Mysql - 错误代码 1054 'where clause' 中的未知列 'players.p_name'
Mysql - Error code 1054 Unknown cloumn 'players.p_name' in 'where clause'
您好,
首先我要你展示我的 table 我有:
CREATE TABLE `channels` (
`channel_id` int(11) NOT NULL AUTO_INCREMENT,
`channel_name` varchar(45) DEFAULT NULL,
PRIMARY KEY (`channel_id`)
) ENGINE=InnoDB AUTO_INCREMENT=2 DEFAULT CHARSET=utf8
CREATE TABLE `gamepoints` (
`gp_id` int(11) NOT NULL AUTO_INCREMENT,
`gamble` int(11) DEFAULT NULL,
`roulette` int(11) DEFAULT NULL,
`blackjack` int(11) DEFAULT NULL,
`slots` int(11) DEFAULT NULL,
PRIMARY KEY (`gp_id`)
) ENGINE=InnoDB AUTO_INCREMENT=4 DEFAULT CHARSET=utf8
CREATE TABLE `player_channel` (
`pc_id` int(11) NOT NULL AUTO_INCREMENT,
`players_id` int(11) DEFAULT NULL,
`channel_id` int(11) DEFAULT NULL,
PRIMARY KEY (`pc_id`),
KEY `players_id_idx` (`players_id`),
KEY `channel_id_idx` (`channel_id`),
CONSTRAINT `channel_id` FOREIGN KEY (`channel_id`) REFERENCES `channels` (`channel_id`) ON DELETE NO ACTION ON UPDATE NO ACTION,
CONSTRAINT `players_id` FOREIGN KEY (`players_id`) REFERENCES `players` (`players_id`) ON DELETE NO ACTION ON UPDATE NO ACTION
) ENGINE=InnoDB AUTO_INCREMENT=3 DEFAULT CHARSET=utf8
CREATE TABLE `players` (
`players_id` int(11) NOT NULL AUTO_INCREMENT,
`p_name` varchar(45) DEFAULT NULL,
`p_right` varchar(45) DEFAULT NULL,
`gp_id` int(11) DEFAULT NULL,
PRIMARY KEY (`players_id`),
KEY `gp_id_idx` (`gp_id`),
CONSTRAINT `gp_id` FOREIGN KEY (`gp_id`) REFERENCES `gamepoints` (`gp_id`) ON DELETE NO ACTION ON UPDATE NO ACTION
) ENGINE=InnoDB AUTO_INCREMENT=4 DEFAULT CHARSET=utf8
我想要这个查询:
UPDATE gamepoints SET gamble = 1
WHERE gamepoints.gp_id = players.gp_id
AND players.p_name = "test"
AND player_channel.players_id = players.players_id
AND player_channel.channel_id = channels.channel_id
AND channels.channel_name = "test";
但是当我这样做时,我得到了这个错误:
Error Code: 1054. Unknown column 'players.p_name' in 'where clause'
我不知道我做错了什么,我也尝试在设置为从所有 table 中添加之后,但这也不起作用。
如果有人能帮助我,我会很高兴:)
提前致谢
您省略了除 gamepoints
之外的所有人的 table 姓名。我建议您使用显式连接更新语法,这样更难出现此类错误:
UPDATE gamepoints t1
INNER JOIN players t2
ON t1.gp_id = t2.gp_id
INNER JOIN player_channel t3
ON t3.players_id = t2.players_id
INNER JOIN channels t4
ON t4.channel_id = t3.channel_id
SET t1.gamble = 1
WHERE t2.p_name = 'test' AND
t4.channel_name = 'test';
如果您想挽救当前的查询,那么它会开始看起来像这样:
UPDATE gamepoints, players, player_channel, channels
SET gamble = 1
WHERE -- a very large number of conditions
不赞成隐式连接的一个原因是它们混合了对结果集的正常限制和连接条件,所有这些都在同一个 WHERE
子句中。这不会发生在我使用显式连接编写的查询中。
您好,
首先我要你展示我的 table 我有:
CREATE TABLE `channels` (
`channel_id` int(11) NOT NULL AUTO_INCREMENT,
`channel_name` varchar(45) DEFAULT NULL,
PRIMARY KEY (`channel_id`)
) ENGINE=InnoDB AUTO_INCREMENT=2 DEFAULT CHARSET=utf8
CREATE TABLE `gamepoints` (
`gp_id` int(11) NOT NULL AUTO_INCREMENT,
`gamble` int(11) DEFAULT NULL,
`roulette` int(11) DEFAULT NULL,
`blackjack` int(11) DEFAULT NULL,
`slots` int(11) DEFAULT NULL,
PRIMARY KEY (`gp_id`)
) ENGINE=InnoDB AUTO_INCREMENT=4 DEFAULT CHARSET=utf8
CREATE TABLE `player_channel` (
`pc_id` int(11) NOT NULL AUTO_INCREMENT,
`players_id` int(11) DEFAULT NULL,
`channel_id` int(11) DEFAULT NULL,
PRIMARY KEY (`pc_id`),
KEY `players_id_idx` (`players_id`),
KEY `channel_id_idx` (`channel_id`),
CONSTRAINT `channel_id` FOREIGN KEY (`channel_id`) REFERENCES `channels` (`channel_id`) ON DELETE NO ACTION ON UPDATE NO ACTION,
CONSTRAINT `players_id` FOREIGN KEY (`players_id`) REFERENCES `players` (`players_id`) ON DELETE NO ACTION ON UPDATE NO ACTION
) ENGINE=InnoDB AUTO_INCREMENT=3 DEFAULT CHARSET=utf8
CREATE TABLE `players` (
`players_id` int(11) NOT NULL AUTO_INCREMENT,
`p_name` varchar(45) DEFAULT NULL,
`p_right` varchar(45) DEFAULT NULL,
`gp_id` int(11) DEFAULT NULL,
PRIMARY KEY (`players_id`),
KEY `gp_id_idx` (`gp_id`),
CONSTRAINT `gp_id` FOREIGN KEY (`gp_id`) REFERENCES `gamepoints` (`gp_id`) ON DELETE NO ACTION ON UPDATE NO ACTION
) ENGINE=InnoDB AUTO_INCREMENT=4 DEFAULT CHARSET=utf8
我想要这个查询:
UPDATE gamepoints SET gamble = 1
WHERE gamepoints.gp_id = players.gp_id
AND players.p_name = "test"
AND player_channel.players_id = players.players_id
AND player_channel.channel_id = channels.channel_id
AND channels.channel_name = "test";
但是当我这样做时,我得到了这个错误:
Error Code: 1054. Unknown column 'players.p_name' in 'where clause'
我不知道我做错了什么,我也尝试在设置为从所有 table 中添加之后,但这也不起作用。
如果有人能帮助我,我会很高兴:)
提前致谢
您省略了除 gamepoints
之外的所有人的 table 姓名。我建议您使用显式连接更新语法,这样更难出现此类错误:
UPDATE gamepoints t1
INNER JOIN players t2
ON t1.gp_id = t2.gp_id
INNER JOIN player_channel t3
ON t3.players_id = t2.players_id
INNER JOIN channels t4
ON t4.channel_id = t3.channel_id
SET t1.gamble = 1
WHERE t2.p_name = 'test' AND
t4.channel_name = 'test';
如果您想挽救当前的查询,那么它会开始看起来像这样:
UPDATE gamepoints, players, player_channel, channels
SET gamble = 1
WHERE -- a very large number of conditions
不赞成隐式连接的一个原因是它们混合了对结果集的正常限制和连接条件,所有这些都在同一个 WHERE
子句中。这不会发生在我使用显式连接编写的查询中。