UserProvider 没有实现正确的接口
UserProvider not implementing correct interface
我正在尝试将自定义 UserProvider 与 FOS 用户捆绑包和 FOS Oauth 包一起使用。我一直在关注本教程 http://blog.tankist.de/blog/2013/07/17/oauth2-explained-part-2-setting-up-oauth2-with-symfony2-using-fosoauthserverbundle/.
当我尝试注册我的新用户服务时,出现以下错误
UserProvider::__construct() must implement interface Doctrine\Common\Persistence\ObjectRepository, array given
用户提供者:
UserProvider implements UserProviderInterface
{
/**
* @var ObjectRepository
*/
protected $userRepository;
/**
* @param ObjectRepository $userRepository
*/
public function __construct(ObjectRepository $userRepository)
{
$this->userRepository = $userRepository;
}
/**
* @param string $username
* @return mixed
*/
public function loadUserByUsername($username)
{ ... }
用户存储库
class UserRepository extends EntityRepository implements ObjectRepository
services.yml
parameters:
entity_name: Hornby\UserBundle\Entity\UserRepository
services:
user_provider_me:
class: Hornby\UserBundle\Provider\UserProvider
arguments:
name: [%entity_name%]
您的 services.yml 文件有误。我不太确定你想要实现什么,但你传递了数组
arguments:
name: [%entity_name%] #entity_name is just a string
作为 UserProvider
class 的参数。此 class 的构造函数期望 ObjectRepository
,这是您的问题。
您提供的 link 的 services.xml 翻译应该看起来像这样:
parameters:
platform.entity.user.class: Acme\DemoBundle\Entity\User
platform.user.provider.class: Acme\DemoBundle\Provider\UserProvider
services:
platform.user.manager:
class: Doctrine\ORM\EntityManager
factory: ["@doctrine", getManagerForClass]
arguments: [%platform.entity.user.class%]
platform.user.repository:
class: Acme\DemoBundle\Repository\UserRepository
factory: ["@platform.user.manager", getRepository]
arguments: [%platform.entity.user.class%]
platform.user.provider:
class: %platform.user.provider.class%
arguments: [@platform.user.repository]
我正在尝试将自定义 UserProvider 与 FOS 用户捆绑包和 FOS Oauth 包一起使用。我一直在关注本教程 http://blog.tankist.de/blog/2013/07/17/oauth2-explained-part-2-setting-up-oauth2-with-symfony2-using-fosoauthserverbundle/.
当我尝试注册我的新用户服务时,出现以下错误
UserProvider::__construct() must implement interface Doctrine\Common\Persistence\ObjectRepository, array given
用户提供者:
UserProvider implements UserProviderInterface
{
/**
* @var ObjectRepository
*/
protected $userRepository;
/**
* @param ObjectRepository $userRepository
*/
public function __construct(ObjectRepository $userRepository)
{
$this->userRepository = $userRepository;
}
/**
* @param string $username
* @return mixed
*/
public function loadUserByUsername($username)
{ ... }
用户存储库
class UserRepository extends EntityRepository implements ObjectRepository
services.yml
parameters:
entity_name: Hornby\UserBundle\Entity\UserRepository
services:
user_provider_me:
class: Hornby\UserBundle\Provider\UserProvider
arguments:
name: [%entity_name%]
您的 services.yml 文件有误。我不太确定你想要实现什么,但你传递了数组
arguments:
name: [%entity_name%] #entity_name is just a string
作为 UserProvider
class 的参数。此 class 的构造函数期望 ObjectRepository
,这是您的问题。
您提供的 link 的 services.xml 翻译应该看起来像这样:
parameters:
platform.entity.user.class: Acme\DemoBundle\Entity\User
platform.user.provider.class: Acme\DemoBundle\Provider\UserProvider
services:
platform.user.manager:
class: Doctrine\ORM\EntityManager
factory: ["@doctrine", getManagerForClass]
arguments: [%platform.entity.user.class%]
platform.user.repository:
class: Acme\DemoBundle\Repository\UserRepository
factory: ["@platform.user.manager", getRepository]
arguments: [%platform.entity.user.class%]
platform.user.provider:
class: %platform.user.provider.class%
arguments: [@platform.user.repository]