编写网站开启程序

Question

我正在使用 python 脚本接收包含一堆网站 URL 的文件，并在新选项卡中打开所有这些文件。但是，我在打开第一个网站时收到一条错误消息：这是我得到的：

0:41: execution error: "https://www.pandora.com/ " doesn’t understand the “open location” message. (-1708)

到目前为止，我的脚本如下所示：

import os
import webbrowser
websites = []
with open("websites.txt", "r+") as my_file:
    websites.append(my_file.readline())
for x in websites:
    try:
        webbrowser.open(x)
    except:
        print (x + " does not work.")

我的文件由一堆独立的 URL 组成。

Answer 1

我试过运行你的代码，它在我的机器上运行 python 2.7.9

打开文件时可能是字符编码问题

这是我对以下修改的建议：


import webbrowser

with open("websites.txt", "r+") as sites:
   sites =  sites.readlines()      # readlines returns a list of all the lines in your file, this makes code more concise
                                   # In addition we can use the variable 'sites' to hold the list returned to us by the file object 'sites.readlines()'


print sites               # here we send the output of the list to the shell to make sure it contains the right information

for url in sites:
    webbrowser.open_new_tab( url.encode('utf-8') )   # this is here just in-case, to encode characters that the webbrowser module can interpret
                                                            # sometimes special characters like '\' or '/' can cause issues for us unless we encode/decode them or make them raw strings

希望对您有所帮助！

编写网站开启程序

Scripting a website-opener

python

file-io

python-webbrowser