google mock - EXPECT_CALL 即使函数有不同的参数也会触发

Question

我有 EXPECT_CALL(MockObj, func("abc")).Times(1) 并且 MockObj 是 NiceMock

在我测试的函数中，除了MockObj.func("abc")之外，还有一个调用MockObj.func("def")。

我希望合理的做法是 Google 模拟说

oh look we call func("def") but the arguments do not match the EXPECT_CALL; nothing to see here

而是 "complains":

unknown file: Failure

Unexpected mock function call - taking default action specified at:

C:/work/unit_test.cpp:36:

Function call: func(84bf3d9 pointing to "def") Returns: 1

Google Mock tried the following 1 expectation, but it didn't match:

unit_test.cpp:50: EXPECT_CALL(MockObj, func("abc"))...

Expected arg #0: is equal to 84c8b96 pointing to "abc"

Actual: 84bf479 pointing to "def"

Expected: to be called once

Actual: called once - saturated and active

首先注意到因为调用了MockObj.func("abc")
所以期望还是满足了
我理解 GMock 抛出错误的原因：我在 func 上声明了一个期望，因此它试图将对 func 的调用与期望相匹配，但它与参数不匹配，所以错误

很好。

但是为什么 GMock 会抛出错误？由于参数不匹配，为什么选择此行为，即

throw an error if the function matches existing EXPECT_CALL but not the arguments

Answer 1

您的问题 "But why does GMock throw an error? " 的直接答案是：因为它就是这样设计的。

AFAIU googlemock - 你的 googlemock 是这样工作的：

EXPECT_CALL(MockObj, func("abc")); - 意思是："I am interested in Obj::func in my tests"
MockObj 为 NiceMock 表示："I do not care about any other functions of Obj that are not explicit subject of EXPECT_CALL"

所以 - 如果您的测试代码调用 func("def") - 那么 google-mock 会这样做：

我们对 func 感兴趣 - 让我们检查一下
我们不希望 "def" - 所以未通过测试

可能你知道你应该这样做：

EXPECT_CALL(MockObj, func(StrNe("abc"))).Times(AnyNumber()); // meaning - do not care EXPECT_CALL(MockObj, func("abc")); // TImes(1) is default - you might skip it

google mock - EXPECT_CALL 即使函数有不同的参数也会触发

google mock - EXPECT_CALL triggers even though function has different argument

c++

unit-testing

googletest

googlemock