如何根据开始和结束日期只获得重叠的记录？

Question

我有一个 table 查询如下：我试图在 [Assignment Start Date] 和 [Assignment End Date] 之间获取相同 Employee Id 的重叠记录。简而言之，我需要那些 Employee Id 的数据，这些数据是在下面的示例中分配给相同时间段或重叠时间段的。例如

  [Employee Id]   [Assignment Start Date]     [Assignment End Date]   [Allocation Percentage]

        100                2016-03-01                 2017-02-28             100
        102                2016-06-01                 2016-12-31             100
        102                2016-07-01                 2016-10-30             100
        102                2016-11-01                 2017-01-31             100
        103                2017-02-01                 2017-05-30             100
        102                2017-04-01                 2017-06-30             100
        102                2017-11-01                 2017-01-31             100
        104                2017-02-01                 2017-05-01             100



CREATE TABLE #Result
(
PK INT IDENTITY(1,1),
[BU] VARCHAR(20),
[Division] VARCHAR(20),
[Product Name] VARCHAR(30),
[Employee ID] NVARCHAR(20),
[Resource Name] VARCHAR(50),
[Resource_ID] INT,
[Assignment Start Date] DATE,
[Assignment End Date] DATE,
[Allocation Percentage] INT,
[Location] VARCHAR(100),
[Development Manager] VARCHAR(50),
[Allocation] VARCHAR(20)
);


SELECT  DISTINCT r1.PK, r1.Resource_ID,r1.[Employee ID], r1.[Assignment Start Date] AS 'Start 1' ,r1.[Assignment End Date] AS 'End 1' , r2.[Assignment Start Date] , r2.[Assignment End Date]
INTO #temp1
FROM #Result r1

INNER JOIN #Result r2
ON r1.[Employee ID] = r2.[Employee ID]
AND (r1.PK <> r2.PK)
AND ((r1.[Assignment Start Date] <= r2.[Assignment Start Date]) AND (r1.[Assignment End Date] >= r2.[Assignment Start Date]))
OR ((r1.[Assignment Start Date] > r2.[Assignment Start Date] AND r1.[Assignment Start Date] <= r2.[Assignment End Date]) AND (r1.[Assignment End Date] <= r2.[Assignment End Date]))
OR ((r1.[Assignment Start Date] > r2.[Assignment Start Date] AND r1.[Assignment Start Date]  <= r2.[Assignment End Date]) AND (r1.[Assignment End Date] > r2.[Assignment End Date]))
OR (r1.[Assignment Start Date]  = r2.[Assignment End Date])

我试过使用上面的查询，但它提供了与重叠员工相关的所有记录，即使该员工的条目没有重叠。

在上面的示例中有一个 Employee Id 102，它有 2 个重叠的条目和第 3 个不重叠的条目我想从这个结果中删除它。请帮忙

Answer 1

CTE，row_number 和自连接

with CTE as
(
select PK, Resource_ID, [Employee ID] as Emp_ID, [Assignment Start Date] as s_Date, [Assignment End Date] as e_date,
       row_number() over(partition by [Employee ID] order by  [Assignment Start Date] ) as rn
from #Result
)
select t1.*, t2.*
from CTE t1
inner join CTE t2
  on t1.Resource_ID = t2.Resource_ID
  and t1.Emp_ID = t2.Emp_ID
  and t2.rn = t1.rn +1
where t2.s_date <= t1.e_date 
or t1.e_date is null -- allows for null end date

Answer 2

您的 SQL 查询应如下所示：

SELECT DISTINCT r1.PK, r1.Resource_ID,r1.[Employee ID], r1.[Assignment Start Date] AS 'Start 1' ,r1.[Assignment End Date] AS 'End 1' , r2.[Assignment Start Date] , r2.[Assignment End Date]
INTO #temp1
FROM #Result r1
JOIN #Result r2 on r1.[Employee ID] = r2.[Employee ID]
WHERE (
(r2.[Assignment Start Date]  BETWEEN r1.[Assignment Start Date]  and r1.[Assignment End Date])
or
(r2.[Assignment End Date] between p1.[Assignment Start Date]  and p1.[Assignment End Date])
)
AND r1.PK <> r2.PK

如何根据开始和结束日期只获得重叠的记录？

how to get only overlapping records based on start and end date?

sql

sql-server-2014-express