鼠标悬停样式触发器不会更改背景
MouseOver style trigger won't change background
WPF 新手,网络背景。
我的样式触发器不会更改按钮背景。样式 XAML:
<Window.Resources>
<Style TargetType="Button">
<Setter Property="Background" Value="GhostWhite" />
<Style.Triggers>
<Trigger Property="IsMouseOver" Value="True">
<Setter Property="Background" Value="#F48230"/>
</Trigger>
</Style.Triggers>
</Style>
</Window.Resources>
按钮 XAML(与 Window 或网格属性无关):
<Window...>
<Grid...>
<StackPanel Orientation="Horizontal" Grid.Row="7" Grid.Column="0" Grid.ColumnSpan="2" VerticalAlignment="Center" HorizontalAlignment="Center">
<Button Name="btnEdit" Cursor="Hand" Content="Edit Settings..." HorizontalAlignment="Left" VerticalAlignment="Top" Width="100" Margin="0,0,5,0" Click="btnEdit_Click"/>
<Button Name="btnExit" Cursor="Hand" Content="Exit" HorizontalAlignment="Left" VerticalAlignment="Top" Width="100" Margin="5,0,0,0" Click="btnExit_Click" />
</StackPanel>
</Grid>
</Window>
按钮会选择资源部分中的背景样式,但不会选择触发器 - 鼠标悬停会导致默认行为。
补充问题:有什么方法可以调试吗?我查看了 Live Visual Tree,但不知道如何获取我需要的信息。
WPF 控件具有类型为 ControlTemplate 的 Template 属性。这个 属性 告诉 WPF 如何在屏幕上绘制控件。 WPF 按钮在其 ControlTemplate 中使用 Windows Chrome,它使用用户选择的系统颜色以允许不同应用程序之间的一致性。利用 WPF 和 XAML 的魔力,您可以创建自己的 ControlTemplate 使按钮看起来像您认为合适的任何方式。
创建带有键的样式,以便您可以选择哪些按钮使用模板:
<Window.Resources>
<Style x:Key="MyButtonStyle" TargetType="{x:Type Button}">
<Setter Property="Background" Value="GhostWhite" />
<Setter Property="Control.Template">
<Setter.Value>
<ControlTemplate TargetType="{x:Type Button}">
<!-- a simple square button -->
<Border Name="wrapper"
Width="{TemplateBinding Width}"
Height="{TemplateBinding Height}"
BorderBrush="{TemplateBinding BorderBrush}"
BorderThickness="{TemplateBinding BorderThickness}"
Margin="{TemplateBinding Margin}"
Background="#01000000">
<!-- notice the wrapper has a background that is NEAR transparent. This is important. It'll ensure the button raises the click event -->
<Border Name=inner
Background="{TemplateBinding Background}">
<ContentPresenter Margin="{TemplateBinding Padding}"
HorizontalAlignment="Center"
VerticalAlignment="Center" />
</Border>
</Border>
</ControlTemplate>
</Setter.Value>
</Setter>
<Style.Triggers>
<Trigger Property="IsMouseOver" Value="True">
<Setter Property="Background" Value="#FFF48230"/>
</Trigger>
<Trigger Property="IsPressed" Value="true">
<Setter Property="Background" Value="#FF99501B"/>
</Trigger>
</Style.Triggers>
</Style>
</Window.Resources>
然后在按钮上使用模板:
<Window...>
<Grid...>
<StackPanel Orientation="Horizontal" Grid.Row="7" Grid.Column="0" Grid.ColumnSpan="2" VerticalAlignment="Center" HorizontalAlignment="Center">
<Button Style="{StaticResource MyButtonStyle}" Name="btnEdit" Cursor="Hand" Content="Edit Settings..." HorizontalAlignment="Left" VerticalAlignment="Top" Width="100" Margin="0,0,5,0" Click="btnEdit_Click"/>
<Button Style="{StaticResource MyButtonStyle}" Name="btnExit" Cursor="Hand" Content="Exit" HorizontalAlignment="Left" VerticalAlignment="Top" Width="100" Margin="5,0,0,0" Click="btnExit_Click" />
</StackPanel>
</Grid>
</Window>
WPF 新手,网络背景。
我的样式触发器不会更改按钮背景。样式 XAML:
<Window.Resources>
<Style TargetType="Button">
<Setter Property="Background" Value="GhostWhite" />
<Style.Triggers>
<Trigger Property="IsMouseOver" Value="True">
<Setter Property="Background" Value="#F48230"/>
</Trigger>
</Style.Triggers>
</Style>
</Window.Resources>
按钮 XAML(与 Window 或网格属性无关):
<Window...>
<Grid...>
<StackPanel Orientation="Horizontal" Grid.Row="7" Grid.Column="0" Grid.ColumnSpan="2" VerticalAlignment="Center" HorizontalAlignment="Center">
<Button Name="btnEdit" Cursor="Hand" Content="Edit Settings..." HorizontalAlignment="Left" VerticalAlignment="Top" Width="100" Margin="0,0,5,0" Click="btnEdit_Click"/>
<Button Name="btnExit" Cursor="Hand" Content="Exit" HorizontalAlignment="Left" VerticalAlignment="Top" Width="100" Margin="5,0,0,0" Click="btnExit_Click" />
</StackPanel>
</Grid>
</Window>
按钮会选择资源部分中的背景样式,但不会选择触发器 - 鼠标悬停会导致默认行为。
补充问题:有什么方法可以调试吗?我查看了 Live Visual Tree,但不知道如何获取我需要的信息。
WPF 控件具有类型为 ControlTemplate 的 Template 属性。这个 属性 告诉 WPF 如何在屏幕上绘制控件。 WPF 按钮在其 ControlTemplate 中使用 Windows Chrome,它使用用户选择的系统颜色以允许不同应用程序之间的一致性。利用 WPF 和 XAML 的魔力,您可以创建自己的 ControlTemplate 使按钮看起来像您认为合适的任何方式。
创建带有键的样式,以便您可以选择哪些按钮使用模板:
<Window.Resources>
<Style x:Key="MyButtonStyle" TargetType="{x:Type Button}">
<Setter Property="Background" Value="GhostWhite" />
<Setter Property="Control.Template">
<Setter.Value>
<ControlTemplate TargetType="{x:Type Button}">
<!-- a simple square button -->
<Border Name="wrapper"
Width="{TemplateBinding Width}"
Height="{TemplateBinding Height}"
BorderBrush="{TemplateBinding BorderBrush}"
BorderThickness="{TemplateBinding BorderThickness}"
Margin="{TemplateBinding Margin}"
Background="#01000000">
<!-- notice the wrapper has a background that is NEAR transparent. This is important. It'll ensure the button raises the click event -->
<Border Name=inner
Background="{TemplateBinding Background}">
<ContentPresenter Margin="{TemplateBinding Padding}"
HorizontalAlignment="Center"
VerticalAlignment="Center" />
</Border>
</Border>
</ControlTemplate>
</Setter.Value>
</Setter>
<Style.Triggers>
<Trigger Property="IsMouseOver" Value="True">
<Setter Property="Background" Value="#FFF48230"/>
</Trigger>
<Trigger Property="IsPressed" Value="true">
<Setter Property="Background" Value="#FF99501B"/>
</Trigger>
</Style.Triggers>
</Style>
</Window.Resources>
然后在按钮上使用模板:
<Window...>
<Grid...>
<StackPanel Orientation="Horizontal" Grid.Row="7" Grid.Column="0" Grid.ColumnSpan="2" VerticalAlignment="Center" HorizontalAlignment="Center">
<Button Style="{StaticResource MyButtonStyle}" Name="btnEdit" Cursor="Hand" Content="Edit Settings..." HorizontalAlignment="Left" VerticalAlignment="Top" Width="100" Margin="0,0,5,0" Click="btnEdit_Click"/>
<Button Style="{StaticResource MyButtonStyle}" Name="btnExit" Cursor="Hand" Content="Exit" HorizontalAlignment="Left" VerticalAlignment="Top" Width="100" Margin="5,0,0,0" Click="btnExit_Click" />
</StackPanel>
</Grid>
</Window>