流程图（旅行路径）在R中使用纬度和经度
Flow map(Travel Path) Using Lat and Long in R
我正在尝试绘制流量图（新加坡）。我有入口（纬度、经度）和出口（纬度、经度）。我正在尝试在新加坡地图中绘制从入口到出口的流程。
structure(list(token_id = c(1.12374e+19, 1.12374e+19, 1.81313e+19,
1.85075e+19, 1.30752e+19, 1.30752e+19, 1.32828e+19, 1.70088e+19,
1.70088e+19, 1.70088e+19, 1.05536e+19, 1.44818e+19, 1.44736e+19,
1.44736e+19, 1.44736e+19, 1.44736e+19, 1.89909e+19, 1.15795e+19,
1.15795e+19, 1.15795e+19, 1.70234e+19, 1.70234e+19, 1.44062e+19,
1.21512e+19, 1.21512e+19, 1.95909e+19, 1.95909e+19, 1.50179e+19,
1.50179e+19, 1.24174e+19, 1.36445e+19, 1.98549e+19, 1.92068e+19,
1.18468e+19, 1.18468e+19, 1.92409e+19, 1.92409e+19, 1.21387e+19,
1.9162e+19, 1.9162e+19, 1.40385e+19, 1.40385e+19, 1.32996e+19,
1.32996e+19, 1.69103e+19, 1.69103e+19, 1.57387e+19, 1.40552e+19,
1.40552e+19, 1.00302e+19), Entry_Station_Lat = c(1.31509, 1.33261,
1.28425, 1.31812, 1.33858, 1.29287, 1.39692, 1.37773, 1.33858,
1.33322, 1.28179, 1.30036, 1.43697, 1.39752, 1.27637, 1.39752,
1.41747, 1.35733, 1.28405, 1.37773, 1.35898, 1.42948, 1.32774,
1.42948, 1.349, 1.36017, 1.34971, 1.38451, 1.31509, 1.31509,
1.37002, 1.34971, 1.31231, 1.39169, 1.31812, 1.44909, 1.29341,
1.41747, 1.33759, 1.44062, 1.31509, 1.38451, 1.29461, 1.32388,
1.41747, 1.27614, 1.39752, 1.39449, 1.33261, 1.31231), Entry_Station_Long = c(103.76525,
103.84718, 103.84329, 103.89308, 103.70611, 103.8526, 103.90902,
103.76339, 103.70611, 103.74217, 103.859, 103.85563, 103.7865,
103.74745, 103.84596, 103.74745, 103.83298, 103.9884, 103.85152,
103.76339, 103.75191, 103.83505, 103.67828, 103.83505, 103.74956,
103.88504, 103.87326, 103.74437, 103.76525, 103.76525, 103.84955,
103.87326, 103.83793, 103.89548, 103.89308, 103.82004, 103.78479,
103.83298, 103.69742, 103.80098, 103.76525, 103.74437, 103.80605,
103.93002, 103.83298, 103.79156, 103.74745, 103.90051, 103.84718,
103.83793), Exit_Station_Lat = structure(c(48L, 34L, 118L, 60L,
14L, 54L, 10L, 49L, 49L, 74L, 71L, 65L, 102L, 5L, 102L, 119L,
116L, 10L, 13L, 88L, 117L, 66L, 40L, 62L, 117L, 37L, 67L, 34L,
85L, 44L, 102L, 44L, 115L, 29L, 92L, 17L, 121L, 70L, 120L, 52L,
85L, 34L, 42L, 11L, 4L, 115L, 62L, 48L, 92L, 14L), .Label = c("1.27082",
"1.27091", "1.27236", "1.27614", "1.27637", "1.27646", "1.27935",
"1.28221", "1.28247", "1.28405", "1.28621", "1.28819", "1.28932",
"1.29287", "1.29309", "1.29338", "1.29341", "1.29461", "1.29694",
"1.29959", "1.29974", "1.30034", "1.30252", "1.30287", "1.30392",
"1.30394", "1.30619", "1.30736", "1.30842", "1.31139", "1.3115",
"1.31167", "1.31188", "1.31509", "1.31654", "1.31756", "1.31913",
"1.31977", "1.32008", "1.3205", "1.32104", "1.32388", "1.32573",
"1.32725", "1.32774", "1.33119", "1.33155", "1.33261", "1.33322",
"1.33474", "1.33554", "1.33759", "1.33764", "1.33858", "1.33921",
"1.34037", "1.34225", "1.34293", "1.3432", "1.34426", "1.34857",
"1.349", "1.34905", "1.35158", "1.35733", "1.35898", "1.36017",
"1.3625", "1.36849", "1.37002", "1.37121", "1.37304", "1.37666",
"1.37775", "1.3786", "1.37862", "1.38001", "1.38029", "1.3803",
"1.38178", "1.38269", "1.38295", "1.38399", "1.38423", "1.38451",
"1.38671", "1.38672", "1.38777", "1.38814", "1.3894", "1.39147",
"1.39169", "1.39189", "1.39208", "1.39389", "1.39449", "1.39452",
"1.39628", "1.39692", "1.39717", "1.39732", "1.39752", "1.39821",
"1.39928", "1.39962", "1.4023", "1.40455", "1.40511", "1.40524",
"1.40843", "1.40961", "1.41184", "1.41588", "1.41685", "1.41747",
"1.42526", "1.42948", "1.43256", "1.43697", "1.44062", "1.44909"
), class = "factor"), Exit_Station_Long = structure(c(59L, 19L,
27L, 4L, 65L, 3L, 63L, 6L, 6L, 21L, 93L, 121L, 9L, 56L, 9L, 32L,
16L, 63L, 44L, 23L, 50L, 12L, 54L, 11L, 50L, 71L, 87L, 19L, 7L,
118L, 9L, 118L, 49L, 90L, 96L, 31L, 45L, 61L, 38L, 2L, 7L, 19L,
117L, 47L, 34L, 49L, 11L, 59L, 96L, 65L), .Label = c("103.67828",
"103.69742", "103.70611", "103.72092", "103.73274", "103.74217",
"103.74437", "103.74529", "103.74745", "103.74905", "103.74956",
"103.75191", "103.7537", "103.75803", "103.76011", "103.76215",
"103.76237", "103.76449", "103.76525", "103.76648", "103.76667",
"103.76893", "103.7696", "103.77082", "103.77145", "103.77266",
"103.774", "103.77866", "103.78185", "103.78425", "103.78479",
"103.7865", "103.78744", "103.79156", "103.79631", "103.79654",
"103.79836", "103.80098", "103.803", "103.80605", "103.80745",
"103.80781", "103.80978", "103.81703", "103.82004", "103.82592",
"103.82695", "103.83216", "103.83298", "103.83505", "103.83918",
"103.83953", "103.83974", "103.84387", "103.84496", "103.84596",
"103.84673", "103.84674", "103.84718", "103.84823", "103.84955",
"103.85092", "103.85152", "103.85226", "103.8526", "103.85267",
"103.85436", "103.85446", "103.85452", "103.86088", "103.86149",
"103.86275", "103.86291", "103.86395", "103.86405", "103.86896",
"103.87087", "103.87135", "103.87534", "103.87563", "103.8763",
"103.87971", "103.88003", "103.88126", "103.88243", "103.88296",
"103.88504", "103.8858", "103.88816", "103.8886", "103.88934",
"103.89054", "103.89237", "103.89313", "103.8938", "103.89548",
"103.89719", "103.89723", "103.89854", "103.9003", "103.90051",
"103.90208", "103.90214", "103.9031", "103.90484", "103.90537",
"103.90597", "103.90599", "103.90663", "103.9086", "103.90902",
"103.9126", "103.9127", "103.91296", "103.91616", "103.9165",
"103.93002", "103.94638", "103.94929", "103.95337", "103.9884"
), class = "factor")), .Names = c("token_id", "Entry_Station_Lat",
"Entry_Station_Long", "Exit_Station_Lat", "Exit_Station_Long"
), row.names = c(10807L, 10808L, 10810L, 10815L, 10817L, 10818L,
10819L, 10820L, 10823L, 10824L, 10826L, 10827L, 10829L, 10831L,
10832L, 10833L, 10834L, 10835L, 10836L, 10838L, 10840L, 10841L,
10843L, 10847L, 10850L, 10852L, 10854L, 10855L, 10859L, 10861L,
10869L, 10872L, 10883L, 10886L, 10891L, 10895L, 10896L, 10897L,
10900L, 10902L, 10903L, 10906L, 10910L, 10911L, 10912L, 10913L,
10915L, 10920L, 10921L, 10924L), class = "data.frame")
我正在尝试得到这样的东西：Map Flow
刚刚意识到使用 geom_path 的原始解决方案比必要的更复杂。 geom_segment在不更改数据的情况下工作：
require(ggplot2)
require(ggmap)
basemap <- get_map("Singapore",
source = "stamen",
maptype = "toner",
zoom = 11)
g = ggplot(a)
map = ggmap(basemap, base_layer = g)
map = map + coord_cartesian() +
geom_curve(size = 1.3,
aes(x=as.numeric(Entry_Station_Long),
y=as.numeric(Entry_Station_Lat),
xend=as.numeric(as.character(Exit_Station_Long)),
yend=as.numeric(as.character(Exit_Station_Lat)),
color=as.factor(token_id)))
map
此解决方案利用 在地图上实现曲线。
ggmaps 用于简单 - 对于更雄心勃勃的项目，我会推荐 leaflet。
下面是使用长数据格式和一些先前数据争论的解决方案。它也使用直线而不是上面的曲线。
a %>%
mutate(path = row_number()) -> a
origin = select(a,token_id,Entry_Station_Lat,Entry_Station_Long,path)
origin$type = "origin"
dest = select(a,token_id,Exit_Station_Lat,Exit_Station_Long,path)
dest$type = "dest"
colnames(origin) = c("id","lat","long","path","type")
colnames(dest) = c("id","lat","long","path","type")
complete = rbind(origin,dest)
complete %>% arrange(path,type) -> complete
require(ggmap)
basemap <- get_map("Singapore",
source = "stamen",
maptype = "toner",
zoom = 11)
g = ggplot(complete, aes(x=as.numeric(long),
y=as.numeric(lat)))
map = ggmap(basemap, base_layer = g)
map + geom_path(aes(color = as.factor(id)),
size = 1.1)
我想为您留一个替代方法。您可以做的是重组数据。现在，您有两列用于入口站，另外两列用于出口站。通过组合这些列，您可以创建一列用于 long，另一列用于 lat。诀窍是使用 rbind() 和 c()。
让我们来看看这个简单的例子。
x <- c(1, 3, 5)
y <- c(2, 4, 6)
c(rbind(x, y))
#[1] 1 2 3 4 5 6
想象一下 x 代表入口站，y 代表出口站。 1 是起点的经度。 2 是第一次旅程结束的经度。据我从您的样本数据中可以看出，3 似乎与 2 相同。您可以删除每个 token_id 的重复数据点。如果您有大量数据，也许这是您要考虑的事情。言归正传，结合这两个函数，你可以按照你想要的顺序创建一个包含经度的列。既然你说你有日期信息，请确保按日期排序数据。然后，每段旅程的顺序在tmp中以正确的方式出现。您也想对纬度执行此操作。
现在我们查看您的示例数据。似乎 Exit_Station_Lat 和 Exit_Station_Long 是有因数的。第一个操作是将它们转换为数字。然后，您应用上述方法并创建一个数据框。我调用了你的数据mydf.
library(dplyr)
library(ggplot2)
library(ggalt)
library(ggthemes)
library(raster)
mydf %>%
mutate_at(vars(Exit_Station_Lat: Exit_Station_Long),
funs(as.numeric(as.character(.)))) -> mydf
group_by(mydf, token_id) %>%
do(data.frame(long = c(rbind(.$Entry_Station_Long,.$Exit_Station_Long)),
lat = c(rbind(.$Entry_Station_Lat, .$Exit_Station_Lat))
)
) -> tmp
现在让我们从 GADM 获取地图数据。您可以使用 raster 包下载数据。
getData(name = "GADM", country = "singapore", level = 0) %>%
fortify -> singapore
最后，你画了一张地图。关键是在geom_path()中使用group在aes中。我希望这能让你继续前进。
ggplot() +
geom_cartogram(data = singapore,
aes(x = long, y = lat, map_id = id),
map = singapore) +
geom_path(data = tmp,
aes(x = long, y = lat, group = token_id,
color = as.character(token_id)),
show.legend = FALSE) +
theme_map()
如果您想在实际的 Google 地图上绘制它，并重新创建链接地图的样式，您可以使用我的 googleway 包，该包使用 Google 的地图API。您需要 API 密钥才能使用他们的地图
library(googleway)
df$Exit_Station_Lat <- as.numeric(as.character(df$Exit_Station_Lat))
df$Exit_Station_Long <- as.numeric(as.character(df$Exit_Station_Long))
df$polyline <- apply(df, 1, function(x) {
lat <- c(x['Entry_Station_Lat'], x['Exit_Station_Lat'])
lon <- c(x['Entry_Station_Long'], x['Exit_Station_Long'])
encode_pl(lat = lat, lon = lon)
})
mapKey <- 'your_api_key'
style <- '[ { "stylers": [{ "visibility": "simplified"}]},{"stylers": [{"color": "#131314"}]},{"featureType": "water","stylers": [{"color": "#131313"},{"lightness": 7}]},{"elementType": "labels.text.fill","stylers": [{"visibility": "on"},{"lightness": 25}]}]'
google_map(key = mapKey, style = style) %>%
add_polylines(data = df,
polyline = "polyline",
mouse_over_group = "Entry_Station_Lat",
stroke_weight = 0.7,
stroke_opacity = 0.5,
stroke_colour = "#ccffff")
注意，要使用航班数据重新创建地图，请参阅 ?add_polylines
中给出的示例
您还可以显示其他类型的路线，例如，通过使用 Google 的路线 API 对行驶路线进行编码，在地点之间行驶。
df$drivingRoute <- lst_directions <- apply(df, 1, function(x){
orig <- as.numeric(c(x['Entry_Station_Lat'], x['Entry_Station_Long']))
dest <- as.numeric(c(x['Exit_Station_Lat'], x['Exit_Station_Long']))
dir <- google_directions(origin = orig, destination = dest, key = apiKey)
dir$routes$overview_polyline$points
})
google_map(key = mapKey, style = style) %>%
add_polylines(data = df,
polyline = "drivingRoute",
mouse_over_group = "Entry_Station_Lat",
stroke_weight = 0.7,
stroke_opacity = 0.5,
stroke_colour = "#ccffff")
使用 leaflet 和 geosphere
的备选答案
#get Packages
require(leaflet)
require(geosphere)
#format data
a$Entry_Station_Long = as.numeric(as.character(a$Entry_Station_Long))
a$Entry_Station_Lat = as.numeric(as.character(a$Entry_Station_Lat))
a$Exit_Station_Long = as.numeric(as.character(a$Exit_Station_Long))
a$Exit_Station_Lat = as.numeric(as.character(a$Exit_Station_Lat))
a$id = as.factor(as.numeric(as.factor(a$token_id)))
#create some colors
factpal <- colorFactor(heat.colors(30), pathList$id)
#create a list of interpolated paths
pathList = NULL
for(i in 1:nrow(a))
{
tmp = gcIntermediate(c(a$Entry_Station_Long[i],
a$Entry_Station_Lat[i]),
c(a$Exit_Station_Long[i],
a$Exit_Station_Lat[i]),n = 25,
addStartEnd=TRUE)
tmp = data.frame(tmp)
tmp$id = a[i,]$id
tmp$color = factpal(a[i,]$id)
pathList = c(pathList,list(tmp))
}
#create empty base leaflet object
leaflet() %>% addTiles() -> lf
#add each entry of pathlist to the leaflet object
for (path in pathList)
{
lf %>% addPolylines(data = path,
lng = ~lon,
lat = ~lat,
color = ~color) -> lf
}
#show output
lf
请注意，正如我之前提到的，无法在如此小的地方对路径进行地理圈定 - 大圆圈实际上是直线。如果为了美观而想要圆角边缘，您可能必须使用我的其他答案中描述的 geom_curve 方式。
我还编写了 mapdeck 库来使这样的可视化效果更具吸引力*
library(mapdeck)
set_token("MAPBOX_TOKEN") ## set your mapbox token here
df$Exit_Station_Lat <- as.numeric(as.character(df$Exit_Station_Lat))
df$Exit_Station_Long <- as.numeric(as.character(df$Exit_Station_Long))
mapdeck(
style = mapdeck_style('dark')
, location = c(104, 1)
, zoom = 8
, pitch = 45
) %>%
add_arc(
data = df
, origin = c("Entry_Station_Long", "Entry_Station_Lat")
, destination = c("Exit_Station_Long", "Exit_Station_Lat")
, layer_id = 'arcs'
, stroke_from_opacity = 100
, stroke_to_opacity = 100
, stroke_width = 3
, stroke_from = "#ccffff"
, stroke_to = "#ccffff"
)
*主观上来说
我正在尝试绘制流量图（新加坡）。我有入口（纬度、经度）和出口（纬度、经度）。我正在尝试在新加坡地图中绘制从入口到出口的流程。
structure(list(token_id = c(1.12374e+19, 1.12374e+19, 1.81313e+19,
1.85075e+19, 1.30752e+19, 1.30752e+19, 1.32828e+19, 1.70088e+19,
1.70088e+19, 1.70088e+19, 1.05536e+19, 1.44818e+19, 1.44736e+19,
1.44736e+19, 1.44736e+19, 1.44736e+19, 1.89909e+19, 1.15795e+19,
1.15795e+19, 1.15795e+19, 1.70234e+19, 1.70234e+19, 1.44062e+19,
1.21512e+19, 1.21512e+19, 1.95909e+19, 1.95909e+19, 1.50179e+19,
1.50179e+19, 1.24174e+19, 1.36445e+19, 1.98549e+19, 1.92068e+19,
1.18468e+19, 1.18468e+19, 1.92409e+19, 1.92409e+19, 1.21387e+19,
1.9162e+19, 1.9162e+19, 1.40385e+19, 1.40385e+19, 1.32996e+19,
1.32996e+19, 1.69103e+19, 1.69103e+19, 1.57387e+19, 1.40552e+19,
1.40552e+19, 1.00302e+19), Entry_Station_Lat = c(1.31509, 1.33261,
1.28425, 1.31812, 1.33858, 1.29287, 1.39692, 1.37773, 1.33858,
1.33322, 1.28179, 1.30036, 1.43697, 1.39752, 1.27637, 1.39752,
1.41747, 1.35733, 1.28405, 1.37773, 1.35898, 1.42948, 1.32774,
1.42948, 1.349, 1.36017, 1.34971, 1.38451, 1.31509, 1.31509,
1.37002, 1.34971, 1.31231, 1.39169, 1.31812, 1.44909, 1.29341,
1.41747, 1.33759, 1.44062, 1.31509, 1.38451, 1.29461, 1.32388,
1.41747, 1.27614, 1.39752, 1.39449, 1.33261, 1.31231), Entry_Station_Long = c(103.76525,
103.84718, 103.84329, 103.89308, 103.70611, 103.8526, 103.90902,
103.76339, 103.70611, 103.74217, 103.859, 103.85563, 103.7865,
103.74745, 103.84596, 103.74745, 103.83298, 103.9884, 103.85152,
103.76339, 103.75191, 103.83505, 103.67828, 103.83505, 103.74956,
103.88504, 103.87326, 103.74437, 103.76525, 103.76525, 103.84955,
103.87326, 103.83793, 103.89548, 103.89308, 103.82004, 103.78479,
103.83298, 103.69742, 103.80098, 103.76525, 103.74437, 103.80605,
103.93002, 103.83298, 103.79156, 103.74745, 103.90051, 103.84718,
103.83793), Exit_Station_Lat = structure(c(48L, 34L, 118L, 60L,
14L, 54L, 10L, 49L, 49L, 74L, 71L, 65L, 102L, 5L, 102L, 119L,
116L, 10L, 13L, 88L, 117L, 66L, 40L, 62L, 117L, 37L, 67L, 34L,
85L, 44L, 102L, 44L, 115L, 29L, 92L, 17L, 121L, 70L, 120L, 52L,
85L, 34L, 42L, 11L, 4L, 115L, 62L, 48L, 92L, 14L), .Label = c("1.27082",
"1.27091", "1.27236", "1.27614", "1.27637", "1.27646", "1.27935",
"1.28221", "1.28247", "1.28405", "1.28621", "1.28819", "1.28932",
"1.29287", "1.29309", "1.29338", "1.29341", "1.29461", "1.29694",
"1.29959", "1.29974", "1.30034", "1.30252", "1.30287", "1.30392",
"1.30394", "1.30619", "1.30736", "1.30842", "1.31139", "1.3115",
"1.31167", "1.31188", "1.31509", "1.31654", "1.31756", "1.31913",
"1.31977", "1.32008", "1.3205", "1.32104", "1.32388", "1.32573",
"1.32725", "1.32774", "1.33119", "1.33155", "1.33261", "1.33322",
"1.33474", "1.33554", "1.33759", "1.33764", "1.33858", "1.33921",
"1.34037", "1.34225", "1.34293", "1.3432", "1.34426", "1.34857",
"1.349", "1.34905", "1.35158", "1.35733", "1.35898", "1.36017",
"1.3625", "1.36849", "1.37002", "1.37121", "1.37304", "1.37666",
"1.37775", "1.3786", "1.37862", "1.38001", "1.38029", "1.3803",
"1.38178", "1.38269", "1.38295", "1.38399", "1.38423", "1.38451",
"1.38671", "1.38672", "1.38777", "1.38814", "1.3894", "1.39147",
"1.39169", "1.39189", "1.39208", "1.39389", "1.39449", "1.39452",
"1.39628", "1.39692", "1.39717", "1.39732", "1.39752", "1.39821",
"1.39928", "1.39962", "1.4023", "1.40455", "1.40511", "1.40524",
"1.40843", "1.40961", "1.41184", "1.41588", "1.41685", "1.41747",
"1.42526", "1.42948", "1.43256", "1.43697", "1.44062", "1.44909"
), class = "factor"), Exit_Station_Long = structure(c(59L, 19L,
27L, 4L, 65L, 3L, 63L, 6L, 6L, 21L, 93L, 121L, 9L, 56L, 9L, 32L,
16L, 63L, 44L, 23L, 50L, 12L, 54L, 11L, 50L, 71L, 87L, 19L, 7L,
118L, 9L, 118L, 49L, 90L, 96L, 31L, 45L, 61L, 38L, 2L, 7L, 19L,
117L, 47L, 34L, 49L, 11L, 59L, 96L, 65L), .Label = c("103.67828",
"103.69742", "103.70611", "103.72092", "103.73274", "103.74217",
"103.74437", "103.74529", "103.74745", "103.74905", "103.74956",
"103.75191", "103.7537", "103.75803", "103.76011", "103.76215",
"103.76237", "103.76449", "103.76525", "103.76648", "103.76667",
"103.76893", "103.7696", "103.77082", "103.77145", "103.77266",
"103.774", "103.77866", "103.78185", "103.78425", "103.78479",
"103.7865", "103.78744", "103.79156", "103.79631", "103.79654",
"103.79836", "103.80098", "103.803", "103.80605", "103.80745",
"103.80781", "103.80978", "103.81703", "103.82004", "103.82592",
"103.82695", "103.83216", "103.83298", "103.83505", "103.83918",
"103.83953", "103.83974", "103.84387", "103.84496", "103.84596",
"103.84673", "103.84674", "103.84718", "103.84823", "103.84955",
"103.85092", "103.85152", "103.85226", "103.8526", "103.85267",
"103.85436", "103.85446", "103.85452", "103.86088", "103.86149",
"103.86275", "103.86291", "103.86395", "103.86405", "103.86896",
"103.87087", "103.87135", "103.87534", "103.87563", "103.8763",
"103.87971", "103.88003", "103.88126", "103.88243", "103.88296",
"103.88504", "103.8858", "103.88816", "103.8886", "103.88934",
"103.89054", "103.89237", "103.89313", "103.8938", "103.89548",
"103.89719", "103.89723", "103.89854", "103.9003", "103.90051",
"103.90208", "103.90214", "103.9031", "103.90484", "103.90537",
"103.90597", "103.90599", "103.90663", "103.9086", "103.90902",
"103.9126", "103.9127", "103.91296", "103.91616", "103.9165",
"103.93002", "103.94638", "103.94929", "103.95337", "103.9884"
), class = "factor")), .Names = c("token_id", "Entry_Station_Lat",
"Entry_Station_Long", "Exit_Station_Lat", "Exit_Station_Long"
), row.names = c(10807L, 10808L, 10810L, 10815L, 10817L, 10818L,
10819L, 10820L, 10823L, 10824L, 10826L, 10827L, 10829L, 10831L,
10832L, 10833L, 10834L, 10835L, 10836L, 10838L, 10840L, 10841L,
10843L, 10847L, 10850L, 10852L, 10854L, 10855L, 10859L, 10861L,
10869L, 10872L, 10883L, 10886L, 10891L, 10895L, 10896L, 10897L,
10900L, 10902L, 10903L, 10906L, 10910L, 10911L, 10912L, 10913L,
10915L, 10920L, 10921L, 10924L), class = "data.frame")
我正在尝试得到这样的东西：Map Flow
刚刚意识到使用 geom_path 的原始解决方案比必要的更复杂。 geom_segment在不更改数据的情况下工作：
require(ggplot2)
require(ggmap)
basemap <- get_map("Singapore",
source = "stamen",
maptype = "toner",
zoom = 11)
g = ggplot(a)
map = ggmap(basemap, base_layer = g)
map = map + coord_cartesian() +
geom_curve(size = 1.3,
aes(x=as.numeric(Entry_Station_Long),
y=as.numeric(Entry_Station_Lat),
xend=as.numeric(as.character(Exit_Station_Long)),
yend=as.numeric(as.character(Exit_Station_Lat)),
color=as.factor(token_id)))
map
此解决方案利用
ggmaps 用于简单 - 对于更雄心勃勃的项目，我会推荐 leaflet。
下面是使用长数据格式和一些先前数据争论的解决方案。它也使用直线而不是上面的曲线。
a %>%
mutate(path = row_number()) -> a
origin = select(a,token_id,Entry_Station_Lat,Entry_Station_Long,path)
origin$type = "origin"
dest = select(a,token_id,Exit_Station_Lat,Exit_Station_Long,path)
dest$type = "dest"
colnames(origin) = c("id","lat","long","path","type")
colnames(dest) = c("id","lat","long","path","type")
complete = rbind(origin,dest)
complete %>% arrange(path,type) -> complete
require(ggmap)
basemap <- get_map("Singapore",
source = "stamen",
maptype = "toner",
zoom = 11)
g = ggplot(complete, aes(x=as.numeric(long),
y=as.numeric(lat)))
map = ggmap(basemap, base_layer = g)
map + geom_path(aes(color = as.factor(id)),
size = 1.1)
我想为您留一个替代方法。您可以做的是重组数据。现在，您有两列用于入口站，另外两列用于出口站。通过组合这些列，您可以创建一列用于 long，另一列用于 lat。诀窍是使用 rbind() 和 c()。
让我们来看看这个简单的例子。
x <- c(1, 3, 5)
y <- c(2, 4, 6)
c(rbind(x, y))
#[1] 1 2 3 4 5 6
想象一下 x 代表入口站，y 代表出口站。 1 是起点的经度。 2 是第一次旅程结束的经度。据我从您的样本数据中可以看出，3 似乎与 2 相同。您可以删除每个 token_id 的重复数据点。如果您有大量数据，也许这是您要考虑的事情。言归正传，结合这两个函数，你可以按照你想要的顺序创建一个包含经度的列。既然你说你有日期信息，请确保按日期排序数据。然后，每段旅程的顺序在tmp中以正确的方式出现。您也想对纬度执行此操作。
现在我们查看您的示例数据。似乎 Exit_Station_Lat 和 Exit_Station_Long 是有因数的。第一个操作是将它们转换为数字。然后，您应用上述方法并创建一个数据框。我调用了你的数据mydf.
library(dplyr)
library(ggplot2)
library(ggalt)
library(ggthemes)
library(raster)
mydf %>%
mutate_at(vars(Exit_Station_Lat: Exit_Station_Long),
funs(as.numeric(as.character(.)))) -> mydf
group_by(mydf, token_id) %>%
do(data.frame(long = c(rbind(.$Entry_Station_Long,.$Exit_Station_Long)),
lat = c(rbind(.$Entry_Station_Lat, .$Exit_Station_Lat))
)
) -> tmp
现在让我们从 GADM 获取地图数据。您可以使用 raster 包下载数据。
getData(name = "GADM", country = "singapore", level = 0) %>%
fortify -> singapore
最后，你画了一张地图。关键是在geom_path()中使用group在aes中。我希望这能让你继续前进。
ggplot() +
geom_cartogram(data = singapore,
aes(x = long, y = lat, map_id = id),
map = singapore) +
geom_path(data = tmp,
aes(x = long, y = lat, group = token_id,
color = as.character(token_id)),
show.legend = FALSE) +
theme_map()
如果您想在实际的 Google 地图上绘制它，并重新创建链接地图的样式，您可以使用我的 googleway 包，该包使用 Google 的地图API。您需要 API 密钥才能使用他们的地图
library(googleway)
df$Exit_Station_Lat <- as.numeric(as.character(df$Exit_Station_Lat))
df$Exit_Station_Long <- as.numeric(as.character(df$Exit_Station_Long))
df$polyline <- apply(df, 1, function(x) {
lat <- c(x['Entry_Station_Lat'], x['Exit_Station_Lat'])
lon <- c(x['Entry_Station_Long'], x['Exit_Station_Long'])
encode_pl(lat = lat, lon = lon)
})
mapKey <- 'your_api_key'
style <- '[ { "stylers": [{ "visibility": "simplified"}]},{"stylers": [{"color": "#131314"}]},{"featureType": "water","stylers": [{"color": "#131313"},{"lightness": 7}]},{"elementType": "labels.text.fill","stylers": [{"visibility": "on"},{"lightness": 25}]}]'
google_map(key = mapKey, style = style) %>%
add_polylines(data = df,
polyline = "polyline",
mouse_over_group = "Entry_Station_Lat",
stroke_weight = 0.7,
stroke_opacity = 0.5,
stroke_colour = "#ccffff")
注意，要使用航班数据重新创建地图，请参阅 ?add_polylines
您还可以显示其他类型的路线，例如，通过使用 Google 的路线 API 对行驶路线进行编码，在地点之间行驶。
df$drivingRoute <- lst_directions <- apply(df, 1, function(x){
orig <- as.numeric(c(x['Entry_Station_Lat'], x['Entry_Station_Long']))
dest <- as.numeric(c(x['Exit_Station_Lat'], x['Exit_Station_Long']))
dir <- google_directions(origin = orig, destination = dest, key = apiKey)
dir$routes$overview_polyline$points
})
google_map(key = mapKey, style = style) %>%
add_polylines(data = df,
polyline = "drivingRoute",
mouse_over_group = "Entry_Station_Lat",
stroke_weight = 0.7,
stroke_opacity = 0.5,
stroke_colour = "#ccffff")
使用 leaflet 和 geosphere
#get Packages
require(leaflet)
require(geosphere)
#format data
a$Entry_Station_Long = as.numeric(as.character(a$Entry_Station_Long))
a$Entry_Station_Lat = as.numeric(as.character(a$Entry_Station_Lat))
a$Exit_Station_Long = as.numeric(as.character(a$Exit_Station_Long))
a$Exit_Station_Lat = as.numeric(as.character(a$Exit_Station_Lat))
a$id = as.factor(as.numeric(as.factor(a$token_id)))
#create some colors
factpal <- colorFactor(heat.colors(30), pathList$id)
#create a list of interpolated paths
pathList = NULL
for(i in 1:nrow(a))
{
tmp = gcIntermediate(c(a$Entry_Station_Long[i],
a$Entry_Station_Lat[i]),
c(a$Exit_Station_Long[i],
a$Exit_Station_Lat[i]),n = 25,
addStartEnd=TRUE)
tmp = data.frame(tmp)
tmp$id = a[i,]$id
tmp$color = factpal(a[i,]$id)
pathList = c(pathList,list(tmp))
}
#create empty base leaflet object
leaflet() %>% addTiles() -> lf
#add each entry of pathlist to the leaflet object
for (path in pathList)
{
lf %>% addPolylines(data = path,
lng = ~lon,
lat = ~lat,
color = ~color) -> lf
}
#show output
lf
请注意，正如我之前提到的，无法在如此小的地方对路径进行地理圈定 - 大圆圈实际上是直线。如果为了美观而想要圆角边缘，您可能必须使用我的其他答案中描述的 geom_curve 方式。
我还编写了 mapdeck 库来使这样的可视化效果更具吸引力*
library(mapdeck)
set_token("MAPBOX_TOKEN") ## set your mapbox token here
df$Exit_Station_Lat <- as.numeric(as.character(df$Exit_Station_Lat))
df$Exit_Station_Long <- as.numeric(as.character(df$Exit_Station_Long))
mapdeck(
style = mapdeck_style('dark')
, location = c(104, 1)
, zoom = 8
, pitch = 45
) %>%
add_arc(
data = df
, origin = c("Entry_Station_Long", "Entry_Station_Lat")
, destination = c("Exit_Station_Long", "Exit_Station_Lat")
, layer_id = 'arcs'
, stroke_from_opacity = 100
, stroke_to_opacity = 100
, stroke_width = 3
, stroke_from = "#ccffff"
, stroke_to = "#ccffff"
)
*主观上来说