我如何 return Flask-restful 中的错误消息？

Question

我在 Post 方法上添加了一个检查，只允许不同日期的约会通过，但我不知道如何 return 一个错误消息。这是代码

from flask_restful import Resource, Api, request
from package.model import conn


class Appointments(Resource):

    def get(self):
        appointment = conn.execute("SELECT p.*,d.*,a.* from appointment a LEFT JOIN patient p ON a.pat_id = p.pat_id LEFT JOIN doctor d ON a.doc_id = d.doc_id ORDER BY appointment_date DESC").fetchall()
        return appointment

    def post(self):
        appointment = request.get_json(force=True)
        pat_id = appointment['pat_id']
        doc_id = appointment['doc_id']
        appointment_date = appointment['appointment_date']

        a = conn.execute("SELECT count(*) From appointment WHERE doc_id =?
         AND appointment_date=?",(doc_id,appointment_date,)).fetchone()
        if a['count(*)'] == 0:
            appointment['app_id'] = conn.execute('''INSERT INTO appointment(pat_id,doc_id,appointment_date)VALUES(?,?,?)''', (pat_id, doc_id,appointment_date)).lastrowid
            conn.commit()
            return appointment
        else:
            pass

我用什么 return 代替 pass 语句？

PS：对于上下文，我正在努力改进 https://github.com/tushariscoolster/HospitalManagementSystem

Answer 1

Flask-Restful 提供了一个 abort 函数，它可以引发带有特殊 HTTP 代码的 HTTPException 并将消息返回给客户端。

因此，您可以尝试更改如下代码：

from flask_restful import abort

class Appointments(Resource):
    def post(self):
        # ignore some code
        if a['count(*)'] == 0:
           # ignore some code
        else:
           abort(403, error_message='just accept an appointment on special date')

然后，客户端将收到 403 和一个有效的 JSON 字符串，如下所示：

{"error_message":"just accept an appointment on special date"}

最后，客户端要妥善处理错误信息。

我如何 return Flask-restful 中的错误消息？

How do I return an error message in Flask-resful?

python

error-handling

flask

flask-restful