单击闪亮的操作按钮转到 flexdashboard 的另一页

Question

我的 test.Rmd.

中有以下代码

---
title: "Test Application"
runtime: shiny
output: 
  flexdashboard::flex_dashboard:
    orientation: rows
    vertical_layout: fill
---

sidebar {.sidebar}
==========================

Controllers
-----------------------
```{r}
actionButton("clickMe", label = "Click Me", class = "btn btn-lg btn-primary")
```

Page1
========================

Page2
=======================

最初，我的应用程序位于第 1 页。我想通过单击按钮 clickMe 将我的应用程序转到第 2 页。请帮我解决这个问题..！

Answer 1

您可以像这样使用 onClick 参数：

actionButton("clickMe", label = "Click Me", class = "btn btn-lg btn-primary", 
             onclick="location.href='#section-page2';")

单击闪亮的操作按钮转到 flexdashboard 的另一页

Go to another page of flexdashboard on click shiny actionbutton

user-interface

shiny

user-experience

shinyjs

flexdashboard