Kotlin、JPA 和@Transient

Question

我有一个实体 class，我已将其从 Java 迁移到 Kotlin。其中一个属性 (inetAddress) 被注释为 @Transient 以防止它被持久化到关系数据库中。但是，JPA（Hibernate 实现）看不到此注释并将其作为自己的字段放在数据库中。当 class 写在 Java.

中时，这一切都正常工作

有谁知道如何正确注释此 Kotlin class 以便 JPA/Hibernate 将看到 @Transient 注释而不是将 inetAddress 属性放在数据库？

package infr.audio.model

import com.fasterxml.jackson.annotation.JsonIgnore
import com.fasterxml.jackson.annotation.JsonProperty
import infr.audio.messages.InetAddressWrapper
import java.io.Serializable
import java.net.InetAddress
import javax.persistence.Column
import javax.persistence.Entity
import javax.persistence.GeneratedValue
import javax.persistence.Id
import javax.persistence.NamedQueries
import javax.persistence.NamedQuery
import javax.persistence.Table

@Entity
@Table(name = "DIS_JOCKEY")
@NamedQueries(NamedQuery(name = "DisJockeyInfo.find", query = "SELECT m FROM DisJockeyInfo m"), NamedQuery(name = "DisJockeyInfo.findByReservationId", query = "SELECT m FROM DisJockeyInfo m WHERE m.reservationId = :reservationId"), NamedQuery(name = "DisJockeyInfo.findByReservationIdAndName", query = "SELECT m FROM DisJockeyInfo m WHERE m.reservationId = :reservationId AND m.name = :name"), NamedQuery(name = "DisJockeyInfo.findMaxDisEntityIdByReservationId", query = "SELECT MAX(m.disEntityId) FROM DisJockeyInfo m WHERE m.reservationId = :reservationId"), NamedQuery(name = "DisJockeyInfo.findActive", query = "SELECT m FROM DisJockeyInfo m WHERE m.disEntityId IS NOT NULL"), NamedQuery(name = "DisJockeyInfo.findActiveByInetAddress", query = "SELECT m FROM DisJockeyInfo m WHERE m.inetAddress = :inetAddress AND m.disEntityId IS NOT NULL"), NamedQuery(name = "DisJockeyInfo.findActiveByReservationId", query = "SELECT m FROM DisJockeyInfo m WHERE m.reservationId = :reservationId AND m.disEntityId IS NOT NULL"), NamedQuery(name = "DisJockeyInfo.deleteInactive", query = "DELETE FROM DisJockeyInfo m WHERE m.id = :id AND m.disEntityId IS NULL"))
data class DisJockeyInfo(
        @get:Id
        @get:GeneratedValue(strategy = GenerationType.IDENTITY)
        @get:Column(name = "ID")
        var id: Long,
        @get:Column(name = "RESERVATION_ID")
        var reservationId: String?,
        @get:Column(name = "NAME")
        var name: String?,
        @get:Column(name = "DIS_ENTITY_ID")
        var disEntityId: Long?,
        @get:java.beans.Transient
        @get:JsonIgnore
        @field:Transient
        var inetAddress: InetAddress?    
) : GenericEntity, Serializable {

    var inetAddressString: String?
        @Column(name = "INET_ADDRESS")
        @JsonProperty("inetAddress")
        get() = if (inetAddress != null) InetAddressWrapper(inetAddress).encodedInetAddress else null
        set(inetAddressString) {
            inetAddress = if (inetAddressString != null) InetAddressWrapper(inetAddressString).inetAddress else null
        }

    constructor() : this(id = 0L, reservationId = null, name = null, disEntityId = null, inetAddress = null) {}

    companion object {
        /** Serial version */
        private val serialVersionUID = 2027355982760360935L
    }
}

Answer 1

您正在注释字段而不是注释 getter。请注意，您的 getter 注释使用了错误的类型 (java.beans.Transient) 而不是正确的 javax.persistence.Transient.

Answer 2

只需添加：

import javax.persistence.Transient

Answer 3

使用@Transient 和导入kotlin.jvm.Transient 帮助了我。（或者只是 @kotlin.jvm.Transient） https://kotlinlang.org/api/latest/jvm/stdlib/kotlin.jvm/-transient/

Kotlin、JPA 和@Transient

Kotlin, JPA and @Transient

hibernate

jpa-2.0

kotlin