Postgres:为什么 Offset/Limit 的子选择性能如此糟糕
Postgres: Why is the performance so bad on subselects with Offset/Limit
你能帮我理解这些语句之间性能下降的原因吗?
对我来说,在 D & E 的情况下,他首先将地址加入所有订阅者,最后应用 Offset & Limit。他到底为什么要这么做?
我是否遗漏了有关 Subselects 和 Offset 如何协同工作的信息?他不应该先找到正确的偏移量然后开始执行subselects吗?
user_id 和 address_id 是主键
Select A:15 毫秒(确定):select 前 200 个订阅者
SELECT s.user_id
FROM subscribers s
ORDER BY s.user_id
OFFSET 0 LIMIT 200
Select B:45 毫秒(正常):Select 最后 200 个订阅者
SELECT s.user_id
FROM subscribers s
ORDER BY s.user_id
OFFSET 100000 LIMIT 200
Select C:15 毫秒(确定):Select 前 200 个订阅者以及第一个可用地址
SELECT s.user_id,
(SELECT address_id FROM address a WHERE a.user_id = s.user_id ORDER BY address_id OFFSET 0 LIMIT 1) AS a_id
FROM subscribers s
ORDER BY s.user_id
OFFSET 0 LIMIT 200
Select D:500 毫秒(不正常):Select 最后 200 个订阅者以及第一个可用地址
SELECT s.user_id,
(SELECT address_id FROM address a WHERE a.user_id = s.user_id ORDER BY address_id OFFSET 0 LIMIT 1) AS a_id
FROM subscribers s
ORDER BY s.user_id
OFFSET 100000 LIMIT 200
Select E:1000 毫秒(更糟):Select 最后 200 个订阅者以及前 2 个可用地址
SELECT s.user_id,
(SELECT address_id FROM address a WHERE a.user_id = s.user_id ORDER BY address_id OFFSET 0 LIMIT 1) AS a_id_1,
(SELECT address_id FROM address a WHERE a.user_id = s.user_id ORDER BY address_id OFFSET 1 LIMIT 2) AS a_id_2
FROM subscribers s
ORDER BY s.user_id
OFFSET 100000 LIMIT 200
Select F: 15 ms (Nice): Select 最后 200 个订阅者和前 2 个可用地址没有偏移但 WHERE s.user_id > 100385
SELECT s.user_id,
(SELECT address_id FROM address a WHERE a.user_id = s.user_id ORDER BY address_id OFFSET 0 LIMIT 1) AS a_id_1,
(SELECT address_id FROM address a WHERE a.user_id = s.user_id ORDER BY address_id OFFSET 1 LIMIT 2) AS a_id_2
FROM subscribers s
WHERE s.user_id > 100385 --same as OFFSET 100000 in my data
ORDER BY s.user_id
LIMIT 200
E 的执行计划:
'Limit (cost=1677635.30..1677635.80 rows=200 width=4) (actual time=2251.503..2251.816 rows=200 loops=1)'
' Output: s.user_id, ((SubPlan 1)), ((SubPlan 2))'
' Buffers: shared hit=607074'
' -> Sort (cost=1677385.30..1677636.08 rows=100312 width=4) (actual time=2146.867..2200.704 rows=100200 loops=1)'
' Output: s.user_id, ((SubPlan 1)), ((SubPlan 2))'
' Sort Key: s.user_id'
' Sort Method: quicksort Memory: 7775kB'
' Buffers: shared hit=607074'
' -> Seq Scan on public.pcv_subscriber s (cost=0.00..1669052.31 rows=100312 width=4) (actual time=0.040..2046.926 rows=100312 loops=1)'
' Output: s.user_id, (SubPlan 1), (SubPlan 2)'
' Buffers: shared hit=607074'
' SubPlan 1'
' -> Limit (cost=8.29..8.29 rows=1 width=4) (actual time=0.008..0.008 rows=1 loops=100312)'
' Output: ua.user_address_id'
' Buffers: shared hit=301458'
' -> Sort (cost=8.29..8.29 rows=1 width=4) (actual time=0.007..0.007 rows=1 loops=100312)'
' Output: ua.user_address_id'
' Sort Key: ua.user_address_id'
' Sort Method: quicksort Memory: 25kB'
' Buffers: shared hit=301458'
' -> Index Scan using ix_pcv_user_address_user_id on public.pcv_user_address ua (cost=0.00..8.28 rows=1 width=4) (actual time=0.003..0.004 rows=1 loops=100312)'
' Output: ua.user_address_id'
' Index Cond: (ua.user_id = [=17=])'
' Buffers: shared hit=301458'
' SubPlan 2'
' -> Limit (cost=8.29..8.29 rows=1 width=4) (actual time=0.009..0.009 rows=0 loops=100312)'
' Output: ua.user_address_id'
' Buffers: shared hit=301458'
' -> Sort (cost=8.29..8.29 rows=1 width=4) (actual time=0.006..0.007 rows=1 loops=100312)'
' Output: ua.user_address_id'
' Sort Key: ua.user_address_id'
' Sort Method: quicksort Memory: 25kB'
' Buffers: shared hit=301458'
' -> Index Scan using ix_pcv_user_address_user_id on public.pcv_user_address ua (cost=0.00..8.28 rows=1 width=4) (actual time=0.003..0.003 rows=1 loops=100312)'
' Output: ua.user_address_id'
' Index Cond: (ua.user_id = [=17=])'
' Buffers: shared hit=301458'
'Total runtime: 2251.968 ms'
免责声明:
这是一个更大、更复杂的语句的精简示例,它使 GUI Table 到 sort/page/filter 订阅者在多个表中具有大量额外的累积数据。所以我知道这个例子可以用更好的方式来完成。因此,请帮助我理解为什么此解决方案如此缓慢或最多建议进行最小的更改。
更新 1:
这是使用 Postgres 9.0.3 制作的
更新二:
目前我能想到的最好的解决方案似乎是这个愚蠢的说法:
Select G: 73ms (OKish)
SELECT s.user_id,
(SELECT address_id FROM address a WHERE a.user_id = s.user_id ORDER BY address_id OFFSET 0 LIMIT 1) AS a_id_1,
(SELECT address_id FROM address a WHERE a.user_id = s.user_id ORDER BY address_id OFFSET 1 LIMIT 2) AS a_id_2
FROM subscribers s
WHERE s.user_id >= (SELECT user_id from subscribers ORDER BY user_id OFFSET 100000 LIMIT 1)
ORDER BY s.user_id
LIMIT 200
更新 3:
迄今为止最好的 select 大卫。 (与 G 性能相同但更直观)
Select H: 73ms (OKish)
SELECT s2.user_id,
(SELECT address_id FROM address a WHERE a.user_id = s2.user_id ORDER BY address_id OFFSET 0 LIMIT 1) AS a_id
FROM (SELECT s.user_id
FROM subscribers s
ORDER BY s.user_id
OFFSET 100000 LIMIT 200) s2
H 的执行计划:
这就是我最初对 E 的想象。
我认为 SELECT 子句中表达的连接正在执行,即使对于您未包含在最终数据集中的 100000 行也是如此。
这个怎么样:
SELECT s2.user_id,
(SELECT address_id FROM address a WHERE a.user_id = s2.user_id ORDER BY address_id OFFSET 0 LIMIT 1) AS a_id
FROM (select *
from subscribers s
ORDER BY s.user_id
OFFSET 100000 LIMIT 200) s2
如果不行,请尝试一个常见的 table 表达式:
With s2 as (
select *
from subscribers s
ORDER BY s.user_id
OFFSET 100000 LIMIT 200)
SELECT s2.user_id,
(SELECT address_id FROM address a WHERE a.user_id = s2.user_id ORDER BY address_id OFFSET 0 LIMIT 1) AS a_id
FROM s2
对于 ranks={1,2} 的情况,这似乎是合理的。 (CTE 很糟糕,仅供参考)
-- EXPLAIN ANALYZE
SELECT s.user_id
, MAX (CASE WHEN a0.rn = 1 THEN a0.address_id ELSE NULL END) AS ad1
, MAX (CASE WHEN a0.rn = 2 THEN a0.address_id ELSE NULL END) AS ad2
FROM subscribers s
JOIN ( SELECT user_id, address_id
, row_number() OVER(PARTITION BY user_id ORDER BY address_id) AS rn
FROM address
)a0 ON a0.user_id = s.user_id AND a0.rn <= 2
GROUP BY s.user_id
ORDER BY s.user_id
OFFSET 10000 LIMIT 200
;
更新:下面的查询似乎执行得稍微好一些:
-- ----------------------------------
-- EXPLAIN ANALYZE
SELECT s.user_id
, MAX (CASE WHEN a0.rn = 1 THEN a0.address_id ELSE NULL END) AS ad1
, MAX (CASE WHEN a0.rn = 2 THEN a0.address_id ELSE NULL END) AS ad2
FROM ( SELECT user_id
FROM subscribers
ORDER BY user_id
OFFSET 10000
LIMIT 200
) s
JOIN ( SELECT user_id, address_id
, row_number() OVER(PARTITION BY user_id ORDER BY address_id) AS rn
FROM address
) a0 ON a0.user_id = s.user_id AND a0.rn <= 2
GROUP BY s.user_id
ORDER BY s.user_id
;
注意:在两个 JOINS 中可能应该 LEFT JOIN
s,以允许缺少第一个和第二个地址。
更新:将子查询(如@David Aldridfge 的回答)与原始查询(两个标量子查询)相结合
自连接订阅者 table 允许索引用于标量子查询,而无需丢弃前 100K 个结果行。
-- EXPLAIN ANALYZE
SELECT s.user_id
, (SELECT address_id
FROM address a
WHERE a.user_id = s.user_id
ORDER BY address_id OFFSET 0 LIMIT 1
) AS a_id1
, (SELECT address_id
FROM address a
WHERE a.user_id = s.user_id
ORDER BY address_id OFFSET 1 LIMIT 1
) AS a_id2
FROM subscribers s
JOIN (
SELECT user_id
FROM subscribers
ORDER BY user_id
OFFSET 10000 LIMIT 200
) x ON x.user_id = s.user_id
ORDER BY s.user_id
;
你能帮我理解这些语句之间性能下降的原因吗?
对我来说,在 D & E 的情况下,他首先将地址加入所有订阅者,最后应用 Offset & Limit。他到底为什么要这么做?
我是否遗漏了有关 Subselects 和 Offset 如何协同工作的信息?他不应该先找到正确的偏移量然后开始执行subselects吗?
user_id 和 address_id 是主键
Select A:15 毫秒(确定):select 前 200 个订阅者
SELECT s.user_id
FROM subscribers s
ORDER BY s.user_id
OFFSET 0 LIMIT 200
Select B:45 毫秒(正常):Select 最后 200 个订阅者
SELECT s.user_id
FROM subscribers s
ORDER BY s.user_id
OFFSET 100000 LIMIT 200
Select C:15 毫秒(确定):Select 前 200 个订阅者以及第一个可用地址
SELECT s.user_id,
(SELECT address_id FROM address a WHERE a.user_id = s.user_id ORDER BY address_id OFFSET 0 LIMIT 1) AS a_id
FROM subscribers s
ORDER BY s.user_id
OFFSET 0 LIMIT 200
Select D:500 毫秒(不正常):Select 最后 200 个订阅者以及第一个可用地址
SELECT s.user_id,
(SELECT address_id FROM address a WHERE a.user_id = s.user_id ORDER BY address_id OFFSET 0 LIMIT 1) AS a_id
FROM subscribers s
ORDER BY s.user_id
OFFSET 100000 LIMIT 200
Select E:1000 毫秒(更糟):Select 最后 200 个订阅者以及前 2 个可用地址
SELECT s.user_id,
(SELECT address_id FROM address a WHERE a.user_id = s.user_id ORDER BY address_id OFFSET 0 LIMIT 1) AS a_id_1,
(SELECT address_id FROM address a WHERE a.user_id = s.user_id ORDER BY address_id OFFSET 1 LIMIT 2) AS a_id_2
FROM subscribers s
ORDER BY s.user_id
OFFSET 100000 LIMIT 200
Select F: 15 ms (Nice): Select 最后 200 个订阅者和前 2 个可用地址没有偏移但 WHERE s.user_id > 100385
SELECT s.user_id,
(SELECT address_id FROM address a WHERE a.user_id = s.user_id ORDER BY address_id OFFSET 0 LIMIT 1) AS a_id_1,
(SELECT address_id FROM address a WHERE a.user_id = s.user_id ORDER BY address_id OFFSET 1 LIMIT 2) AS a_id_2
FROM subscribers s
WHERE s.user_id > 100385 --same as OFFSET 100000 in my data
ORDER BY s.user_id
LIMIT 200
E 的执行计划:
'Limit (cost=1677635.30..1677635.80 rows=200 width=4) (actual time=2251.503..2251.816 rows=200 loops=1)'
' Output: s.user_id, ((SubPlan 1)), ((SubPlan 2))'
' Buffers: shared hit=607074'
' -> Sort (cost=1677385.30..1677636.08 rows=100312 width=4) (actual time=2146.867..2200.704 rows=100200 loops=1)'
' Output: s.user_id, ((SubPlan 1)), ((SubPlan 2))'
' Sort Key: s.user_id'
' Sort Method: quicksort Memory: 7775kB'
' Buffers: shared hit=607074'
' -> Seq Scan on public.pcv_subscriber s (cost=0.00..1669052.31 rows=100312 width=4) (actual time=0.040..2046.926 rows=100312 loops=1)'
' Output: s.user_id, (SubPlan 1), (SubPlan 2)'
' Buffers: shared hit=607074'
' SubPlan 1'
' -> Limit (cost=8.29..8.29 rows=1 width=4) (actual time=0.008..0.008 rows=1 loops=100312)'
' Output: ua.user_address_id'
' Buffers: shared hit=301458'
' -> Sort (cost=8.29..8.29 rows=1 width=4) (actual time=0.007..0.007 rows=1 loops=100312)'
' Output: ua.user_address_id'
' Sort Key: ua.user_address_id'
' Sort Method: quicksort Memory: 25kB'
' Buffers: shared hit=301458'
' -> Index Scan using ix_pcv_user_address_user_id on public.pcv_user_address ua (cost=0.00..8.28 rows=1 width=4) (actual time=0.003..0.004 rows=1 loops=100312)'
' Output: ua.user_address_id'
' Index Cond: (ua.user_id = [=17=])'
' Buffers: shared hit=301458'
' SubPlan 2'
' -> Limit (cost=8.29..8.29 rows=1 width=4) (actual time=0.009..0.009 rows=0 loops=100312)'
' Output: ua.user_address_id'
' Buffers: shared hit=301458'
' -> Sort (cost=8.29..8.29 rows=1 width=4) (actual time=0.006..0.007 rows=1 loops=100312)'
' Output: ua.user_address_id'
' Sort Key: ua.user_address_id'
' Sort Method: quicksort Memory: 25kB'
' Buffers: shared hit=301458'
' -> Index Scan using ix_pcv_user_address_user_id on public.pcv_user_address ua (cost=0.00..8.28 rows=1 width=4) (actual time=0.003..0.003 rows=1 loops=100312)'
' Output: ua.user_address_id'
' Index Cond: (ua.user_id = [=17=])'
' Buffers: shared hit=301458'
'Total runtime: 2251.968 ms'
免责声明: 这是一个更大、更复杂的语句的精简示例,它使 GUI Table 到 sort/page/filter 订阅者在多个表中具有大量额外的累积数据。所以我知道这个例子可以用更好的方式来完成。因此,请帮助我理解为什么此解决方案如此缓慢或最多建议进行最小的更改。
更新 1:
这是使用 Postgres 9.0.3 制作的
更新二:
目前我能想到的最好的解决方案似乎是这个愚蠢的说法:
Select G: 73ms (OKish)
SELECT s.user_id,
(SELECT address_id FROM address a WHERE a.user_id = s.user_id ORDER BY address_id OFFSET 0 LIMIT 1) AS a_id_1,
(SELECT address_id FROM address a WHERE a.user_id = s.user_id ORDER BY address_id OFFSET 1 LIMIT 2) AS a_id_2
FROM subscribers s
WHERE s.user_id >= (SELECT user_id from subscribers ORDER BY user_id OFFSET 100000 LIMIT 1)
ORDER BY s.user_id
LIMIT 200
更新 3:
迄今为止最好的 select 大卫。 (与 G 性能相同但更直观)
Select H: 73ms (OKish)
SELECT s2.user_id,
(SELECT address_id FROM address a WHERE a.user_id = s2.user_id ORDER BY address_id OFFSET 0 LIMIT 1) AS a_id
FROM (SELECT s.user_id
FROM subscribers s
ORDER BY s.user_id
OFFSET 100000 LIMIT 200) s2
H 的执行计划:
这就是我最初对 E 的想象。
我认为 SELECT 子句中表达的连接正在执行,即使对于您未包含在最终数据集中的 100000 行也是如此。
这个怎么样:
SELECT s2.user_id,
(SELECT address_id FROM address a WHERE a.user_id = s2.user_id ORDER BY address_id OFFSET 0 LIMIT 1) AS a_id
FROM (select *
from subscribers s
ORDER BY s.user_id
OFFSET 100000 LIMIT 200) s2
如果不行,请尝试一个常见的 table 表达式:
With s2 as (
select *
from subscribers s
ORDER BY s.user_id
OFFSET 100000 LIMIT 200)
SELECT s2.user_id,
(SELECT address_id FROM address a WHERE a.user_id = s2.user_id ORDER BY address_id OFFSET 0 LIMIT 1) AS a_id
FROM s2
对于 ranks={1,2} 的情况,这似乎是合理的。 (CTE 很糟糕,仅供参考)
-- EXPLAIN ANALYZE
SELECT s.user_id
, MAX (CASE WHEN a0.rn = 1 THEN a0.address_id ELSE NULL END) AS ad1
, MAX (CASE WHEN a0.rn = 2 THEN a0.address_id ELSE NULL END) AS ad2
FROM subscribers s
JOIN ( SELECT user_id, address_id
, row_number() OVER(PARTITION BY user_id ORDER BY address_id) AS rn
FROM address
)a0 ON a0.user_id = s.user_id AND a0.rn <= 2
GROUP BY s.user_id
ORDER BY s.user_id
OFFSET 10000 LIMIT 200
;
更新:下面的查询似乎执行得稍微好一些:
-- ----------------------------------
-- EXPLAIN ANALYZE
SELECT s.user_id
, MAX (CASE WHEN a0.rn = 1 THEN a0.address_id ELSE NULL END) AS ad1
, MAX (CASE WHEN a0.rn = 2 THEN a0.address_id ELSE NULL END) AS ad2
FROM ( SELECT user_id
FROM subscribers
ORDER BY user_id
OFFSET 10000
LIMIT 200
) s
JOIN ( SELECT user_id, address_id
, row_number() OVER(PARTITION BY user_id ORDER BY address_id) AS rn
FROM address
) a0 ON a0.user_id = s.user_id AND a0.rn <= 2
GROUP BY s.user_id
ORDER BY s.user_id
;
注意:在两个 JOINS 中可能应该 LEFT JOIN
s,以允许缺少第一个和第二个地址。
更新:将子查询(如@David Aldridfge 的回答)与原始查询(两个标量子查询)相结合
自连接订阅者 table 允许索引用于标量子查询,而无需丢弃前 100K 个结果行。
-- EXPLAIN ANALYZE
SELECT s.user_id
, (SELECT address_id
FROM address a
WHERE a.user_id = s.user_id
ORDER BY address_id OFFSET 0 LIMIT 1
) AS a_id1
, (SELECT address_id
FROM address a
WHERE a.user_id = s.user_id
ORDER BY address_id OFFSET 1 LIMIT 1
) AS a_id2
FROM subscribers s
JOIN (
SELECT user_id
FROM subscribers
ORDER BY user_id
OFFSET 10000 LIMIT 200
) x ON x.user_id = s.user_id
ORDER BY s.user_id
;