在 Php 中使用 Mysql 错误 500

Question

有人可以向我解释一下我的代码有什么问题吗？当我尝试访问该页面时，它只是给我一个 HTTP 错误 500。这是代码。

<?php
$conn = new mysqli("localhost","user","pass","db");
if(!empty($_GET['Info']))
{
    $Info = $_GET['Info'];
    $sql = "SELECT * FROM `Judges` WHERE `id` EQUALS $Info";
    $result = $conn->query($sql);

    if ($result->num_rows > 0) 
    {
        while($rows = $result->fetch_assoc()) 
        {
            $PictureFile = Null
            if(empty($rows["PictureFile"]))
            {
                $PictureFile = "MissingPicture.png";
            }
            else
            {
                $PictureFile = $rows["PictureFile"];
            }
            echo '<div><img src="' . $PictureFile . '" style="width=100px;height=100px;"> <p>This Is Just A Test Message!</p></div>';
        }
    } 
    else 
    {
        echo "<p style='text-align: center;'>Your Search Came Back With 0 Results :(</p>";
    }
}
$conn->close();
?>

Answer 1

在$PictureFile = Null

末尾添加;

Answer 2

你忘了一个;在这个命令行之后

$PictureFile = Null

我无法测试脚本，但它一定能解决您的问题。

Answer 3

将 EQUALS 更改为 = 并添加 ;在 $PictureFile = Null

之后

    <?php
$conn = new mysqli("localhost","user","pass","db");
if(!empty($_GET['Info']))
{
    $Info = $_GET['Info'];
    $sql = "SELECT * FROM `Judges` WHERE `id`= $Info";
    $result = $conn->query($sql);

    if ($result->num_rows > 0) 
    {
        while($rows = $result->fetch_assoc()) 
        {
            $PictureFile = Null;
            if(empty($rows["PictureFile"]))
            {
                $PictureFile = "MissingPicture.png";
            }
            else
            {
                $PictureFile = $rows["PictureFile"];
            }
            echo '<div><img src="' . $PictureFile . '" style="width=100px;height=100px;"> <p>This Is Just A Test Message!</p></div>';
        }
    } 
    else 
    {
        echo "<p style='text-align: center;'>Your Search Came Back With 0 Results :(</p>";
    }
}
$conn->close();
?>

在 Php 中使用 Mysql 错误 500

Error 500 Using Mysql In Php

php

mysql

http-error