php/jQuery - 表单验证，获取动态添加的输入值

Question

我正在尝试使用 Formvalidation.io plugin 来动态添加输入字段。

这些是我的输入：

<div class="col-lg-4">

    <label class="control-label">Model</label>
    <select name="box[0].model" class="ui dropdown dropdown-model semantic-dropdown">
        <option value="">Choose Model</option>
        <option value="model_one">Model One</option>
        <option value="model_two">Model Two</option>
        <option value="model_three">Model Three</option>
    </select>

</div>

<div class="col-lg-4">
    <label class="control-label">Type</label>
    <select name="box[0].type" class="ui dropdown dropdown-type semantic-dropdown">
        <option value="">Choose Type</option>
        <option value="0">Ingen Konfiguration</option>
        <option value="1">Sommer</option>
        <option value="2">Vinter</option>
    </select>

</div>

<div class="col-lg-4">
    <label class="control-label">Temperatur</label>

    <select name="box[0].temperatur" class="ui dropdown dropdown-temperatur semantic-dropdown">
        <option value="">Choose Temperatur</option>
        <option value="0">No Temperature</option>
        <option value="1">2-8 Grader</option>
        <option value="2">15-25 Grader</option>
        <option value="3">Frozen</option>
    </select>

</div>
<a href="#" class="addButton">Add extra input</a>

还有，我的隐藏字段模板：

<!-- The template for adding new field -->
<div class="form-group hide" id="bookTemplate">
    <div class="col-lg-4">
        <select name="model" class="ui dropdown dropdown-model semantic-dropdown">
            <option value="">Choose Model</option>
            <option value="model_one">Model One</option>
            <option value="model_two">Model Two</option>
            <option value="model_three">Model Three</option>

        </select>

    </div>
    <div class="col-lg-4">
        <select name="type" class="ui dropdown dropdown-type semantic-dropdown">
            <option value="">Choose Type</option>
            <option value="0">Ingen Konfiguration</option>
            <option value="1">Sommer</option>
            <option value="2">Vinter</option>
        </select>

    </div>
    <div class="col-lg-4">

        <select name="temperatur" class="ui dropdown dropdown-temperatur semantic-dropdown">
            <option value="">Vælg Temperatur</option>
            <option value="0">No Temperature</option>
            <option value="1">2-8 Grader</option>
            <option value="2">15-25 Grader</option>
            <option value="3">Frozen</option>
        </select>

    </div>
    <div class="col-xs-1">
        <button type="button" class="btn btn-default removeButton"><i class="fa fa-minus"></i></button>
    </div>
</div>
<!-- END HIDDEN TEMPLATE-->

添加字段并动态验证它们的工作正常。但是，当提交表单时，我没有看到输入的值：这是上面的 var_dump($_POST)：

"array(4) {
  ["box"]=>
  array(3) {
    [0]=>
    string(1) "0"
    [1]=>
    string(1) "2"
    [2]=>
    string(1) "1"
  }
  ["model"]=>
  string(0) ""
  ["type"]=>
  string(0) ""
  ["temperatur"]=>
  string(0) ""

表单使用 AJAX:

提交

//Submit the form:
$('#bookingform').on('submit', function(e) { 
    e.preventDefault(); //prevent form from submitting
    $form = $(this);
    // Use Ajax to submit form data
    $.ajax({
        url: '/api/submit-form',
        type: 'POST',
        data: $form.serialize(),
        dataType: "json",
        success: function(data) {
            console.log(data.result);
            if (data.result == 'success') {
                console.log(data);
            } else {
                alert('Error #1');
            }
        },
        error: function(data) {
            console.log("ERROR");

        }
    });

});

运行一个console.log($form.serialize());在表格上：

box%5B0%5D.model=model_one&box%5B0%5D.type=1&box%5B0%5D.temperatur=1&model=&type=&temperatur=

如您所见，我没有得到 box[o].name 的值 - 此外，我对隐藏字段的输入值不感兴趣，只有当它们可见时 (box[].name)

编辑： 下面是用于添加输入的 javascript 代码：

bookIndex = 0;
.. code here that is not relevant ..          
// Add button click handler
          .on('click', '.addButton', function() {
              bookIndex++;
              var $template = $('#bookTemplate'),
                  $clone = $template
                  .clone()
                  .removeClass('hide')
                  .removeAttr('id')
                  .attr('data-book-index', bookIndex)
                  .insertBefore($template);

              // Update the name attributes
              $clone
                  .find('[name="model"]').attr('name', 'box[' + bookIndex + '].model').end()
                  .find('[name="type"]').attr('name', 'box[' + bookIndex + '].type').end()
                  .find('[name="temperatur"]').attr('name', 'box[' + bookIndex + '].temperatur').end();

              //Semantic Dropdown - refresh dynamic added dropdowns:
              $('.semantic-dropdown').dropdown();

              // Add new fields
              // Note that we also pass the validator rules for new field as the third parameter
              $('#bookingform')
                  .formValidation('addField', 'box[' + bookIndex + '].model', titleValidators)
                  .formValidation('addField', 'box[' + bookIndex + '].type', isbnValidators)
                  .formValidation('addField', 'box[' + bookIndex + '].temperatur', priceValidators);
          })

但是，如前所述，我可以动态添加输入，但问题是从动态添加的输入中获取值。我似乎也无法在 formvalidation.io 插件文档中找到它。

Answer 1

我认为问题在于数据类型，因为您发送的是 x-www-form-urlencoded 而不是 json 数据，因此请尝试更改：

dataType : "html" 并添加 contentType: "application/x-www-form-urlencoded; charset=UTF-8" // 默认设置

$.ajax({
    url: '/api/submit-form',
    type: 'POST',
    data: $form.serialize(),
    dataType : "html",
    contentType: "application/x-www-form-urlencoded; charset=UTF-8", 
   ....
});

php/jQuery - 表单验证，获取动态添加的输入值

php/jQuery - formvalidation, get value of dynamically added inputs

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