Python 通过套接字发送文件
Python sending files over socket
我想做一个文件调度程序,服务器加载文件列表,然后根据每个客户端请求一个一个地发送它们。
想法是在 5 个服务器之间分配许多文件的处理。
如何为每个客户端连接调用 ClientThread class?
脚本只被编程为向每个客户端请求发送相同的文件,我想要的是从每个客户端请求中的文件列表发送不同的文件。
Server.py
import socket
from threading import Thread
from socketserver import ThreadingMixIn
TCP_IP = '10.30.16.28'
TCP_PORT = 1006
BUFFER_SIZE = 1024
class ClientThread(Thread):
def __init__(self,ip,port,sock):
Thread.__init__(self)
self.ip = ip
self.port = port
self.sock = sock
print(" New thread started for "+ip+":"+str(port))
def run(self):
filename='log.VW.20170214a.log'
f = open(filename,'rb')
while True:
l = f.read(BUFFER_SIZE)
while (l):
self.sock.send(l)
l = f.read(BUFFER_SIZE)
if not l:
f.close()
self.sock.close()
break
tcpsock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
tcpsock.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
tcpsock.bind((TCP_IP, TCP_PORT))
threads = []
with open("list.txt") as x: #File containing files list
lines=x.read().splitlines()
while True:
tcpsock.listen(5)
print("Waiting for incoming connections...")
(conn, (ip,port)) = tcpsock.accept()
print('Got connection from ', (ip,port))
newthread = ClientThread(ip,port,conn)
newthread.start()
threads.append(newthread)
for t in threads:
t.join()
Client.py
import socket
TCP_IP = '10.30.16.28'
TCP_PORT = 1006
BUFFER_SIZE = 1024
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((TCP_IP, TCP_PORT))
with open('received_file', 'wb') as f:
print('file opened')
while True:
data = s.recv(BUFFER_SIZE)
if not data:
f.close()
print('file close()')
break
f.write(data)
print('Successfully get the file')
s.close()
print('connection closed')
我看不出这与线程或端口或类似的东西有什么关系。改变这个:
def __init__(self,ip,port,sock,fname):
Thread.__init__(self)
self.ip = ip
self.port = port
self.sock = sock
self.fname = fname
print(" New thread started for "+ip+":"+str(port))
def run(self):
f = open(self.fname,'rb')
当你发球时:
with open("list.txt") as x: #File containing files list
lines=iter(x.read().splitlines())
最后:
newthread = ClientThread(ip,port,conn,lines.next().strip())
lines.next()
完成后会抛出 StopIteration
异常,所以你必须处理它。
我想做一个文件调度程序,服务器加载文件列表,然后根据每个客户端请求一个一个地发送它们。 想法是在 5 个服务器之间分配许多文件的处理。
如何为每个客户端连接调用 ClientThread class?
脚本只被编程为向每个客户端请求发送相同的文件,我想要的是从每个客户端请求中的文件列表发送不同的文件。
Server.py
import socket
from threading import Thread
from socketserver import ThreadingMixIn
TCP_IP = '10.30.16.28'
TCP_PORT = 1006
BUFFER_SIZE = 1024
class ClientThread(Thread):
def __init__(self,ip,port,sock):
Thread.__init__(self)
self.ip = ip
self.port = port
self.sock = sock
print(" New thread started for "+ip+":"+str(port))
def run(self):
filename='log.VW.20170214a.log'
f = open(filename,'rb')
while True:
l = f.read(BUFFER_SIZE)
while (l):
self.sock.send(l)
l = f.read(BUFFER_SIZE)
if not l:
f.close()
self.sock.close()
break
tcpsock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
tcpsock.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
tcpsock.bind((TCP_IP, TCP_PORT))
threads = []
with open("list.txt") as x: #File containing files list
lines=x.read().splitlines()
while True:
tcpsock.listen(5)
print("Waiting for incoming connections...")
(conn, (ip,port)) = tcpsock.accept()
print('Got connection from ', (ip,port))
newthread = ClientThread(ip,port,conn)
newthread.start()
threads.append(newthread)
for t in threads:
t.join()
Client.py
import socket
TCP_IP = '10.30.16.28'
TCP_PORT = 1006
BUFFER_SIZE = 1024
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((TCP_IP, TCP_PORT))
with open('received_file', 'wb') as f:
print('file opened')
while True:
data = s.recv(BUFFER_SIZE)
if not data:
f.close()
print('file close()')
break
f.write(data)
print('Successfully get the file')
s.close()
print('connection closed')
我看不出这与线程或端口或类似的东西有什么关系。改变这个:
def __init__(self,ip,port,sock,fname):
Thread.__init__(self)
self.ip = ip
self.port = port
self.sock = sock
self.fname = fname
print(" New thread started for "+ip+":"+str(port))
def run(self):
f = open(self.fname,'rb')
当你发球时:
with open("list.txt") as x: #File containing files list
lines=iter(x.read().splitlines())
最后:
newthread = ClientThread(ip,port,conn,lines.next().strip())
lines.next()
完成后会抛出 StopIteration
异常,所以你必须处理它。