在 PostgreSQL 函数中使用递归查询
Use a recursive query in a PostgreSQL function
我有一个包含 (id, name, parent_id ) 列的 table 文件夹。作为父文件夹的文件夹是 parent_id = -1。我需要获取每个文件夹的顶级父 ID。以下查询工作正常,但不适用于 spring data jpa.
WITH RECURSIVE nodes_cte AS (
SELECT tn.id, tn.parent_id, tn.name, tn.id top_id
FROM folder AS tn
WHERE tn.parent_id =-1
UNION ALL
SELECT c.id, c.parent_id, c.name, p.top_id
FROM nodes_cte AS p, folder AS c
WHERE c.parent_id = p.id
)
SELECT distinct * FROM nodes_cte
我如何创建 postgresql 函数来 return 与上述查询相同的结果?
创建一个 SQL 函数返回 table:
CREATE OR REPLACE FUNCTION my_function()
RETURNS TABLE (id int, parent_id int, name text, top_id int)
LANGUAGE SQL AS $$
WITH RECURSIVE nodes_cte AS (
SELECT tn.id, tn.parent_id, tn.name, tn.id top_id
FROM folder AS tn
WHERE tn.parent_id =-1
UNION ALL
SELECT c.id, c.parent_id, c.name, p.top_id
FROM nodes_cte AS p, folder AS c
WHERE c.parent_id = p.id
)
SELECT distinct * FROM nodes_cte
$$;
--use:
SELECT *
FROM my_function();
请注意,返回的 table 中的 name
列应与 table folder
.
中的类型相同
我有一个包含 (id, name, parent_id ) 列的 table 文件夹。作为父文件夹的文件夹是 parent_id = -1。我需要获取每个文件夹的顶级父 ID。以下查询工作正常,但不适用于 spring data jpa.
WITH RECURSIVE nodes_cte AS (
SELECT tn.id, tn.parent_id, tn.name, tn.id top_id
FROM folder AS tn
WHERE tn.parent_id =-1
UNION ALL
SELECT c.id, c.parent_id, c.name, p.top_id
FROM nodes_cte AS p, folder AS c
WHERE c.parent_id = p.id
)
SELECT distinct * FROM nodes_cte
我如何创建 postgresql 函数来 return 与上述查询相同的结果?
创建一个 SQL 函数返回 table:
CREATE OR REPLACE FUNCTION my_function()
RETURNS TABLE (id int, parent_id int, name text, top_id int)
LANGUAGE SQL AS $$
WITH RECURSIVE nodes_cte AS (
SELECT tn.id, tn.parent_id, tn.name, tn.id top_id
FROM folder AS tn
WHERE tn.parent_id =-1
UNION ALL
SELECT c.id, c.parent_id, c.name, p.top_id
FROM nodes_cte AS p, folder AS c
WHERE c.parent_id = p.id
)
SELECT distinct * FROM nodes_cte
$$;
--use:
SELECT *
FROM my_function();
请注意,返回的 table 中的 name
列应与 table folder
.