为什么服务没有启动？

Question

我有 MainActivity 和自定义服务名称 BatteryService.In 此服务我正在测量电池电量并对其进行一些处理。这是此服务的示例代码 class。

public class BatteryService extends Service {
    Context context ;
    @Override
    public int onStartCommand(Intent intent, int flags, int startId) {
        context = this;
        Log.v("Service Started : ", "" );
        BatteryService.this.registerReceiver(brodcastReceiver, new IntentFilter(Intent.ACTION_BATTERY_CHANGED));
        return super.onStartCommand(intent, flags, startId);
    }

    @Override
    public IBinder onBind(Intent intent) {
        return null;
    }

    protected BroadcastReceiver brodcastReceiver = new BroadcastReceiver() {
        int intlevel;
        MediaPlayer mediaPlayer;

        @Override
        public void onReceive(Context context, Intent intent) {


            if (intent.getAction().equals(Intent.ACTION_BATTERY_CHANGED)) {

                intlevel = intent.getIntExtra(BatteryManager.EXTRA_LEVEL, 0);
                String dtr;
                dtr = String.valueOf(intlevel);
                Toast.makeText(context, dtr, Toast.LENGTH_LONG).show();
                try {

                    intlevel = intent.getIntExtra("level", 0);
                    Log.v("Battery level is : ", "" + dtr);


                } catch (Exception e) {
                    // TODO: handle exception
                    e.printStackTrace();
                }
            }


            int status = intent.getIntExtra("status", BatteryManager.BATTERY_STATUS_UNKNOWN);
            String strStatus;

            if ((status == BatteryManager.BATTERY_STATUS_CHARGING) && (intlevel >= 90)) {


                Toast.makeText(context, "charging", Toast.LENGTH_LONG).show();
                mediaPlayer = MediaPlayer.create(BatteryService.this, R.raw.alarmsound);
                mediaPlayer.start();

            }

            if ((status == BatteryManager.BATTERY_STATUS_DISCHARGING) && (intlevel >= 99))

            {

                mediaPlayer.stop();

            }
        }


    };
}

And in Main Activity I have button and on that button click I am starting service such as :

public class MainActivity extends Activity {

Button btnStart;
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    btnStart = (Button) findViewById(R.id.btn_startService);
    btnStart.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            Log.v("Starting service","On Button click");
            Intent intent = new Intent(MainActivity.this, BatteryService.class);
            startService(intent);
        }
    });

}

}

并按照以下方式在清单中声明它

android:name="com.brokenfloorstudios.eyebattery.BatteryService" />

Answer 1

我发布这个答案是为了如果有人遇到与我遇到的问题相同的问题。这是一个小的。当我制作自己的自定义服务时，我在 Manifest 文件中的 Application 结束标记下方声明它。它应该在 manifest.It 中的应用程序标记中声明的位置花了一些时间来弄清楚，因为我在 Logcat 中没有收到任何错误或异常。

Answer 2

试试这个

 Intent a = new Intent();
  a.setAction (" *** insert service name here**");
StartService(a);

我通常将清单文件中的字符串复制并粘贴到我的 activity，因为它很容易出现拼写错误

为什么服务没有启动？

Why Service is not starting?

android

android-service