由字母组成的字母

Question

我是 python（版本 3.4.）的新手，我想知道如何编写与此类似的代码：

#block letters 
B1 = ("BBBB  ")
B2 = ("B   B ")
B3 = ("B   B ")
B4 = ("BBBB  ")
B5 = ("B   B ")
B6 = ("B   B ")
B7 = ("BBBB  ")
B = [B1, B2, B3, B4, B5, B6, B7]

E1 = ("EEEEE ")
E2 = ("E     ")
E3 = ("E     ")
E4 = ("EEEEE ")
E5 = ("E     ")
E6 = ("E     ")
E7 = ("EEEEE ")
E = [E1, E2, E3, E4, E5, E6, E7]

N1 = ("N    N")
N2 = ("NN   N")
N3 = ("N N  N")
N4 = ("N N  N")
N5 = ("N  N N")
N6 = ("N   NN")
N7 = ("N    N")
N = [N1, N2, N3, N4, N5, N6, N7]
for i in range(7):
    print(B[i], E[i], N[i])

我当前代码的输出如下所示：

BBBB   EEEEE  N    N
B   B  E      NN   N
B   B  E      N N  N
BBBB   EEEEE  N N  N
B   B  E      N  N N
B   B  E      N   NN
BBBB   EEEEE  N    N

但我想知道如何制作一个可以接受用户输入并以上面的样式打印的。我已经尝试了几个小时，但无法提出解决方案，很高兴看到其他人 do/have 是如何做到的。我认为当屏幕上放不下字母时会变得更加困难，所以我只想打印 10 个字母。谢谢

Answer 1

Assumption: you have all the letters constructed and that all letters have the same number of rows.

在这种情况下，您可以构造一个字典，例如：

ascii_art = { 'B': B, 'E': E, 'N': N }

当然在现实生活中，你构建一个包含所有字母、可能还有空格、数字等的字典

现在您可以将字符串作为输入：

text = input('Enter text? ')

接下来我们将字符串映射到一个可迭代的字母上：

chars = map(ascii_art.get,text)

最后我们将它们放入一个 zip 中并打印出来：

for d in zip(*chars):
    print(*d)

或者把它们放在一起：

ascii_art = { 'B': B, 'E': E, 'N': N }
text = input('Enter text? ')
chars = map(ascii_art.get,text)
for d in zip(*chars):
    print(*d)

如果你想限制输出到每行 10 个字符，你可以将代码更改为：

ascii_art = { 'B': B, 'E': E, 'N': N }
text = input('Enter text? ')
for i in range(0,len(text),10):
    chars = map(ascii_art.get,text[i:i+10])
    for d in zip(*chars):
        print(*d)

结果为：

Enter text? BEBEBEBBEBEENNNENNNN
BBBB   EEEEE  BBBB   EEEEE  BBBB   EEEEE  BBBB   BBBB   EEEEE  BBBB  
B   B  E      B   B  E      B   B  E      B   B  B   B  E      B   B 
B   B  E      B   B  E      B   B  E      B   B  B   B  E      B   B 
BBBB   EEEEE  BBBB   EEEEE  BBBB   EEEEE  BBBB   BBBB   EEEEE  BBBB  
B   B  E      B   B  E      B   B  E      B   B  B   B  E      B   B 
B   B  E      B   B  E      B   B  E      B   B  B   B  E      B   B 
BBBB   EEEEE  BBBB   EEEEE  BBBB   EEEEE  BBBB   BBBB   EEEEE  BBBB  
EEEEE  EEEEE  N    N N    N N    N EEEEE  N    N N    N N    N N    N
E      E      NN   N NN   N NN   N E      NN   N NN   N NN   N NN   N
E      E      N N  N N N  N N N  N E      N N  N N N  N N N  N N N  N
EEEEE  EEEEE  N N  N N N  N N N  N EEEEE  N N  N N N  N N N  N N N  N
E      E      N  N N N  N N N  N N E      N  N N N  N N N  N N N  N N
E      E      N   NN N   NN N   NN E      N   NN N   NN N   NN N   NN
EEEEE  EEEEE  N    N N    N N    N EEEEE  N    N N    N N    N N    N

我们可以通过添加一个额外的语句来每行添加一个空行：

ascii_art = { 'B': B, 'E': E, 'N': N }
text = input('Enter text? ')
for i in range(0,len(text),10):
    chars = map(ascii_art.get,text[i:i+10])
    for d in zip(*chars):
        print(*d)
    <b>print()</b>

这会生成：

Enter text? BBBEEEEEEENNNNN
BBBB   BBBB   BBBB   EEEEE  EEEEE  EEEEE  EEEEE  EEEEE  EEEEE  EEEEE 
B   B  B   B  B   B  E      E      E      E      E      E      E     
B   B  B   B  B   B  E      E      E      E      E      E      E     
BBBB   BBBB   BBBB   EEEEE  EEEEE  EEEEE  EEEEE  EEEEE  EEEEE  EEEEE 
B   B  B   B  B   B  E      E      E      E      E      E      E     
B   B  B   B  B   B  E      E      E      E      E      E      E     
BBBB   BBBB   BBBB   EEEEE  EEEEE  EEEEE  EEEEE  EEEEE  EEEEE  EEEEE 

N    N N    N N    N N    N N    N
NN   N NN   N NN   N NN   N NN   N
N N  N N N  N N N  N N N  N N N  N
N N  N N N  N N N  N N N  N N N  N
N  N N N  N N N  N N N  N N N  N N
N   NN N   NN N   NN N   NN N   NN
N    N N    N N    N N    N N    N

Answer 2

首先你必须像以前一样手动制作字母表，

N1 = ("N    N")
N2 = ("NN   N")
N3 = ("N N  N")
N4 = ("N N  N")
N5 = ("N  N N")
N6 = ("N   NN")
N7 = ("N    N")
N = [N1, N2, N3, N4, N5, N6, N7]

对每个字母都这样做。 [a-z]

# Now to let user input print your alphabet we will use a dictionary
# The the key is the letter and value is the printable  array
d = {'a':A,'b':B, ... , 'z':Z }

# Let's ask for user input:
line = input('What do you want to print> ')

# Now lets print what the user said in our alphabet
# iterate through the input and print it

sentence = map(d.get,line)
for letter in zip(*sentence):
    print(*letter)

Answer 3

在不变得超级复杂的情况下，您需要将每个字母硬核化（即静态定义）为字符串列表，类似于您对 B、E 和 N 的处理方式。

然后你构建一个字典，将每个字母映射到相应的列表：

>>> letters = {
...     'b': ["BBBB  ", "B   B ", "B   B ", "BBBB  ", "B   B ", "B   B ", "BBBB  "],
...     'e': ["EEEEE ", "E     ", "E     ", "EEEEE ", "E     ", "E     ", "EEEEE "],
...     'n': ["N    N", "NN   N", "N N  N", "N N  N", "N  N N", "N   NN", "N    N"]
... }

本例只包含字母b、e、n的定义，其他的你需要自己添加定义。确保所有列表的长度相同。一旦你完成了这些，你就可以使用这个字典来显示你从用户输入中得到的任何字母序列。演示：

>>> name = raw_input('enter your name: ')
enter your name: Ben
>>>
>>> for row in zip(*[letters[x.lower()] for x in name]):
...     print ''.join(row)
... 
BBBB  EEEEE N    N
B   B E     NN   N
B   B E     N N  N
BBBB  EEEEE N N  N
B   B E     N  N N
B   B E     N   NN
BBBB  EEEEE N    N

Answer 4

我找到了一个不太复杂（对我来说）的答案。我不明白如何使用 zip 或 map，但是这种方式与 out them.And 我可以理解代码在做什么。

A =["   A    ", #CREATING LIST OF LETTERS
    "  A A   ",
    " A   A  ",
    "AAAAAAA ",
    "A     A ",
    "A     A ",
    "A     A "]

以这种方式创建字母表然后：

#PUTTING LETTERS IN LIST
Alphabet = {"A":A,"B": B, "C": C, "D":D, "E":E ,"F":F, "N": N} 
#ASKER USER FOR INPUT
text = input('Enter text(Only takes A, B, C, D, E, F, N)? ')
#INPUT IN UPPERCASE
text = text.upper()
for i in range(7):
    for letter in text:
        temp = Alphabet[letter]
        print(temp[i],end="")
    print('')

由字母组成的字母

Letters Made From Letters

python

ascii-art