在 react-router v4 中嵌套路由

Question

我已经在我的应用程序中将 React 路由器升级到版本 4。但是现在我得到了错误

Warning: You should not use <Route component> and <Route children> in the same route; <Route children> will be ignored

这个路由有什么问题？

import {
    Switch,
    BrowserRouter as Router,
    Route, IndexRoute, Redirect,
    browserHistory
} from 'react-router-dom'   

render((
    <Router history={ browserHistory }>
        <Switch>
            <Route path='/' component={ Main }>
                <IndexRoute component={ Search } />
                <Route path='cars/:id' component={ Cars } />
                <Route path='vegetables/:id' component={ Vegetables } />
            </Route>
            <Redirect from='*' to='/' />
        </Switch>
    </Router>
), document.getElementById('main'))

Answer 1

IndexRoute 和 browserHistory 在最新版本中不可用，并且 Routes 不接受 v4 的子 Routes，相反，您可以在组件本身中指定 Routes

import {
    Switch,
    BrowserRouter as Router,
    Route,  Redirect
} from 'react-router-dom'   

render((
    <Router>
        <Switch>
            <Route exact path='/' component={ Main }/>

            <Redirect from='*' to='/' />
        </Switch>
    </Router>
), document.getElementById('main'))

然后在主组件

render() {
     const {match} = this.props;
     return (
        <div>
           {/* other things*/}
           <Route exact path="/" component={ Search } />
           <Route path={`${match.path}cars/:id`} component={ Cars } />
         </div>
    )

}

同样在汽车组件中

你将拥有

render() {
     const {match} = this.props;
     return (
        <div>
           {/* other things*/}
           <Route path={`${match.path}/vegetables/:id`} component={ Vegetables } />
        </div>
    )

}

Answer 2

嵌套路由在版本 react-router 4.x 中不可用。这是关于如何在 v4.x.

中为嵌套路由 secnarios 编码的 basic example straight from react-router documentation

也看看这个问题

在 react-router v4 中嵌套路由

Nesting Routes in react-router v4

reactjs

react-router

url-routing

react-router-v4