如何显示单个用户的多个联系人swift 3
how to display multiple contact of a single user swift 3
我正在从 contacts.But 中获取用户的信息,例如他的姓名、phone 电话号码和电子邮件 ID 它只显示第一个联系人 number.IF 一个人有多个联系电话,它没有显示第二个 number.Can 有人帮忙吗?我正在使用这个功能
其中 EVContactProtocol 是库的一部分
func didChooseContacts(_ contacts: [EVContactProtocol]?) {
var conlist : String = ""
if let cons = contacts {
for con in cons {
if let fullname = con.fullname(),let email1 = con.email , let phoneNumber = con.phone {
conlist += fullname + "\n"
print("Full Name: ",fullname)
print("Email: ",email1)
print("Phone Number: ",phoneNumber)
}
}
self.textView?.text = conlist
} else {
print("I got nothing")
}
let _ = self.navigationController?.popViewController(animated: true)
}
你应该试试这个:
import Contacts
class ViewController: UIViewController
{
lazy var contacts: [CNContact] =
{
let contactStore = CNContactStore()
let keysToFetch = [
CNContactFormatter.descriptorForRequiredKeys(for: .fullName),
CNContactEmailAddressesKey,
CNContactPhoneNumbersKey] as [Any]
// Get all the containers
var allContainers: [CNContainer] = []
do
{
allContainers = try contactStore.containers(matching: nil)
}
catch
{
print("Error fetching containers")
}
var results: [CNContact] = []
// Iterate all containers and append their contacts to our results array
for container in allContainers
{
let fetchPredicate = CNContact.predicateForContactsInContainer(withIdentifier: container.identifier)
do
{
let containerResults = try contactStore.unifiedContacts(matching: fetchPredicate, keysToFetch: keysToFetch as! [CNKeyDescriptor])
results.append(contentsOf: containerResults)
}
catch
{
print("Error fetching results for container")
}
}
return results
}()
override func viewDidLoad()
{
super.viewDidLoad()
print(contacts[0].givenName)
print(contacts[0].phoneNumbers)
print(contacts[0].emailAddresses)
print(contacts)
}
}
我正在从 contacts.But 中获取用户的信息,例如他的姓名、phone 电话号码和电子邮件 ID 它只显示第一个联系人 number.IF 一个人有多个联系电话,它没有显示第二个 number.Can 有人帮忙吗?我正在使用这个功能 其中 EVContactProtocol 是库的一部分
func didChooseContacts(_ contacts: [EVContactProtocol]?) {
var conlist : String = ""
if let cons = contacts {
for con in cons {
if let fullname = con.fullname(),let email1 = con.email , let phoneNumber = con.phone {
conlist += fullname + "\n"
print("Full Name: ",fullname)
print("Email: ",email1)
print("Phone Number: ",phoneNumber)
}
}
self.textView?.text = conlist
} else {
print("I got nothing")
}
let _ = self.navigationController?.popViewController(animated: true)
}
你应该试试这个:
import Contacts
class ViewController: UIViewController
{
lazy var contacts: [CNContact] =
{
let contactStore = CNContactStore()
let keysToFetch = [
CNContactFormatter.descriptorForRequiredKeys(for: .fullName),
CNContactEmailAddressesKey,
CNContactPhoneNumbersKey] as [Any]
// Get all the containers
var allContainers: [CNContainer] = []
do
{
allContainers = try contactStore.containers(matching: nil)
}
catch
{
print("Error fetching containers")
}
var results: [CNContact] = []
// Iterate all containers and append their contacts to our results array
for container in allContainers
{
let fetchPredicate = CNContact.predicateForContactsInContainer(withIdentifier: container.identifier)
do
{
let containerResults = try contactStore.unifiedContacts(matching: fetchPredicate, keysToFetch: keysToFetch as! [CNKeyDescriptor])
results.append(contentsOf: containerResults)
}
catch
{
print("Error fetching results for container")
}
}
return results
}()
override func viewDidLoad()
{
super.viewDidLoad()
print(contacts[0].givenName)
print(contacts[0].phoneNumbers)
print(contacts[0].emailAddresses)
print(contacts)
}
}