geom_hline 或 geom_vline 似乎不接受向量作为参考线,如果在函数内部调用并使用 facet_grid()
geom_hline or geom_vline does not seem to accept vector for reference line, if called inside a function and facet_grid() is used
如果我在自定义函数下调用它并且它从向量中获取值,我一直面临 geom_hline 或 geom_vline 的问题。它似乎工作正常,直到我在该函数 body.e.g 中添加 facet_grid()
无功能
c<- data.frame(A = c("carr","bike","truck","carr","truck","bike","bike","carr","truck","carr","truck","truck","carr","truck","truck"),
B = c(10,20,30,23,45,56,78,44,10,20,30,10,20,30,67),
D = c(1,2,3,1,2,3,2,3,2,3,2,2,3,2,1))
a = c(1:4)*4
ggplot(c, aes(A,B, color = D))+
geom_point()+
facet_grid( .~D)+
geom_hline(yintercept = a,linetype = "dotted",size =0.3)
`
我明白了:
但是有功能
tk_fun <- function(dat,x1,y1,clr){ # I need to have this a declared and defined with in function.
a = c(1:4)*4.5 p <- ggplot(dat, aes_string(colnames(dat)[1],colnames(dat)[2], color = colnames(dat)[3]))+
geom_point()+ facet_grid( .~dat[,3])+
geom_hline(yintercept = a,linetype = "dotted",size =0.3) return(p) } tk_fun(c,"A","B","D")
使用函数时出现此错误:
Error in $<-.data.frame
(*tmp*
, "PANEL", value = c(1L, 2L, 3L, 1L, :
replacement has 15 rows, data has 4
I hope someone can help me in figuring out, how to do it through function, without an error. Thanks
问题出在你对构面的定义上。您需要使用正确的变量名称创建适当的公式调用,而不是直接使用数据。使用 paste
和 as.formula
可以提供帮助。
tk_fun <- function(dat,x1,y1,clr){ # I need to have this a declared and defined with in function.
a = c(1:4)*4.5
p <- ggplot(dat, aes_string(colnames(dat)[1],colnames(dat)[2], color = colnames(dat)[3]))+
geom_point() +
facet_grid(as.formula(paste('. ~', names(dat)[3]))) +
geom_hline(yintercept = a, linetype = "dotted", size =0.3)
return(p)
}
如果我在自定义函数下调用它并且它从向量中获取值,我一直面临 geom_hline 或 geom_vline 的问题。它似乎工作正常,直到我在该函数 body.e.g 中添加 facet_grid() 无功能
c<- data.frame(A = c("carr","bike","truck","carr","truck","bike","bike","carr","truck","carr","truck","truck","carr","truck","truck"),
B = c(10,20,30,23,45,56,78,44,10,20,30,10,20,30,67),
D = c(1,2,3,1,2,3,2,3,2,3,2,2,3,2,1))
a = c(1:4)*4
ggplot(c, aes(A,B, color = D))+
geom_point()+
facet_grid( .~D)+
geom_hline(yintercept = a,linetype = "dotted",size =0.3)
`
我明白了:
但是有功能
tk_fun <- function(dat,x1,y1,clr){ # I need to have this a declared and defined with in function.
a = c(1:4)*4.5 p <- ggplot(dat, aes_string(colnames(dat)[1],colnames(dat)[2], color = colnames(dat)[3]))+
geom_point()+ facet_grid( .~dat[,3])+
geom_hline(yintercept = a,linetype = "dotted",size =0.3) return(p) } tk_fun(c,"A","B","D")
使用函数时出现此错误:
Error in
$<-.data.frame
(*tmp*
, "PANEL", value = c(1L, 2L, 3L, 1L, : replacement has 15 rows, data has 4 I hope someone can help me in figuring out, how to do it through function, without an error. Thanks
问题出在你对构面的定义上。您需要使用正确的变量名称创建适当的公式调用,而不是直接使用数据。使用 paste
和 as.formula
可以提供帮助。
tk_fun <- function(dat,x1,y1,clr){ # I need to have this a declared and defined with in function.
a = c(1:4)*4.5
p <- ggplot(dat, aes_string(colnames(dat)[1],colnames(dat)[2], color = colnames(dat)[3]))+
geom_point() +
facet_grid(as.formula(paste('. ~', names(dat)[3]))) +
geom_hline(yintercept = a, linetype = "dotted", size =0.3)
return(p)
}