Create Table Pm_Test (
Ticket_id Number,
Department_From varchar2(100),
Department_To varchar2(100),
Routing_Date Date
);

Insert Into Pm_Test Values (1,'A','B',To_Date('20140101120005','yyyymmddhh24miss'));
Insert Into Pm_Test Values (1,'B','C',To_Date('20140101130004','yyyymmddhh24miss'));
Insert Into Pm_Test Values (1,'C','D',To_Date('20140101130004','yyyymmddhh24miss'));
Insert Into Pm_Test Values (1,'D','E',To_Date('20140201150004','yyyymmddhh24miss'));
Insert Into Pm_Test Values (2,'A','B',To_Date('20140102120005','yyyymmddhh24miss'));
Insert Into Pm_Test Values (3,'D','B',To_Date('20140102120005','yyyymmddhh24miss'));
Insert Into Pm_Test Values (3,'B','A',To_Date('20140102170005','yyyymmddhh24miss'));

对于以下要求，我已经添加了两个虚拟列，我认为它们可能是必要的：

Select t.*,
Count(Ticket_id)  Over (Partition By Ticket_id Order By Ticket_id) Cnt_Id,
Row_Number() Over (Partition By Ticket_id Order By Ticket_id ) row_number
From Pm_Test t;

1) 我想通过添加列 PROCESSING_TIME 来测量每张票在一个部门（successor_department 的 routing_date - 前任部门的 routing_date 中停留的时间:

2) 我想通过添加列 TOTAL_PROCESSING_TIME:

来测量总处理时间

这样做需要哪些 SQL 语句？

非常感谢您！

Answer 1

要按照您描述的方式解决您的问题，以下 sql 应该可以帮助您解决问题。要记住的一件事是，如果这是它的真实意图，那么这个数据模型似乎并不是捕获处理时间的最有效方法，因为没有测量第一个获得工单的部门。

 select dept.ticket_id, department_from, department_to, routing_date, dept_processing_time, total_ticket_processing_time
from
(select ticket_id, max(routing_date) - min(routing_date) total_ticket_processing_time
from pm_test
group by ticket_id) total
join
(select ticket_id, department_from, department_to, routing_date, 
coalesce(routing_date - lag(routing_date) over (partition by ticket_id order by routing_date), 0) dept_processing_time
from pm_test) dept
on (total.ticket_id = dept.ticket_id);

Answer 2

此查询生成所需的输出。用于计算的解析函数 max()、min() 和 lag()。结果以小时为单位，就像您的问题一样。

SQLFiddle

select t.ticket_id, t.department_from, t.department_to, 
    to_char(t.routing_date, 'mm.dd.yy hh24:mi:ss') rd,
    count(ticket_id)  over (partition by ticket_id) cnt_id,
    row_number() over (partition by ticket_id order by t.routing_date ) rn,
    round(24 * (t.routing_date-
      nvl(lag(t.routing_date) over (partition by ticket_id 
        order by t.routing_date), routing_date) ) , 8) dept_time,
    round(24 * (max(t.routing_date) over (partition by ticket_id) 
      - min(t.routing_date) over (partition by ticket_id)), 8) total_time
  from pm_test t

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