单击按钮时转到下一步 activity，释放按钮时转到 Return

Question

我有一个 OnTouch 按钮，当单击该按钮时使用运动事件转到下一个 activity，但我希望它仅在按下按钮时停留在下一个 activity单击然后 return...如果它看起来很复杂，这里是代码-:

   @Override
        public boolean onTouch(View v, MotionEvent event) {
            while (event.getAction() == MotionEvent.ACTION_DOWN){
                Intent myIntent = new Intent(MainActivity.this, ActionActivity.class);
                myIntent.putExtra("key", value); //Optional parameters
                MainActivity.this.startActivity(myIntent);
            }
            if(event.getAction() == MotionEvent.ACTION_UP){


            }
            return true;
        }

    });

Answer 1

在下一个 activity 的根视图上使用相同的 onTouch 并完成活动 ACTION_UP

 @Override
    public boolean onTouch(View v, MotionEvent event) {
        if(event.getAction() == MotionEvent.ACTION_UP){
           finish();
        }
        return true;
    }

});

（更新）测试答案：

第一个Activity:

public class MainActivity extends AppCompatActivity implements View.OnTouchListener {

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    final ViewGroup viewGroup = (ViewGroup) ((ViewGroup) this
            .findViewById(android.R.id.content)).getChildAt(0);

    viewGroup.setOnTouchListener(this);
}


@Override
public boolean onTouch(View view, MotionEvent motionEvent) {
    if (motionEvent.getAction() == MotionEvent.ACTION_DOWN) {
        Intent myIntent = new Intent(MainActivity.this, SecondActivity.class);
        MainActivity.this.startActivity(myIntent);
        return true;
    } else if (motionEvent.getAction() == MotionEvent.ACTION_UP) {
        SecondActivity.activity.get().finish();
        return true;
    }
    return true;
}

}

第二个Activity：

public class SecondActivity extends AppCompatActivity {

public static WeakReference<Activity> activity;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_second);

    activity = new WeakReference<Activity>(this);
}

}

不要在 onTouch
使用静态 Activity 对象从第一个 activity 完成第二个 activity，

这是有效的

单击按钮时转到下一步 activity，释放按钮时转到 Return

Go to Next activity while the Button is clicked & Return when Released

android

android-activity

ontouch