多个对象中的 Tweenlite

Question

我尝试将卡片移动给我的用户他们是这里的三个成员我这里有九张卡我的代码 below.I 已经使用 tweenlite 移动前三张卡成功移动然后其余的卡我如何移动到用户.

import com.greensock.*;
import com.greensock.easing.*;
import flash.events.MouseEvent;

 click_mc.addEventListener(MouseEvent.CLICK, UserOne);



function UserOne(evt:MouseEvent):void
{

    TweenMax.to(joker_mc, .5, { x:598.25, y:164.45 , onComplete:UserTwo} );     
}

function UserTwo():void
{
    TweenLite.to(king_mc, .5, { x:316.50, y:267.90, onComplete:UserThree} );

}

function UserThree():void
{
    TweenLite.to(queen_mc, .5, { x:39, y:172} );

}

谁知道请详细说明一下。

Answer 1

无需为每张卡片创建单独的代码，它们都很相似。使用 card + x + y 条目创建一个数组，并使用这些条目。

import com.greensock.*;
import com.greensock.easing.*;
import flash.events.MouseEvent;

var currentEntry:int = -1;
var aList:Array =
[
    {card:joker_mc, x:598.25, y:164.45},
    {card:king_mc,  x:316.50, y:267.90},
    {card:queen_mc, x:39, y:172},

    // ...
    // and so on
];

click_mc.addEventListener(MouseEvent.CLICK, onClick);

function onClick(e:MouseEvent):void
{
    // Unsubscribe to avoid the mess with second click.
    click_mc.removeEventListener(MouseEvent.CLICK, onClick);

    // Start process.
    moveNext();
}

function moveNext():void
{
    currentEntry++;

    // Stop the process if all the cards have been moved.
    if (currentEntry >= aList.length) return;

    // Get the entry.
    var anEntry:Object = aList[currentEntry];

    // Move the card.
    TweenLite.to(anEntry['card'], .5, {x:anEntry['x'], y:anEntry['y'], onComplete:moveNext});
}

多个对象中的 Tweenlite

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actionscript-3