将两个用户输入的数字相减,并显示结果
Subtracting two user input numbers, with a move and display the result
我是 MIPS 的新手,我正在使用 MARS。我不能走对,当我执行它时,它给了我一些 nuts o number。这是我目前的情况,如有任何帮助,我们将不胜感激。
.data
message1: .asciiz "Enter the any number to subtract :"
message2: .asciiz "\nEnter the any number to subtract :"
n1 : .word 0
n2 : .word 0
message3: .asciiz "\nThe subtraction of the two numbers is "
.text
main:
li $v0 4 #print out message1
la $a0 message1
syscall
li $v0 5 #read message1 as number1
syscall
sw $v0 n1 #store number
li $v0 4 #print out message2
la $a0 message2
syscall
li $v0 5 #read message2 as number2
syscall
sw $v0 n2 #store number
li $v0 4
la $a0 message3
syscall
lw $t0 n1
lw $t1 n2
sub $t0, $v0, $v0 # t0 = number1 s1 - number2 s2
li $v0, 1 # print integer
move $t0, $a0 # move t0 to a0
syscall # run
您的代码在此处 sub $t0, $v0, $v0
之前运行良好。当您减去时,您应该将结果放入参数寄存器 $a0
然后您可以使用 move
将结果放入return 注册 $v0
打印。
按照以下方式更改它们。
sub $t2, $t0, $t1 # t2 = t0 - t1
move $a0, $t2 # copy t2 to a0
li $v0, 1 # print integer
syscall #
执行此减法的另一种方法是您根本不需要 .word
和 lw
。如下
.data
message1: .asciiz "Enter the any number to subtract :"
message2: .asciiz "\nEnter the any number to subtract :"
message3: .asciiz "\nThe subtraction of the two numbers is "
.text
main:
li $v0 4 #print out message1
la $a0 message1
syscall
li $v0 5 #read message1 as number1
syscall
move $t0,$v0 # set $t0 to the content of $v0
li $v0 4 #print out message2
la $a0 message2
syscall
li $v0 5 #read message2 as number2
syscall
move $t1,$v0
li $v0 4
la $a0 message3
syscall
sub $a0, $t0, $t1 # t0 = number1 t1 = number2
li $v0, 1 # print integer
syscall # run
我是 MIPS 的新手,我正在使用 MARS。我不能走对,当我执行它时,它给了我一些 nuts o number。这是我目前的情况,如有任何帮助,我们将不胜感激。
.data
message1: .asciiz "Enter the any number to subtract :"
message2: .asciiz "\nEnter the any number to subtract :"
n1 : .word 0
n2 : .word 0
message3: .asciiz "\nThe subtraction of the two numbers is "
.text
main:
li $v0 4 #print out message1
la $a0 message1
syscall
li $v0 5 #read message1 as number1
syscall
sw $v0 n1 #store number
li $v0 4 #print out message2
la $a0 message2
syscall
li $v0 5 #read message2 as number2
syscall
sw $v0 n2 #store number
li $v0 4
la $a0 message3
syscall
lw $t0 n1
lw $t1 n2
sub $t0, $v0, $v0 # t0 = number1 s1 - number2 s2
li $v0, 1 # print integer
move $t0, $a0 # move t0 to a0
syscall # run
您的代码在此处 sub $t0, $v0, $v0
之前运行良好。当您减去时,您应该将结果放入参数寄存器 $a0
然后您可以使用 move
将结果放入return 注册 $v0
打印。
按照以下方式更改它们。
sub $t2, $t0, $t1 # t2 = t0 - t1
move $a0, $t2 # copy t2 to a0
li $v0, 1 # print integer
syscall #
执行此减法的另一种方法是您根本不需要 .word
和 lw
。如下
.data
message1: .asciiz "Enter the any number to subtract :"
message2: .asciiz "\nEnter the any number to subtract :"
message3: .asciiz "\nThe subtraction of the two numbers is "
.text
main:
li $v0 4 #print out message1
la $a0 message1
syscall
li $v0 5 #read message1 as number1
syscall
move $t0,$v0 # set $t0 to the content of $v0
li $v0 4 #print out message2
la $a0 message2
syscall
li $v0 5 #read message2 as number2
syscall
move $t1,$v0
li $v0 4
la $a0 message3
syscall
sub $a0, $t0, $t1 # t0 = number1 t1 = number2
li $v0, 1 # print integer
syscall # run