如何在 MySQL 中更新具有不同参数的查询

How to UPDATE a query with different arguments in MySQL

环境

Node.js, MySQL (using node-mysql library connect)

起初

我可以 one argument 'aaa'two arguments 'aaa' and 'bbb'

UPDATE user SET email = 'aaa' WHERE uid = 'xxx';
UPDATE user SET email = 'aaa', password = 'bbb' WHERE uid = 'xxx';

我的问题

如何使用一个查询来克服上述情况?就像下面...

var sql = "UPDATE user SET email = ?, password = ? WHERE uid = ?;"
dbclient.query(sql, [email, password, uid], function (err, results) {
    ...
});
  1. 如果两个参数是 defined,变量 sql 是:

    sql = "UPDATE user SET email = 'test@mail.com', password = 'abcd' WHERE uid = 1;";
    
  2. 如果有人参数是 undefined,变量 sql 是:

    sql = "UPDATE user SET email = 'test@mail.com', password = password WHERE uid = 1;";
    

请阅读文档,尤其是 escaping query values 部分。 node-mysql 支持对象序列化的一些巧妙使用。

以下示例应该是您想要的(它使用格式,但 query() 内部也是):

var mysql = require( 'mysql' );

var credfull = {
        email: "a@exemple.com",
        password: "secret"
    },
    crednopwd = {
        email: "a@exemple.com"
    },
    whereclause = {
        uid: "blabla"
    };

console.log( mysql.format( 'UPDATE user SET ? WHERE ?', [credfull, whereclause]) );
// UPDATE user SET `email` = 'a@exemple.com', `password` = 'secret' WHERE `uid` = 'blabla'

console.log( mysql.format( 'UPDATE user SET ? WHERE ?', [crednopwd, whereclause]) );
// UPDATE user SET `email` = 'a@exemple.com' WHERE `uid` = 'blabla'

希望对您有所帮助。