Python 如何将时间差累积到一个变量中

Question

我是一个 Python 新手，我真的很难将经过的时间累积到一个变量中。数据来自时间和考勤程序。我要寻找的是在每条记录中给定开始 dates/times 和结束 dates/time 的给定时间段内的总工作时间。我的代码如下：

import pyodbc
import datetime 
import time

fname = "\\frontoffice\z\data.mdb"
sname = "\\frontoffice\z\secured.mdw"    
connect_string = "Driver={Microsoft Access Driver (*.mdb, *.accdb)};DBQ=" + fname +";UID=me;PWD=password;systemDB=" + sname + ";"

cnxn = pyodbc.connect(connect_string)
cursor = cnxn.cursor()
SQL = "SELECT EmpID, Weekending, Department, PayType, StartTime, EndTime FROM EmpHours WHERE EmpID=" + str(1) + " AND Weekending = #28/03/2015#;"
ttime = 0.0

for timerec in cursor.execute(SQL):
    print timerec.Department, timerec.PayType,
    if timerec.StartTime is not None:
        print timerec.StartTime,
    else:
        print "",

    if timerec.EndTime is not None:
        print timerec.EndTime,
    else:
        print "",

    if timerec.StartTime is not None and timerec.EndTime is not None:
        print timerec.EndTime - timerec.StartTime

        #ttime = ttime + timerec.EndTime - timerec.StartTime

        print ttime

    else:
        print "n/a"

我的输出是：

Admin Regular 2015-03-23 17:04:33 2015-03-23 17:04:41 0:00:08
0.0
Admin Regular 2015-03-23 17:04:51 2015-03-23 17:04:57 0:00:06
0.0
Admin Regular 2015-03-23 17:05:04  n/a
Admin Regular 2015-03-23 17:05:13 2015-03-23 17:05:20 0:00:07
0.0
Admin Regular 2015-03-23 17:05:26 2015-03-23 17:05:33 0:00:07
0.0
Admin Regular 2015-03-23 17:06:09 2015-03-23 17:06:15 0:00:06
0.0
Admin Regular 2015-03-23 17:06:22 2015-03-23 17:06:28 0:00:06
0.0
Admin Regular 2015-03-23 17:06:35 2015-03-23 17:06:42 0:00:07
0.0
Admin Regular 2015-03-23 17:07:17 2015-03-23 17:07:23 0:00:06
0.0
Admin Regular 2015-03-23 17:07:29 2015-03-23 17:07:35 0:00:06
0.0
Admin Regular 2015-03-23 17:07:42 2015-03-23 17:07:48 0:00:06
0.0
Admin Regular 2015-03-23 17:08:45 2015-03-23 17:08:52 0:00:07
0.0
Admin Regular 2015-03-23 17:08:59 2015-03-23 17:09:05 0:00:06
0.0

我似乎无法将 timerec.StartTime/EndTime 更改为纪元以来的秒数，也无法将 ttime 初始化为空 datetime.datetime 变量。有什么想法吗？

Answer 1

您已经有 datetime.datetime() 个对象，减去它们得到 datetime.timedelta()。只需对这些对象求和：

ttime = datetime.timedelta()

for timerec in cursor.execute(SQL):
    if timerec.StartTime and timerec.EndTime:
        ttime += timerec.EndTime - timerec.StartTime

在 for 循环结束时，ttime 是一个 timedelta() 对象，代表工作的总时间。您可以将其表示为秒数：

ttime_seconds = ttime.total_seconds()

Answer 2

您也可以在 SQL 级别执行此操作，这可能更容易：

SQL = "SELECT EmpID, Weekending, Department, PayType, StartTime, EndTime, DATEDIFF(SECOND, StartTime, EndTime) AS SecondDiff FROM EmpHours WHERE EmpID=" + str(1) + " AND Weekending = #28/03/2015#;"

将 SECOND 替换为 MINUTE、WEEK、YEAR 或您需要的任何内容。祝你好运！

Python 如何将时间差累积到一个变量中

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