文件对话框不适用于 PyQt5?
File dialog not working with PyQt5?
这是我第一次尝试创建 GUI。我已经创建了一个简单的程序,其中包含一个应该打开文件浏览器的按钮和 return 该文件。我知道 PyQt5 有一些内置的文件对话框命令,但它们对我不起作用。我试图使用 https://pythonspot.com/en/pyqt5-file-dialog/ 上的教程。我还尝试了其他几种在线方法。我想不出它不起作用的原因。
import sys, os
from PyQt5.QtWidgets import QMainWindow, QApplication, QWidget, QInputDialog, QLineEdit, QFileDialog
from PyQt5 import QtCore, QtGui, QtWidgets
from PyQt5.QtGui import QIcon
class Ui_Form(object):
def setupUi(self, Form):
Form.setObjectName("Form")
Form.resize(1082, 800)
self.horizontalLayout_2 = QtWidgets.QHBoxLayout(Form)
self.horizontalLayout_2.setObjectName("horizontalLayout_2")
self.horizontalLayout = QtWidgets.QHBoxLayout()
self.horizontalLayout.setObjectName("horizontalLayout")
self.pushButton = QtWidgets.QPushButton(Form)
self.pushButton.setObjectName("pushButton")
self.horizontalLayout.addWidget(self.pushButton)
self.horizontalLayout_2.addLayout(self.horizontalLayout)
self.retranslateUi(Form)
QtCore.QMetaObject.connectSlotsByName(Form)
self.pushButton.clicked.connect(self.openFile)
def retranslateUi(self, Form):
_translate = QtCore.QCoreApplication.translate
Form.setWindowTitle(_translate("Form", "Form"))
self.pushButton.setText(_translate("Form", "PushButton"))
# FUNCTION BELOW NOT WORKING
def openFile(self):
options = QFileDialog.Options()
options |= QFileDialog.DontUseNativeDialog
fileName, _ = QFileDialog.getOpenFileName(self,"QFileDialog.getOpenFileName()", "","All Files (*);;Python Files (*.py)", options=options)
if fileName:
print(fileName)
if __name__ == "__main__":
import sys
app = QtWidgets.QApplication(sys.argv)
Form = QtWidgets.QWidget()
ui = Ui_Form()
ui.setupUi(Form)
Form.show()
sys.exit(app.exec_())
getOpenFileName
需要一个 QWidget
类型的对象作为参数,在您的情况下 Ui_Form 不是那种类型。
- 第一个解决方案:通过
None
:
fileName, _ = QFileDialog.getOpenFileName(None,"QFileDialog.getOpenFileName()", "","All Files (*);;Python Files (*.py)", options=options)
- 第二种解决方案:创建一个实现Ui_Form签证的class,并在其中创建openFile槽。
class Widget(QtWidgets.QWidget, Ui_Form):
def __init__(self, parent=None):
QtWidgets.QWidget.__init__(self, parent)
self.setupUi(self)
self.pushButton.clicked.connect(self.openFile)
def openFile(self):
options = QFileDialog.Options()
options |= QFileDialog.DontUseNativeDialog
fileName, _ = QFileDialog.getOpenFileName(self,"QFileDialog.getOpenFileName()", "","All Files (*);;Python Files (*.py)", options=options)
if fileName:
print(fileName)
您需要传递一个 QWidget 作为父级。我修改了您的代码以保存 Form
并稍后使用它。
class Ui_Form(object):
def setupUi(self, Form):
self.Form = Form # <-----
...
def openFile(self):
fileName, _ = QFileDialog.getOpenFileName(self.Form, # <-----
...
我找到的另一个解决方案是将函数更改为:
def openFileNameDialog(self):
fname = QFileDialog.getOpenFileName()
self.ui.lineEdit.setText(fname)
这是我第一次尝试创建 GUI。我已经创建了一个简单的程序,其中包含一个应该打开文件浏览器的按钮和 return 该文件。我知道 PyQt5 有一些内置的文件对话框命令,但它们对我不起作用。我试图使用 https://pythonspot.com/en/pyqt5-file-dialog/ 上的教程。我还尝试了其他几种在线方法。我想不出它不起作用的原因。
import sys, os
from PyQt5.QtWidgets import QMainWindow, QApplication, QWidget, QInputDialog, QLineEdit, QFileDialog
from PyQt5 import QtCore, QtGui, QtWidgets
from PyQt5.QtGui import QIcon
class Ui_Form(object):
def setupUi(self, Form):
Form.setObjectName("Form")
Form.resize(1082, 800)
self.horizontalLayout_2 = QtWidgets.QHBoxLayout(Form)
self.horizontalLayout_2.setObjectName("horizontalLayout_2")
self.horizontalLayout = QtWidgets.QHBoxLayout()
self.horizontalLayout.setObjectName("horizontalLayout")
self.pushButton = QtWidgets.QPushButton(Form)
self.pushButton.setObjectName("pushButton")
self.horizontalLayout.addWidget(self.pushButton)
self.horizontalLayout_2.addLayout(self.horizontalLayout)
self.retranslateUi(Form)
QtCore.QMetaObject.connectSlotsByName(Form)
self.pushButton.clicked.connect(self.openFile)
def retranslateUi(self, Form):
_translate = QtCore.QCoreApplication.translate
Form.setWindowTitle(_translate("Form", "Form"))
self.pushButton.setText(_translate("Form", "PushButton"))
# FUNCTION BELOW NOT WORKING
def openFile(self):
options = QFileDialog.Options()
options |= QFileDialog.DontUseNativeDialog
fileName, _ = QFileDialog.getOpenFileName(self,"QFileDialog.getOpenFileName()", "","All Files (*);;Python Files (*.py)", options=options)
if fileName:
print(fileName)
if __name__ == "__main__":
import sys
app = QtWidgets.QApplication(sys.argv)
Form = QtWidgets.QWidget()
ui = Ui_Form()
ui.setupUi(Form)
Form.show()
sys.exit(app.exec_())
getOpenFileName
需要一个 QWidget
类型的对象作为参数,在您的情况下 Ui_Form 不是那种类型。
- 第一个解决方案:通过
None
:
fileName, _ = QFileDialog.getOpenFileName(None,"QFileDialog.getOpenFileName()", "","All Files (*);;Python Files (*.py)", options=options)
- 第二种解决方案:创建一个实现Ui_Form签证的class,并在其中创建openFile槽。
class Widget(QtWidgets.QWidget, Ui_Form):
def __init__(self, parent=None):
QtWidgets.QWidget.__init__(self, parent)
self.setupUi(self)
self.pushButton.clicked.connect(self.openFile)
def openFile(self):
options = QFileDialog.Options()
options |= QFileDialog.DontUseNativeDialog
fileName, _ = QFileDialog.getOpenFileName(self,"QFileDialog.getOpenFileName()", "","All Files (*);;Python Files (*.py)", options=options)
if fileName:
print(fileName)
您需要传递一个 QWidget 作为父级。我修改了您的代码以保存 Form
并稍后使用它。
class Ui_Form(object):
def setupUi(self, Form):
self.Form = Form # <-----
...
def openFile(self):
fileName, _ = QFileDialog.getOpenFileName(self.Form, # <-----
...
我找到的另一个解决方案是将函数更改为:
def openFileNameDialog(self):
fname = QFileDialog.getOpenFileName()
self.ui.lineEdit.setText(fname)