无法将“__NSDictionaryM”类型的值 (0x1055952b0) 转换为 'NSString' (0x1023e3c60)

Could not cast value of type '__NSDictionaryM' (0x1055952b0) to 'NSString' (0x1023e3c60)

我在我的代码中为 "pulp fiction" 使用 http://www.omdbapi.com/?t=pulp+fiction IMDB api。

应用程序中有一个搜索栏,我在这个搜索栏中输入 "pulp fiction" 然后输入。 我收到这个错误。

Could not cast value of type '__NSDictionaryM' (0x1055952b0) to 'NSString' (0x1023e3c60).

ViewController.swift:

//
//  ViewController.swift
//  IMDB Api Project
//
//  Created by gurkan on 5.05.2017.
//  Copyright © 2017 gurkan. All rights reserved.
//

import UIKit

class ViewController: UIViewController,UISearchBarDelegate {
    @IBOutlet weak var searchBar: UISearchBar!
    @IBOutlet weak var imageView: UIImageView!
    @IBOutlet weak var titleLabel: UILabel!
    @IBOutlet weak var directorLabel: UILabel!
    @IBOutlet weak var ratingLabel: UILabel!
    @IBOutlet weak var actorsLabel: UILabel!

    override func viewDidLoad() {
        super.viewDidLoad()

        searchBar.delegate = self
    }

    func searchBarSearchButtonClicked(_ searchBar: UISearchBar) {
        searchForMovie(title: searchBar.text!)
        searchBar.text = ""
    }

    func searchForMovie(title: String){
        //http://www.omdbapi.com/?t=pulp+fiction
        if let movie = title.addingPercentEncoding(withAllowedCharacters: CharacterSet.urlQueryAllowed){
            let url = URL(string: "http://www.omdbapi.com/?t=\(movie)")
            let session = URLSession.shared
            let task = session.dataTask(with: url!, completionHandler: { (data, response, error) in
                if error != nil {
                    print(error!)
                } else {
                    if data != nil {
                        do {
                            let jsonResult = try JSONSerialization.jsonObject(with: data!, options: JSONSerialization.ReadingOptions.mutableContainers)
                                as! String //Error Line!

                            let jsonString = jsonResult.components(separatedBy: "")

                            let jsonDict = jsonString as! Dictionary<String,String>

                            DispatchQueue.main.async {
                                print(jsonDict)
                            }
                        } catch {
                        }
                    }
                }
            })
            task.resume()
        }
    }
}

我该如何解决这个问题?

有两点不对。

首先,这条线强制展开为 String

let jsonResult = try JSONSerialization.jsonObject(with: data!, options: JSONSerialization.ReadingOptions.mutableContainers)
                            as! String

简单删除 as! String - 不需要。 Swift 将推断类型并正确创建 jsonResult.

其次,您的代码假定返回的 JSON 响应是一个完全由 String 名称和 String 值组成的字典。查看您发布的 url 的响应,与 Ratings 值关联的对象实际上是一个字典。由于您强制将 jsonString 解包到字符串字典中,这将失败,因为它不是字符串字典。它是字符串和其他内容的字典 - 字典。

最简单的修复方法是:

替换此行:

let jsonDict = jsonString as! Dictionary<String,String>

let jsonDict = jsonString as! [String: AnyObject]