找到第一个 space 字符的索引?

Find the index of the first space character?

我已经编写了将数据值读取和写入数组列表的功能代码。尽管它 return 包含所有内容,但如果一个值有多个单词,我如何排除第一个单词?

  // 3 points
static ArrayList<String> Q2(String filename) {

    // You are given a file (filename) containing a different random phrase on each line. Return an
    // ArrayList containing each phrase, but without the first word of each phrase.
    //
    // Example: If the files contains the 2 phrases "roofed crossover" and "beneficiary charles frederick worth" the
    // ArrayList should contain "crossover" and "charles frederick worth"
    ArrayList<String> al = new ArrayList<String>();

    try {
        for(String s : Files.readAllLines(Paths.get(filename))){


            al.add(s.substring(9));
        }
    } catch (IOException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

    return al;
}

评分者的评价如下:

Incorrect on input: data/phrases0.txt
Expected output : [algae, blood platelet, charles frederick worth, convert, crossover, eye movement, ferocity, itch, lake albert, loewi, mountainside, peach, sontag, specialty, supposition, surprised endometriosis, testimonial, trial golden fleece, waterproofing, wrongdoer]
Your output     : [ferocity, peach, ed algae, wi, ossover, ry charles frederick worth, ised endometriosis, wrongdoer,  lake albert, ng waterproofing, d eye movement, mountainside, g testimonial, c itch, tal sontag, ive blood platelet, golden fleece, ic specialty, convert, s supposition]

我已经return返回了一些没有第一个字符串的值,但是有些单词比子字符串可以达到的要大。

迭代拆分字符串时忽略第一项可能是最简单的方法

    data = "";
    for(String s : Files.readAllLines(Paths.get(filename))){    
         line = s.split(",");
         for (int i = 1; i < line.length; i++) {
             String data = line[i] + System.getProperty("line.separator");
             list.add(data);
         }
    }

根据评论,您还需要在输出中使用逗号。

您只需要删除 space 之前的第一个单词,然后只需使用此代码:从 space 字符的位置获取输入字符串的子字符串。

for(String s : Files.readAllLines(Paths.get(filename))){
    al.add(s.substring(s.indexOf(" ")+1)));
}