如何在弹出菜单中使用单选按钮？

Question

我正在尝试创建一个包含可选单选按钮的弹出菜单，以便更改视图类型（例如图库、卡片、滑动、网格、列表等）。

我运行遇到的问题是 PopupMenu 有自己的回调来选择值，Radio 和 RadioListTile 也是如此。

忽略 RadioListTile 的 onChanged

这是我的第一次尝试。这确实有效，除了按钮永远变灰。为 RadioListTiles 提供一个非 null noop 函数会导致按钮不再变灰（禁用），但弹出菜单不再有效。

new PopupMenuButton<String>(
    ...
    itemBuilder: (ctx) => <PopupMenuEntry<String>>[
          new PopupMenuItem(
              child: new RadioListTile(
                  title: new Text("Cards"),
                  value: 'cards',
                  groupValue: _view,
                  onChanged: null),
              value: 'cards'),
          new PopupMenuItem(
              child: new RadioListTile(
                  title: new Text("Swipe"),
                  value: 'swipe',
                  groupValue: _view,
                  onChanged: null),
              value: 'swipe'),
        ],
    onSelected: (String viewType) {
      _view = viewType;
    }));

使用 RadioListTile，忽略 PopupMenu

第二次尝试是完全忽略 PopupMenu，只使用 RadioListTile onChanged。这些按钮不是 grayed-out/disabled，但也不起作用。

new PopupMenuButton<String>(
  ...
  itemBuilder: (ctx) => <PopupMenuEntry<Null>>[
        new PopupMenuItem(
            child: new RadioListTile(
                title: new Text("Cards"),
                value: 'cards',
                groupValue: _view,
                onChanged: (v) => setState(() => _view = v)),
            value: 'cards'),
        new PopupMenuItem(
            child: new RadioListTile(
                title: new Text("Swipe"),
                value: 'swipe',
                groupValue: _view,
                onChanged: (v) => setState(() => _view = v)),
            value: 'swipe'),
      ],
));

正确的做法是什么？ PopupMenu 适用于极其简单的菜单，但元素选择给我带来了冲突。有没有办法获得 "dumb" 弹出菜单，在按钮处显示一列小部件（样式像菜单）？

Answer 1

我认为最适合您的解决方案是使用 CheckedPopupMenuItems 而不是广播列表。该功能应该正是您想要实现的，不是吗？

这是一个小例子：

import 'package:flutter/widgets.dart';
import 'package:flutter/material.dart';

void main() {
  runApp(new MyApp());
}

class MyApp extends StatelessWidget {
  @override
  Widget build(BuildContext context) {
    return new MaterialApp(
      title: 'Flutter Demo',
      home: new MyHomePage(),
    );
  }
}

class MyHomePage extends StatefulWidget {
  @override
  _MyHomePageState createState() => new _MyHomePageState();
}

class _MyHomePageState extends State<MyHomePage> {
  String _selectedView = 'Card';

  @override
  Widget build(BuildContext context) {
    return new Scaffold(
      appBar: new AppBar(
        title: new Text('TestProject'),
        actions: <Widget>[
          new PopupMenuButton(
            onSelected: (value) => setState(() => _selectedView = value),
            itemBuilder: (_) => [
                  new CheckedPopupMenuItem(
                    checked: _selectedView == 'Card',
                    value: 'Card',
                    child: new Text('Card'),
                  ),
                  new CheckedPopupMenuItem(
                    checked: _selectedView == 'Swipe',
                    value: 'Swipe',
                    child: new Text('Swipe'),
                  ),
                  new CheckedPopupMenuItem(
                    checked: _selectedView == 'List',
                    value: 'List',
                    child: new Text('List'),
                  ),
                ],
          ),
        ],
      ),
      body: new Center(child: new Text(_selectedView)),
    );
  }
}

Answer 2

问题是 PopupMenuButton is maintaining the popup dialog as private state (it even pushes a new route onto the Navigator stack). Calling setState won't rebuild the items. You can use an AnimatedBuilder and a ValueNotifier 解决这个问题。

这是弹出窗口中有效单选按钮列表的示例：

import 'package:flutter/foundation.dart';
import 'package:flutter/material.dart';

void main() {
  runApp(new MyApp());
}

class MyApp extends StatelessWidget {
  @override
  Widget build(BuildContext context) {
    return new MaterialApp(
      title: 'Flutter Demo',
      home: new MyHomePage(),
    );
  }
}

class MyHomePage extends StatefulWidget {
  State createState() => new MyHomePageState();
}

enum Fruit {
  apple,
  banana,
}

class MyHomePageState extends State<MyHomePage> {
  ValueNotifier<Fruit> _selectedItem = new ValueNotifier<Fruit>(Fruit.apple);

  @override
  Widget build(BuildContext context) {
    return new Scaffold(
      body: new Center(
        child: new PopupMenuButton<Fruit>(
          itemBuilder: (BuildContext context) {
            return new List<PopupMenuEntry<Fruit>>.generate(
              Fruit.values.length,
              (int index) {
                return new PopupMenuItem(
                  value: Fruit.values[index],
                  child: new AnimatedBuilder(
                    child: new Text(Fruit.values[index].toString()),
                    animation: _selectedItem,
                    builder: (BuildContext context, Widget child) {
                      return new RadioListTile<Fruit>(
                        value: Fruit.values[index],
                        groupValue: _selectedItem.value,
                        title: child,
                        onChanged: (Fruit value) {
                          _selectedItem.value = value;
                        },
                      );
                    },
                  ),
                );
              },
            );
          },
        ),
      ),
    );
  }
}

如何在弹出菜单中使用单选按钮？

How do I use radio buttons inside popup menus?

dart

flutter

忽略 RadioListTile 的 onChanged

使用 RadioListTile，忽略 PopupMenu