使用 Automapper 映射具有相似名称的成员

Question

在我只能读取的远程数据库中，一天中的每个小时都有 24 列连续。他们的名字分别是 P1、P2、...、P24。

我必须将这些值复制到我自己的数据库中，我将其命名为 H1、H2、...、H24。

如何使用自动映射器将远程列映射到本地？

CreateMap<Data.Context.SomeTableFromRemoteDb, Data.Entity.MyTableInLocaldb>()
                .ForMember(x => x.H1, y => y.MapFrom(z => z.P1))
                .ForMember(x => x.H2, y => y.MapFrom(z => z.P2))
                .ForMember(x => x.H3, y => y.MapFrom(z => z.P3))
                .ForMember(x => x.H4, y => y.MapFrom(z => z.P4))
                .ForMember(x => x.H5, y => y.MapFrom(z => z.P5))
                .ForMember(x => x.H6, y => y.MapFrom(z => z.P6))
                .ForMember(x => x.H7, y => y.MapFrom(z => z.P7))
                .ForMember(x => x.H8, y => y.MapFrom(z => z.P8))
                .ForMember(x => x.H9, y => y.MapFrom(z => z.P9))
                .ForMember(x => x.H10, y => y.MapFrom(z => z.P10))
                 .ForMember(x => x.H11, y => y.MapFrom(z => z.P11))
                 .ForMember(x => x.H12, y => y.MapFrom(z => z.P12))
                 .ForMember(x => x.H13, y => y.MapFrom(z => z.P13))
                 .ForMember(x => x.H14, y => y.MapFrom(z => z.P14))
                 .ForMember(x => x.H15, y => y.MapFrom(z => z.P15))
                 .ForMember(x => x.H16, y => y.MapFrom(z => z.P16))
                 .ForMember(x => x.H17, y => y.MapFrom(z => z.P17))
                 .ForMember(x => x.H18, y => y.MapFrom(z => z.P18))
                 .ForMember(x => x.H19, y => y.MapFrom(z => z.P19))
                 .ForMember(x => x.H20, y => y.MapFrom(z => z.P20))
                 .ForMember(x => x.H21, y => y.MapFrom(z => z.P21))
                 .ForMember(x => x.H22, y => y.MapFrom(z => z.P22))
                 .ForMember(x => x.H23, y => y.MapFrom(z => z.P23))
                 .ForMember(x => x.H24, y => y.MapFrom(z => z.P24));

这是当前代码。我想问的是我们可以把它转换成这样吗：

CreateMap<Data.Context.SomeTableFromRemoteDb, Data.Entity.MyTableInLocaldb>()
                    .ForMember(x => x.ReplaceMemberName(o=> o, "H", "P"), y => y.MapFrom(z => z.P1))

Automapper 有一个名为 replacemembername 的函数，但它似乎不是我要找的。

Answer 1

您对 ReplaceMemberName 的看法几乎是正确的，但使用起来有点不正确。它应该应用于整个映射器配置。有关详细信息，请参阅 https://github.com/AutoMapper/AutoMapper/wiki/Configuration#replacing-characters。

    private static void Main(string[] args)
    {
        var a = new Class1
        {
            a1 = "1",
            a2 = "2",
            a3 = "3",
            a4 = "4",
            a5 = "5"
        };

        Mapper.Initialize(config =>
            {
                config.ReplaceMemberName("a", "b");
                config.CreateMap<Class1, Class2>();
            }
        );

        var b = Mapper.Map<Class1, Class2>(a);
    }

    private class Class1
    {
        public string a1;
        public string a2;
        public string a3;
        public string a4;
        public string a5;
    }

    private class Class2
    {
        public string b1;
        public string b2;
        public string b3;
        public string b4;
        public string b5;
    }

您也可以像这样创建本地映射器：

var config = new MapperConfiguration(c =>
{
    c.ReplaceMemberName("a", "b");
    c.CreateMap<Class1, Class2>();
});

var mapper = config.CreateMapper();

var b = mapper.Map<Class1, Class2>(a);

使用 Automapper 映射具有相似名称的成员

Mapping members with similar names Using Automapper

c#

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