如何从 Django Channels 获取查询参数？

Question

我需要从 Django Channels 访问查询参数字典。

url 可能如下所示：ws://127.0.0.1:8000/?hello="world"

如何像这样检索 'world'：query_params["hello"]？

Answer 1

在 websocket 连接上 message.content 字典包含 query_string.

import urlparse
def ws_connect(message):
    params = urlparse.parse_qs(message.content['query_string'])
    hello = params.get('hello', (None,))[0]

入门文档 (http://channels.readthedocs.io/en/stable/getting-started.html) 暗示 query_string 包含在 message.content 路径中，但事实并非如此。

下面是聊天应用程序示例的工作 consumer.py，其中房间在查询字符串中传递：

import urlparse
from channels import Group
from channels.sessions import channel_session

@channel_session
def ws_message(message):
    room = message.channel_session['room']
    Group("chat-{0}".format(room)).send({"text": "[{1}] {0}".format(message.content['text'], room)})

@channel_session
def ws_connect(message):
    message.reply_channel.send({"accept": True})
    params = urlparse.parse_qs(message.content['query_string'])
    room = params.get('room',('Not Supplied',))[0]
    message.channel_session['room'] = room
    Group("chat-{0}".format(room)).add(message.reply_channel)

@channel_session
def ws_disconnect(message):
    room = message.channel_session['room']
    Group("chat-{0}".format(room)).discard(message.reply_channel)

Answer 2

频道 3 更新：

from urllib.parse import parse_qs

# Types
class Scope(TypedDict):   
    query_string: bytes

scope: Scope
query_params: Dict[str, List[str]]

# Parse query_string
query_params = parse_qs(scope["query_string"].decode())

print(query_params["access_token"][-1])

如果您经常这样做，您可以将它放在一个中间件中并将您的 ASGI 应用程序包装在其中。类似于：

class QueryParamsMiddleware(BaseMiddleware):
    async def __call__(self, scope, receive, send):
        scope = dict(scope)

        scope["query_params"] = parse_qs(scope["query_string"].decode())

        return await super().__call__(scope, receive, send)

如何从 Django Channels 获取查询参数？

How to get query parameters from Django Channels?

python

django

websocket

django-channels