Delayed_job 在 Rails 应用程序的 Ruby 中不工作

Question

我只是想在特定时间获取运行的函数，但运气不佳。让我运行简单介绍一下我所做的事情

#Gemfile

gem 'delayed_job_active_record'

#config/application.rb

module SampleApp
  class Application < Rails::Application
    # Settings in config/environments/* take precedence over those specified here.
    # Application configuration should go into files in config/initializers
    # -- all .rb files in that directory are automatically loaded.
    config.active_job.queue_adapter = :delayed_job
  end
end

#Ran from command line

[06.07.2017/15:38:02] user@ubuntu $ rails g delayed_job:active_record
Running via Spring preloader in process 72879
   identical  bin/delayed_job
       chmod  bin/delayed_job
      create  db/migrate/20170607203821_create_delayed_jobs.rb
[06.07.2017/15:38:21] user@ubuntu $ rake db:migrate
== 20170607203821 CreateDelayedJobs: migrating ================================
-- create_table(:delayed_jobs, {:force=>true})
   -> 0.0088s
-- add_index(:delayed_jobs, [:priority, :run_at], {:name=>"delayed_jobs_priority"})
   -> 0.0051s
== 20170607203821 CreateDelayedJobs: migrated (0.0142s) =======================

所以我的视图上基本上有一个调用 post_now 的按钮，然后它会调用我拥有的自定义模型中的一个函数。这是我所拥有的示例：

#posts_controller.rb
  def post_now
    set_post
    submit_post = SchedulePost.delay(run_at: 1.minute.from_now).schedule_post(@post)
    redirect_to posts_path, flash: {success: submit_post[1] }
  end

然后是 SchedulePost class，它只是在编写一个文本文件（暂时）

#models/schedule_post.rb
class SchedulePost < ActiveRecord::Base
    def self.schedule_post(post)
        command = "touch #{Rails.root}/public/test.txt"
        system(command)
        return
    end
end

所以我期望发生的是，当 post_now 被调用时，它应该运行从现在起 1 分钟后的 schedule_post 函数，它应该简单地写成一个文本文件。如果我删除 .delay(run_at: 1.minute.from_now) 块并只将 schedule_post 留在那里，那么它就可以正常工作。所以我肯定在延迟功能上做错了。

Answer 1

您需要启动 delayed_job worker 来执行延迟任务...在您的终端中从应用程序根目录执行

rake jobs:work

Delayed_job 在 Rails 应用程序的 Ruby 中不工作

Delayed_job not working in Ruby on Rails app

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