在 Python 中绘制实时数据
Plotting Real Time Data in Python
我编写了一个生成随机坐标并将它们写入没有格式的文本文件的脚本。
有没有办法格式化此列表以使其更易于阅读?像 (x, y) 每行?现在它是一个列表,它们之间只有一个 space。
有没有更简单的方法在一个 python 文件中生成随机坐标而不使用文本文件?还是使用文本文件更容易?
下面是这个的工作代码和文本文件的示例:(根据评论和工作进行了修订)
import random
import threading
def main():
#Open a file named numbersmake.txt.
outfile = open('new.txt', 'w')
for count in range(12000):
x = random.randint(0,10000)
y = random.randint(0,10000)
outfile.write("{},{}\n".format(x, y))
#Close the file.
outfile.close()
print('The data is now the the new.txt file')
def coordinate():
threading.Timer(0.0000000000001, coordinate).start ()
coordinate()
#Call the main function
main()
我试过拆分,但没有用。我知道我不需要线程选项。我宁愿在范围内穿线,但目前范围还可以...
Example of the text in text file:
[4308][1461][1163][846][1532][318]... and so on
我写了一个 python 脚本来读取坐标的文本文件并将它们放在图表上,但是,没有绘制任何点。该图本身确实显示了。下面是代码:(根据评论修改)
import matplotlib.pyplot as plt
import matplotlib.animation as animation
from matplotlib import style
from numpy import loadtxt
style.use('dark_background')
fig = plt.figure()
ax1 = fig.add_subplot(1,1,1)
with open('new.txt') as graph_data:
for line in graph_data:
x, y = line.split(',')
def animate(i):
xs = []
ys = []
for line in graph_data:
if len(line)>1:
x,y = line.split(',')
xs.append(x)
ys.append(y)
ax1.clear()
ax1.plot(xs,ys)
lines = loadtxt("C:\Users\591756\new.txt", comments="#", delimiter=",", unpack="false")
ani = animation.FuncAnimation(fig, animate, interval=1000) # 1 second- 10000 milliseconds
plt.show()
为了让你的绘图逻辑正常工作,文件应该这样写
with open('new.txt', 'w') as out_file:
for count in range(12000):
x = random.randint(0,10000)
y = random.randint(0,10000)
outfile.write("{},{}\n".format(x, y))
此外,您阅读这样的行
def animate(i):
xs = []
ys = []
with open('filename') as graph_data:
for line in graph_data:
x, y = line.split(',')
xs.append(x)
ys.append(y)
ax1.clear()
ax1.plot(xs,ys)
我编写了一个生成随机坐标并将它们写入没有格式的文本文件的脚本。
有没有办法格式化此列表以使其更易于阅读?像 (x, y) 每行?现在它是一个列表,它们之间只有一个 space。
有没有更简单的方法在一个 python 文件中生成随机坐标而不使用文本文件?还是使用文本文件更容易?
下面是这个的工作代码和文本文件的示例:(根据评论和工作进行了修订)
import random
import threading
def main():
#Open a file named numbersmake.txt.
outfile = open('new.txt', 'w')
for count in range(12000):
x = random.randint(0,10000)
y = random.randint(0,10000)
outfile.write("{},{}\n".format(x, y))
#Close the file.
outfile.close()
print('The data is now the the new.txt file')
def coordinate():
threading.Timer(0.0000000000001, coordinate).start ()
coordinate()
#Call the main function
main()
我试过拆分,但没有用。我知道我不需要线程选项。我宁愿在范围内穿线,但目前范围还可以...
Example of the text in text file: [4308][1461][1163][846][1532][318]... and so on
我写了一个 python 脚本来读取坐标的文本文件并将它们放在图表上,但是,没有绘制任何点。该图本身确实显示了。下面是代码:(根据评论修改)
import matplotlib.pyplot as plt
import matplotlib.animation as animation
from matplotlib import style
from numpy import loadtxt
style.use('dark_background')
fig = plt.figure()
ax1 = fig.add_subplot(1,1,1)
with open('new.txt') as graph_data:
for line in graph_data:
x, y = line.split(',')
def animate(i):
xs = []
ys = []
for line in graph_data:
if len(line)>1:
x,y = line.split(',')
xs.append(x)
ys.append(y)
ax1.clear()
ax1.plot(xs,ys)
lines = loadtxt("C:\Users\591756\new.txt", comments="#", delimiter=",", unpack="false")
ani = animation.FuncAnimation(fig, animate, interval=1000) # 1 second- 10000 milliseconds
plt.show()
为了让你的绘图逻辑正常工作,文件应该这样写
with open('new.txt', 'w') as out_file:
for count in range(12000):
x = random.randint(0,10000)
y = random.randint(0,10000)
outfile.write("{},{}\n".format(x, y))
此外,您阅读这样的行
def animate(i):
xs = []
ys = []
with open('filename') as graph_data:
for line in graph_data:
x, y = line.split(',')
xs.append(x)
ys.append(y)
ax1.clear()
ax1.plot(xs,ys)