根据另一列中的值计算一列中字符串出现的次数 Python

Count nr of occurrences of strings in one column based on value in other column Python

对于这个非常基本的问题提前表示抱歉,我知道到处都有关于这个问题的帖子,但我似乎也无法在其他网页上的所有帮助下解决这个问题。

首先,我是 python 的初学者,对于模糊的代码深表歉意。但我只是想计算某个字符串在第 2 列中出现的次数,而第 1 列中的值保持不变。如果这个值改变,循环应该重新开始。这听起来很简单,但我对 python 将我的文本文件作为字符串读取感到困惑(给我关于 strip 和 split 等的问题)。我似乎无法使这段代码正常工作。请有人帮助这个处于困境中的菜鸟!

输入:

    6    ABMV
    6    ABMV
    6    FOOD
    6    FOOD
    6    IDLE
    10    IDLE
    10    ABMV
    10    IDLE

代码:

    #! /usr/bin/env python

    from collections import Counter

    outfile = open ("counts_outfile.txt", "w")

    with open("test_counts.txt", "r") as infile:
        lines = infile.readlines()
        for i, item in enumerate(lines):
        lines[i] = item.rstrip().split('\t')
        last_chimp = lines[0][0]
        behavior = lines[0][1]
        nr_ABMV = 0
        nr_FOOD = 0
        nr_IDLE = 0

        for lines in infile:
            chimp = lines[0][0]
            behavior = lines[0][1]
            if chimp == last_chimp:
                if behavior == "ABMV":
                    nr_ABMV += 1
                elif behavior == "FOOD":
                    nr_FOOD += 1
                elif behavior == "IDLE":
                    nr_IDLE += 1
                else:
                    continue
        else:
            outline = "chimp_header %s\t%s\t%s\t%s" % (last_chimp, nr_ABMV, nr_FOOD, nr_IDLE)
            outfile.write(outline)
            last_chimp == lines[0][0]
            nr_ABMV = 0
            nr_FOOD = 0
            nr_IDLE = 0

    outfile.close()

提前谢谢你,你会帮助我,显然很多'chimps'(黑猩猩)很多!!

问候,

这是一个示例,与您的代码非常相似:

outfile = open ("counts_outfile.txt", "w")
outfile.write("chimp_header {:>4} {:4} {:4} {:4}\r\n".format('chimp', 'ABMV', 'FOOD', 'IDLE'))

with open("test_counts.txt", "r") as infile:
    lines = [ line.strip() for line in infile if line.strip() ]

last_chimp = lines[0].split()[0]
behavior = { "ABMV":0, "FOOD":0, "IDLE":0 }

for line in lines : 
    line_split = line.strip().split() 
    chimp = line_split[0]

    if chimp != last_chimp : 
        outfile.write("chimp_header {:>4} {:4} {:4} {:4}\r\n".format(last_chimp, behavior["ABMV"], behavior["FOOD"], behavior["IDLE"]))
        last_chimp = chimp
        behavior = { "ABMV":0, "FOOD":0, "IDLE":0 }
    behavior[line_split[1]] += 1

outfile.write("chimp_header {:>4} {:4} {:4} {:4}\r\n".format(last_chimp, behavior["ABMV"], behavior["FOOD"], behavior["IDLE"]))
outfile.close()

这是另一个使用 Counter 和字典的例子:

from collections import Counter

with open("test_counts.txt", "r") as infile:
    lines = [ tuple(line.strip().split()) for line in infile if line.strip() ]

chimps = { line[0] : { "ABMV":0, "FOOD":0, "IDLE":0 } for line in lines }
for k, v in Counter(lines).items() :
    chimps[k[0]][k[1]] = v

with open("counts_outfile.txt", "w") as outfile : 
    outfile.write("chimp_header {:>4} {:4} {:4} {:4}\r\n".format('chimp', 'ABMV', 'FOOD', 'IDLE'))
    for chimp in chimps : 
        outfile.write("chimp_header {:>4} {:4} {:4} {:4}\r\n".format(chimp, chimps[chimp]["ABMV"], chimps[chimp]["FOOD"], chimps[chimp]["IDLE"]))

两个示例产生相同的结果:

chimp_header chimp ABMV FOOD IDLE
chimp_header    6    2    2    1
chimp_header   10    1    0    2

我希望这能给你一些想法。