要在 python 中列出的网址代码

Question

   finalKeywords = [] 
   #after populating finalKeywords 
   query = {
       "apiKey" : self.apikey,
        "country" : country,
        "currency" : currency,
        "kw" : finalKeywords,
        "t" : int(time.time())
    }
    uri = urllib.urlencode(query, True)
    print uri

解码uri后我得到

country=&apiKey=5f0092f1777c3a5ed0de&kw=iphone&kw=android&t=1496924489&currency=usd

虽然我的预期输出是

country=&apiKey=5f0092f1777c3a5ed0de&kw[0]=iphone&kw[1]=android&t=1496924489&currency=usd

怎么办..？我一直在寻找解决方案，但无法得到。

Answer 1

像这样？

query = {
       "apiKey" : self.apikey,
        "country" : country,
        "currency" : currency,
        "kw[]" : finalKeywords,
        "t" : int(time.time())
    }

如果出于某种原因您也需要在其中包含位置值，这是一种方法：

query = {
        "apiKey" : self.apikey,
        "country" : country,
        "currency" : currency,
        "t" : int(time.time())
    }
for p,q in enumerate(finalKeywords):
   query["kw[{pos}]".format(pos=p)] = q

Answer 2

基于 the W3C spec for URLs，[ 和 ] 在搜索字符串中无效，因此将被 urlencode 转义。有了这个警告，您可以通过使用字典理解来构建具有唯一键的字典：

kw_dict = { "kw[{}]".format(n): finalKeywords[n] for n in range(0, len(finalKeywords)) }

然后您可以将其添加到查询的其他部分，如下所示：

query = dict({
    "apiKey" : self.apikey,
    "country" : country,
    "currency" : currency,
    "t" : int(time.time())
}, **kw_dict)

要在 python 中列出的网址代码

Urlencode to list in python

python

urllib2

urllib