php

Question

我有 2 个数组 arr1 和 arr2。我想合并它们而不复制或覆盖 arr1.

中的数组值

arr1
(
    [0] => Array (
    [aName] => Doe jones
    [ref] => 3
    [afield] => 01-06-2015
    )

    [1] => Array (
    [aName] => John doe
    [ref] => 5
    [afield] => 01-10-2015
    )

    [2] => Array (
    [aName] => Peter Griffin
    [ref] => 7
    [afield]
    )

)
arr2
(
    [0] => Array (
    [aName] => Doe jones
    [ref] => null
    [afield] => null
    )

    [1] => Array (
    [aName] => John doe
    [ref] => null
    [afield] => null
    )

    [2] => Array (
    [aName] => Peter Griffin
    [ref] => null
    [afield] => null
    )

    [3] => Array (
    [aName] => Stuart Griffin
    [ref] => null
    [afield] => null
    )

)

期望的输出：

newArr
(
    [0] => Array (
    [aName] => Doe jones
    [ref] => 3
    [afield] => 01-06-2015
    )

    [1] => Array (
    [aName] => John doe
    [ref] => 5
    [afield] => 01-10-2015
    )

    [2] => Array (
    [aName] => Peter Griffin
    [ref] => 7
    [afield]
    )

    [3] => Array (
    [aName] => Stuart Griffin
    [ref] => null
    [afield] => null
    )

)

我已经设法通过一系列嵌套的 foreach 循环和 if 语句实现了这一点。然而，这似乎是执行此任务的一种非常低效的方法。

我认为下面的功能组合可以工作，但没有达到预期的效果

$newArray = array_unique(array_merge($arr1, $arr2));

Answer 1

你不能使用那种方法来做你想做的事情，因为你有一些功能规则，比如合并具有相同名称的项目而不是空值删除空值。 array_merge 和 array_unique 不知道该规则。

你可以使用那种功能：

function mergeArray(array $arr1, array $arr2) {
    $mergedArray = array();

    foreach ($arr1 as $item1) {
        $mergedArray[$item1['aName']] = $item1;
    }

    foreach ($arr2 as $item2) {
        if (!isset($mergedArray[$item2['aName']]) {
            $mergedArray[$item2['aName']] = $item2;
        } else {
            $item = $mergedArray[$item2['aName']];
            foreach ($item as $key => $value) {
                if (null === $value && isset($item2[$key])) {
                    $mergedArray[$item2['aName']][$key] = $item2[$key];
                }
            }
        }
    }

    return $mergedArray;
}

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