Sql 服务器 2016 在第 5 个逗号后拆分

Question

我需要拆分以下字符串

10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29

到

10, 11, 12, 13, 14
15, 16, 17, 18, 19
20, 21, 22, 23, 24
25, 26, 27, 28, 29

Answer 1

对此有类似的答案 - 尝试以下 link：SQL Server - find nth occurrence in a string

您要做的是找到子字符串的第 N 次出现。我相信当我遇到这个问题时，我使用了上述 link 中接受的答案来解决这个问题。

Answer 2

create function dbo.SplitString (@string varchar(max), @delimiter char(1), @Occurence int)
returns @t table
(
    String varchar(max)
)
as

begin
declare @i int = 0
    , @k int = 1
    , @j int = 0
    , @str varchar(max);

if right(@string, 1) <> ','
    set @string = @string + ',';

while CHARINDEX(@delimiter, @string, @i + 1) > 0
begin
    set @i = CHARINDEX(@delimiter, @string, @i + 1);
    set @j = @j + 1;

    if @j = @Occurence or CHARINDEX(@delimiter, @string, @i + 1) = 0
    begin
        insert into @t (String)
        select SUBSTRING (@string, @k, @i - @k);

        set @k = @i + 1;
        set @j = 0;
    end


end

return;

end

select *
from dbo.SplitString ('10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29', ',', 5);

Answer 3

另一种解决方案不是很好，但它仍然在集合操作中而不是循环，如下所示：

Declare @str varchar(100) = '10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25'

;With cte as
    (
    select RowN = Row_Number() over (order by (SELECT NULL)), *, SplitValue= Case When (Row_Number() over (order by (Select NULL)) % 5 = 0 ) then [Value]+ '$' else [Value] end 
    from string_Split(@str, ',')
    ) 
    Select * from string_split( Stuff((Select ', ' + SplitValue from cte for xml path('')),1,1,''), '$')

Sql 服务器 2016 在第 5 个逗号后拆分

Sql server 2016 split after 5th comma

sql

sql-server

sql-server-2016-express