不能用 arduino 安排好时间?
Can't get time right with arduino?
我有一个小型 7 段 LED 显示屏,我想知道是否可以让它显示分钟的最后一位数字。下载了 Arduino 的时间库,我尝试了几种方法,使用 switch case 和 if else if,但都给出相同的结果,LED 显示屏只显示 0...你能指出我做错了什么吗?
#include <Time.h>
#include <TimeLib.h>
int led1=2;
int led2=3;
int led3=4;
int led4=5;
int led5=6;
int led6=7;
int led7=8;
int led8=9;
void setup() {
pinMode(led1,OUTPUT);
pinMode(led2,OUTPUT);
pinMode(led3,OUTPUT);
pinMode(led4,OUTPUT);
pinMode(led5,OUTPUT);
pinMode(led6,OUTPUT);
pinMode(led7,OUTPUT);
pinMode(led8,OUTPUT);
}
void loop(){
time_t t=minute();
int digit1=t%10;
if(digit1==1){
digitalWrite(led5, HIGH);
digitalWrite(led3, HIGH);
}else if(digit1==2)
{
digitalWrite(led6, HIGH);
digitalWrite(led5, HIGH);
digitalWrite(led4, HIGH);
digitalWrite(led1, HIGH);
digitalWrite(led2, HIGH);
} else if(digit1==3)
{
digitalWrite(led4, HIGH);
digitalWrite(led6, HIGH);
digitalWrite(led5, HIGH);
digitalWrite(led3, HIGH);
digitalWrite(led2, HIGH);
}else if(digit1==4)
{
digitalWrite(led4, HIGH);
digitalWrite(led7, HIGH);
digitalWrite(led5, HIGH);
digitalWrite(led3, HIGH);
}else if(digit1==5)
{
digitalWrite(led6, HIGH);
digitalWrite(led7, HIGH);
digitalWrite(led4, HIGH);
digitalWrite(led3, HIGH);
digitalWrite(led2, HIGH);
}else if(digit1==6)
{
digitalWrite(led6, HIGH);
digitalWrite(led7, HIGH);
digitalWrite(led4, HIGH);
digitalWrite(led1, HIGH);
digitalWrite(led2, HIGH);
digitalWrite(led3, HIGH);
}else if(digit1==7)
{
digitalWrite(led5, HIGH);
digitalWrite(led6, HIGH);
digitalWrite(led3, HIGH);
}else if(digit1==8)
{
digitalWrite(led1, HIGH);
digitalWrite(led2, HIGH);
digitalWrite(led3, HIGH);
digitalWrite(led4, HIGH);
digitalWrite(led5, HIGH);
digitalWrite(led6, HIGH);
digitalWrite(led7, HIGH);
}else if(digit1==9)
{
digitalWrite(led2, HIGH);
digitalWrite(led3, HIGH);
digitalWrite(led4, HIGH);
digitalWrite(led5, HIGH);
digitalWrite(led6, HIGH);
digitalWrite(led7, HIGH);
}else if(digit1==0)
{
digitalWrite(led1, HIGH);
digitalWrite(led2, HIGH);
digitalWrite(led3, HIGH);
digitalWrite(led5, HIGH);
digitalWrite(led6, HIGH);
digitalWrite(led7, HIGH);
}
}
您永远不会将任何引脚写为低电平。当下一分钟到来时,正确的 LED 灯可能会亮起,但旧的 LED 灯不会熄灭,因此您看不到任何变化。
为了避免每个循环都关闭和再次打开所有 LED,我会存储最后一个已知数字,并在每次循环迭代时查看数字是否已更改。如果有,请关闭所有灯,然后 运行 您在此处发布的代码。
您没有添加低电平条件,因此当引脚变高时它保持高电平。另外,我已经检查过,我认为你的接线不正确。我在下面发布了完整的代码和相应的连接。
#include <Time.h>
#include <TimeLib.h>
int a = 2;
int b = 3;
int c = 4;
int d = 5;
int e = 6;
int f = 7;
int g = 8;
int dp = 9;
void setup() {
pinMode(led1,OUTPUT);
pinMode(led2,OUTPUT);
pinMode(led3,OUTPUT);
pinMode(led4,OUTPUT);
pinMode(led5,OUTPUT);
pinMode(led6,OUTPUT);
pinMode(led7,OUTPUT);
pinMode(led8,OUTPUT);
}
void loop(){
time_t t=minute();
int digit1=t%10;
if(digit1==0) {
digitalWrite(a, HIGH);
digitalWrite(b, HIGH);
digitalWrite(c, HIGH);
digitalWrite(d, HIGH);
digitalWrite(e, HIGH);
digitalWrite(f, HIGH);
digitalWrite(g, LOW);
digitalWrite(dp, LOW);
}
else if(digit1==1) {
digitalWrite(a, LOW);
digitalWrite(b, HIGH);
digitalWrite(c, HIGH);
digitalWrite(d, LOW);
digitalWrite(e, LOW);
digitalWrite(f, LOW);
digitalWrite(g, LOW);
digitalWrite(dp, LOW);
}
else if(digit1==2) {
digitalWrite(a, HIGH);
digitalWrite(b, HIGH);
digitalWrite(c, LOW);
digitalWrite(d, HIGH);
digitalWrite(e, HIGH);
digitalWrite(f, LOW);
digitalWrite(g, HIGH);
digitalWrite(dp, LOW);
}
else if(digit1==3) {
digitalWrite(a, HIGH);
digitalWrite(b, HIGH);
digitalWrite(c, HIGH);
digitalWrite(d, HIGH);
digitalWrite(e, LOW);
digitalWrite(f, LOW);
digitalWrite(g, HIGH);
digitalWrite(dp, LOW);
}
else if(digit1==4) {
digitalWrite(a, LOW);
digitalWrite(b, HIGH);
digitalWrite(c, HIGH);
digitalWrite(d, LOW);
digitalWrite(e, LOW);
digitalWrite(f, HIGH);
digitalWrite(g, HIGH);
digitalWrite(dp, LOW);
}
else if(digit1==5) {
digitalWrite(a, HIGH);
digitalWrite(b, LOW);
digitalWrite(c, HIGH);
digitalWrite(d, HIGH);
digitalWrite(e, LOW);
digitalWrite(f, HIGH);
digitalWrite(g, HIGH);
digitalWrite(dp, LOW);
}
else if(digit1==6) {
digitalWrite(a, LOW);
digitalWrite(b, LOW);
digitalWrite(c, HIGH);
digitalWrite(d, HIGH);
digitalWrite(e, HIGH);
digitalWrite(f, HIGH);
digitalWrite(g, HIGH);
digitalWrite(dp, LOW);
}
else if(digit1==7) {
digitalWrite(a, HIGH);
digitalWrite(b, HIGH);
digitalWrite(c, HIGH);
digitalWrite(d, LOW);
digitalWrite(e, LOW);
digitalWrite(f, LOW);
digitalWrite(g, LOW);
digitalWrite(dp, LOW);
}
else if(digit1==8) {
digitalWrite(a, HIGH);
digitalWrite(b, HIGH);
digitalWrite(c, HIGH);
digitalWrite(d, HIGH);
digitalWrite(e, HIGH);
digitalWrite(f, HIGH);
digitalWrite(g, HIGH);
digitalWrite(dp, LOW);
}
else if(digit1==9) {
digitalWrite(a, HIGH);
digitalWrite(b, HIGH);
digitalWrite(c, HIGH);
digitalWrite(d, HIGH);
digitalWrite(e, LOW);
digitalWrite(f, HIGH);
digitalWrite(g, HIGH);
digitalWrite(dp, LOW);
}
}
我有一个小型 7 段 LED 显示屏,我想知道是否可以让它显示分钟的最后一位数字。下载了 Arduino 的时间库,我尝试了几种方法,使用 switch case 和 if else if,但都给出相同的结果,LED 显示屏只显示 0...你能指出我做错了什么吗?
#include <Time.h>
#include <TimeLib.h>
int led1=2;
int led2=3;
int led3=4;
int led4=5;
int led5=6;
int led6=7;
int led7=8;
int led8=9;
void setup() {
pinMode(led1,OUTPUT);
pinMode(led2,OUTPUT);
pinMode(led3,OUTPUT);
pinMode(led4,OUTPUT);
pinMode(led5,OUTPUT);
pinMode(led6,OUTPUT);
pinMode(led7,OUTPUT);
pinMode(led8,OUTPUT);
}
void loop(){
time_t t=minute();
int digit1=t%10;
if(digit1==1){
digitalWrite(led5, HIGH);
digitalWrite(led3, HIGH);
}else if(digit1==2)
{
digitalWrite(led6, HIGH);
digitalWrite(led5, HIGH);
digitalWrite(led4, HIGH);
digitalWrite(led1, HIGH);
digitalWrite(led2, HIGH);
} else if(digit1==3)
{
digitalWrite(led4, HIGH);
digitalWrite(led6, HIGH);
digitalWrite(led5, HIGH);
digitalWrite(led3, HIGH);
digitalWrite(led2, HIGH);
}else if(digit1==4)
{
digitalWrite(led4, HIGH);
digitalWrite(led7, HIGH);
digitalWrite(led5, HIGH);
digitalWrite(led3, HIGH);
}else if(digit1==5)
{
digitalWrite(led6, HIGH);
digitalWrite(led7, HIGH);
digitalWrite(led4, HIGH);
digitalWrite(led3, HIGH);
digitalWrite(led2, HIGH);
}else if(digit1==6)
{
digitalWrite(led6, HIGH);
digitalWrite(led7, HIGH);
digitalWrite(led4, HIGH);
digitalWrite(led1, HIGH);
digitalWrite(led2, HIGH);
digitalWrite(led3, HIGH);
}else if(digit1==7)
{
digitalWrite(led5, HIGH);
digitalWrite(led6, HIGH);
digitalWrite(led3, HIGH);
}else if(digit1==8)
{
digitalWrite(led1, HIGH);
digitalWrite(led2, HIGH);
digitalWrite(led3, HIGH);
digitalWrite(led4, HIGH);
digitalWrite(led5, HIGH);
digitalWrite(led6, HIGH);
digitalWrite(led7, HIGH);
}else if(digit1==9)
{
digitalWrite(led2, HIGH);
digitalWrite(led3, HIGH);
digitalWrite(led4, HIGH);
digitalWrite(led5, HIGH);
digitalWrite(led6, HIGH);
digitalWrite(led7, HIGH);
}else if(digit1==0)
{
digitalWrite(led1, HIGH);
digitalWrite(led2, HIGH);
digitalWrite(led3, HIGH);
digitalWrite(led5, HIGH);
digitalWrite(led6, HIGH);
digitalWrite(led7, HIGH);
}
}
您永远不会将任何引脚写为低电平。当下一分钟到来时,正确的 LED 灯可能会亮起,但旧的 LED 灯不会熄灭,因此您看不到任何变化。
为了避免每个循环都关闭和再次打开所有 LED,我会存储最后一个已知数字,并在每次循环迭代时查看数字是否已更改。如果有,请关闭所有灯,然后 运行 您在此处发布的代码。
您没有添加低电平条件,因此当引脚变高时它保持高电平。另外,我已经检查过,我认为你的接线不正确。我在下面发布了完整的代码和相应的连接。
#include <Time.h>
#include <TimeLib.h>
int a = 2;
int b = 3;
int c = 4;
int d = 5;
int e = 6;
int f = 7;
int g = 8;
int dp = 9;
void setup() {
pinMode(led1,OUTPUT);
pinMode(led2,OUTPUT);
pinMode(led3,OUTPUT);
pinMode(led4,OUTPUT);
pinMode(led5,OUTPUT);
pinMode(led6,OUTPUT);
pinMode(led7,OUTPUT);
pinMode(led8,OUTPUT);
}
void loop(){
time_t t=minute();
int digit1=t%10;
if(digit1==0) {
digitalWrite(a, HIGH);
digitalWrite(b, HIGH);
digitalWrite(c, HIGH);
digitalWrite(d, HIGH);
digitalWrite(e, HIGH);
digitalWrite(f, HIGH);
digitalWrite(g, LOW);
digitalWrite(dp, LOW);
}
else if(digit1==1) {
digitalWrite(a, LOW);
digitalWrite(b, HIGH);
digitalWrite(c, HIGH);
digitalWrite(d, LOW);
digitalWrite(e, LOW);
digitalWrite(f, LOW);
digitalWrite(g, LOW);
digitalWrite(dp, LOW);
}
else if(digit1==2) {
digitalWrite(a, HIGH);
digitalWrite(b, HIGH);
digitalWrite(c, LOW);
digitalWrite(d, HIGH);
digitalWrite(e, HIGH);
digitalWrite(f, LOW);
digitalWrite(g, HIGH);
digitalWrite(dp, LOW);
}
else if(digit1==3) {
digitalWrite(a, HIGH);
digitalWrite(b, HIGH);
digitalWrite(c, HIGH);
digitalWrite(d, HIGH);
digitalWrite(e, LOW);
digitalWrite(f, LOW);
digitalWrite(g, HIGH);
digitalWrite(dp, LOW);
}
else if(digit1==4) {
digitalWrite(a, LOW);
digitalWrite(b, HIGH);
digitalWrite(c, HIGH);
digitalWrite(d, LOW);
digitalWrite(e, LOW);
digitalWrite(f, HIGH);
digitalWrite(g, HIGH);
digitalWrite(dp, LOW);
}
else if(digit1==5) {
digitalWrite(a, HIGH);
digitalWrite(b, LOW);
digitalWrite(c, HIGH);
digitalWrite(d, HIGH);
digitalWrite(e, LOW);
digitalWrite(f, HIGH);
digitalWrite(g, HIGH);
digitalWrite(dp, LOW);
}
else if(digit1==6) {
digitalWrite(a, LOW);
digitalWrite(b, LOW);
digitalWrite(c, HIGH);
digitalWrite(d, HIGH);
digitalWrite(e, HIGH);
digitalWrite(f, HIGH);
digitalWrite(g, HIGH);
digitalWrite(dp, LOW);
}
else if(digit1==7) {
digitalWrite(a, HIGH);
digitalWrite(b, HIGH);
digitalWrite(c, HIGH);
digitalWrite(d, LOW);
digitalWrite(e, LOW);
digitalWrite(f, LOW);
digitalWrite(g, LOW);
digitalWrite(dp, LOW);
}
else if(digit1==8) {
digitalWrite(a, HIGH);
digitalWrite(b, HIGH);
digitalWrite(c, HIGH);
digitalWrite(d, HIGH);
digitalWrite(e, HIGH);
digitalWrite(f, HIGH);
digitalWrite(g, HIGH);
digitalWrite(dp, LOW);
}
else if(digit1==9) {
digitalWrite(a, HIGH);
digitalWrite(b, HIGH);
digitalWrite(c, HIGH);
digitalWrite(d, HIGH);
digitalWrite(e, LOW);
digitalWrite(f, HIGH);
digitalWrite(g, HIGH);
digitalWrite(dp, LOW);
}
}