如何在lxml中获取连接的子文本节点

How to get concatenated child text nodes in lxml

这是 HTML 示例:

<div class="wpb_text_column">
    <div class="wpb_wrapper">
      <p style="text-align: center;"><a href="http://somepage1.com">First text part </a></p>
      <p style="text-align: center;"><a href="http://somepage2.com">Second text part </a></p>
      <p style="text-align: center;"><a href="http://somepage3.com">Third text part</a></p>
    </div> 
</div>
<div class="wpb_text_column">
    <div class="wpb_wrapper">
      <p style="text-align: center;"><a href="http://somepage4.com">First text part </a></p>
      <p style="text-align: center;"><a href="http://somepage5.com">Second text part</a></p>
    </div> 
</div>

使用以下代码

tree = html.fromstring(html_sample)
tree.xpath('//div[@class="wpb_text_column"]/div[@class="wpb_wrapper"]/p/a/text()')

我可以获得文本值列表

['First text part ', 'Second text part ', 'Third text part', 'First text part ', 'Second text part']

但是,我想从每个 div 中获取所有值作为单个字符串,如

['First text part Second text part Third text part', 'First text part Second text part']

//div[@class="wpb_text_column"]/div[@class="wpb_wrapper"]/normalize-space()

好像是exact XPath to solve the problem,但是lxml不支持/normalize-space()语法:

lxml.etree.XPathEvalError: Invalid expression

那么如何在 lxml 中获得所需的输出?

使用以下代码解决:

[" ".join(string.text_content().split()) for string in tree.xpath('//div[@class="wpb_text_column"]/div[@class="wpb_wrapper"]')]