来自 appDelegate 时的 performSegue 错误

Question

我的情况比较特殊，因为如果在正常模式下打开应用程序，这对我来说是正确的。

这是我在收到推送通知后尝试这样做的时候。

内部 didReceive 通知：

func application(_ application: UIApplication, didReceive notification: UILocalNotification) {

我正在从我的 initial view controller(HOME)

中调用一个函数

That is just the view that is displayed when the application opens when you click on the notification

let homeVC : HomeViewController! = HomeViewController()
homeVC.goAdvertisement(id, data: dataInfo)

在 goAdvertisement 中您可以找到：

self.performSegue(withIdentifier: "mySegue", sender: itemData)

这就是错误发生的地方。

libc++abi.dylib: terminating with uncaught exception of type NSException

起初我认为可能是它给了加载视图的时间，以便我可以执行 performSegue，并尝试使用以下方法延迟它：

func delay(delay:Double, closure:@escaping ()->()) {
        DispatchQueue.main.asyncAfter(deadline: .now() + delay) {
            closure()
        }
    }

self.delay(delay: 4, closure: {
    let homeVC : HomeViewController! = HomeViewController()
    homeVC.goAdvertisement(id, hardwareAd: dataInfo)
}

但是不行

我的另一个想法是抛开 performSegue 并尝试使用 present.

let vc = self.storyboard?.instantiateViewController(withIdentifier: "myVcId") as! MyController
vc.data = itemData
self.present(vc, animated: true, completion: nil)

但是这个也没用（崩溃指向instantiateViewController行）

非常感谢任何帮助，谢谢。

更新

关注 APK APPS 回答。终于找到方法了

let storyboard = UIStoryboard(name: "Main", bundle: nil)
let homeVC: HomeViewController = storyboard.instantiateViewController(withIdentifier: "homeView") as! HomeViewController

let rootViewController = self.window!.rootViewController as! UINavigationController;
rootViewController.pushViewController(homeVC, animated: false);

Answer 1

From the AppDelegate class you can not perform segue. So this line will never work from your AppDelegate class.

self.performSegue(withIdentifier: "mySegue", sender: itemData)

你需要简单

let storyboard = UIStoryboard(name: "Main", bundle: nil)
let scheduleController = storyboard.instantiateViewController(withIdentifier: "yourIdentiFier")
self.window!.rootViewController = scheduleController
self.window!.makeKeyAndVisible()

您可以从您的 Main.storyboard 向您的控制器提供标识符，请按照以下步骤操作。

打开主故事板
单击要打开的视图
Select 该控制器顶部的黄色/左按钮
现在打开位于右侧的实用工具箱
现在点击 Show the Identical Inspector
现在您可以将您的身份作为 StoryBoard Id

来自 appDelegate 时的 performSegue 错误

performSegue error when come from appDelegate

crash

ios

segue

uistoryboardsegue

swift