如何打印带有索引号（python）的列表？

Question

好的，我走了！顺便说一句，我是个菜鸟，我正在尽我最大的努力学习。我不得不写一些代码来打开一个 csv 文件并将列表格式化为可以与 Libsvm 一起使用的方式，但无论如何这是我到目前为止写的代码：

import csv
with open ('testingSeta.csv')as csvfile:
reader = csv.reader(csvfile, delimiter = ',')
for i in reader:
    i.insert (0, i.pop(13))
    print (" ".join(i))

这给了我一个这样的列表：

-1 0 1 1 0 1 1 1 4 5 6 5 5 8
-1 0 1 0 0 1 1 1 4 3 7 1 3 6
 1 3 7 2 0 4 4 1 41 46 86 20 18 48
 1 10 11 0 0 6 6 3 26 65 102 25 16 38

testingSeta.csv原格式：

0,1,1,0,1,1,1,4,5,6,5,5,8,-1
0,1,0,0,1,1,1,4,3,7,1,3,6,-1
3,7,2,0,4,4,1,41,46,86,20,18,48,1
10,11,0,0,6,6,3,26,65,102,25,16,38,1

我希望列表是这样排序的：

-1 1:0 2:1 3:1 4:0 5:1 6:1 7:1 8:4 9:5 10:6 11:5 12:5 13:8
-1 1:0 2:1 3:0 4:0 5:1 6:1 7:1 8:4 9:3 10:7 11:1 12:3 13:6
1 1:3 2:7 3:2 4:0 5:4 6:4 7:1 8:41 9:46 10:86 11:20 12:18 13:48
1 1:10 2:11 3:0 4:0 5:6 6:6 7:3 8:26 9:65 10:102 11:25 12:16 13:38

编号“1:”应始终从第二个 number/value 开始。任何人都可以帮忙吗？谢谢你的时间

Answer 1

这样试试：

>>> with open('your_file') as f:
...     for x in f:
...         line = x.strip().split(',')
...         print "{} ".format(line[-1]) + " ".join("{}:{}".format(i,y) for i,y in enumerate(line[:-1],start=1))
... 
-1 1:0 2:1 3:1 4:0 5:1 6:1 7:1 8:4 9:5 10:6 11:5 12:5 13:8
-1 1:0 2:1 3:0 4:0 5:1 6:1 7:1 8:4 9:3 10:7 11:1 12:3 13:6
1 1:3 2:7 3:2 4:0 5:4 6:4 7:1 8:41 9:46 10:86 11:20 12:18 13:48
1 1:10 2:11 3:0 4:0 5:6 6:6 7:3 8:26 9:65 10:102 11:25 12:16 13:38

Answer 2

>>> with open ('testingSeta.csv') as csvfile:
...     reader = csv.reader(csvfile, delimiter = ',')
...     for i in reader:
...         last = i.pop(13)
...         for index,string in enumerate( i ) :
...             i[ index ] = str(index+1) + ":" + string
...         print last + " " + " ".join(i)
... 
-1 1:0 2:1 3:1 4:0 5:1 6:1 7:1 8:4 9:5 10:6 11:5 12:5 13:8
-1 1:0 2:1 3:0 4:0 5:1 6:1 7:1 8:4 9:3 10:7 11:1 12:3 13:6
1 1:3 2:7 3:2 4:0 5:4 6:4 7:1 8:41 9:46 10:86 11:20 12:18 13:48
1 1:10 2:11 3:0 4:0 5:6 6:6 7:3 8:26 9:65 10:102 11:25 12:16 13:38

Answer 3

with open('testingSeta.csv') as f:
   for line in csv.reader(f):
      print(' '.join(
                [line[-1]] + 
                ['{0}:{1}'.format(*x) for x in enumerate(line[:-1], start=1)]))


-1 1:0 2:1 3:1 4:0 5:1 6:1 7:1 8:4 9:5 10:6 11:5 12:5 13:8
-1 1:0 2:1 3:0 4:0 5:1 6:1 7:1 8:4 9:3 10:7 11:1 12:3 13:6
1 1:3 2:7 3:2 4:0 5:4 6:4 7:1 8:41 9:46 10:86 11:20 12:18 13:48
1 1:10 2:11 3:0 4:0 5:6 6:6 7:3 8:26 9:65 10:102 11:25 12:16 13:38

如何打印带有索引号（python）的列表？

How to print a list with the index numbers (python)?

python

csv

printing

indexing

list