在 PHP 中每个月的所有天数都介于两个日期之间

Question

如何在这样的数组中获取两天之间每个月的所有天数

$dateStart = "2016/12/14"; 
$dateFin =   "2017/04/21"

[2016/12/14 - 2016/12/31] => 17 days
[2017/01/01 - 2017/01/31] => 31 days
[2017/02/01 - 2017/02/28] => 28 days
[2017/03/01 - 2017/03/30] => 31 days
[2017/04/01 - 2017/04/21] => 21 days

Answer 1

要获取两个日期的日期差异（以天为单位），您可以这样做：

function daysDiff($d1, $d2) 
{
    $x1 = days($d1);
    $x2 = days($d2);

    if ($x1 && $x2) {
        return abs($x1 - $x2);
    }
}

function days(DateTime $x) 
{
    $y = $x->format('Y') - 1;
    $days = $y * 365;
    $z = (int)($y / 4);
    $days += $z;
    $z = (int)($y / 100);
    $days -= $z;
    $z = (int)($y / 400);
    $days += $z;
    $days += $x->format('z');

    return $days;
}

$d1 和 $d2 应该是 DateTime 类型，我从这里复制这段代码：http://php.net/manual/es/function.date-diff.php#117691 并做了一个小修改以使用类型提示而不是使用 get_class[ 验证变量类型=12=]

Answer 2

Powerful Function to get two date difference

查看演示 here

function dateDifference($date_1, $date_2, $differenceFormat = '%a')
{
    $datetime1 = date_create($date_1);
    $datetime2 = date_create($date_2);

    $interval = date_diff($datetime1, $datetime2);

    return $interval->format($differenceFormat);
}

Answer 3

您可以使用函数 cal_days_in_month 加上 DateTime class:

<?php
$dateStart = new DateTime("2016/12/14");
$dateFin = new DateTime("2017/04/21");
$firstDay = $dateStart->format('Y/m/d');
$lastDay = $dateStart->format('Y/m/t');
$totalMonths = $dateStart->diff($dateFin)->m + ($dateStart->diff($dateFin)->y*12);
$result = [];
for ($i = 0; $i <= $totalMonths; $i++)
{
    if ($i != 0){
        $dateStart->modify('first day of next month');
        $firstDay = $dateStart->format('Y/m/d');
        $dateStart->modify('last day of month');
        $lastDay = $dateStart->format('Y/m/t');
    }

    $nextDate = explode('/', $firstDay);

    $totalDays = cal_days_in_month(CAL_GREGORIAN, $nextDate[1], $nextDate[2]);
    if ($i == 0){
        $totalDays -= $dateStart->format('d');
    } else if ($i == $totalMonths) {
        $totalDays = $dateFin->format('d');
    }

    $result["$firstDay - $lastDay"] = $totalDays;
}

var_dump($result);

缺乏改进，但满足您的要求。

常规改进，检查如下：

$dateStart = new DateTime("2016/12/14");
$dateFin = new DateTime("2017/04/21");
$totalMonths = $dateStart->diff($dateFin)->m + ($dateStart->diff($dateFin)->y*12);
$result = [];
for ($i = 0; $i <= $totalMonths; $i++)
{
    if ($i != 0){
        $obj = $dateStart->modify('first day of next month');
    }

    $firstDay = $dateStart->format('Y/m/d');
    if ($i == $totalMonths){
        $lastDay = $dateFin->format('Y/m/d');
    } else {
        $lastDay = $dateStart->format('Y/m/t');
    }
    $firstDayObj = strtotime($firstDay);
    $lastDayObj = strtotime($lastDay);
    $totalDays = (int) ceil(($lastDayObj - $firstDayObj) / 86400);
    $totalDays = ((int) $dateStart->format('d') == 1) ? $totalDays + 1 : $totalDays;
    $result["$firstDay - $lastDay"] = $totalDays;
}

var_dump($result);

//array(5) { ["2016/12/14 - 2016/12/31"]=> int(17) ["2017/01/01 - 2017/01/31"]=> int(31) ["2017/02/01 - 2017/02/28"]=> int(28) ["2017/03/01 - 2017/03/31"]=> int(31) ["2017/04/01 - 2017/04/21"]=> int(21) }

Answer 4

请根据上述描述尝试执行以下代码片段作为解决方案

$start_date = new DateTime('2016/12/14');
$start_date=$start_date->modify('+1 day');
$end_date = new DateTime('2017/04/21');
$end_date = $end_date->modify('+1 day');

$interval = new DateInterval('P1D');
$daterange = new DatePeriod($start_date, $interval ,$end_date);
$month_days=array();
foreach($daterange as $date)
{
  $date_month=$date->format('m');
  $month_days[$date_month][]=$date->format('Y/m/d');
}
$result=array();
foreach($month_days as $days)
{
  $begin=reset($days);
  $end=end($days);
  $result[$begin.'-'.$end]=count($days);
}
echo '<pre>';
print_r($result);

在 PHP 中每个月的所有天数都介于两个日期之间

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