Android Studio - 以编程方式删除 table 行
Android Studio - removing table row programmatically
我已经从数组列表
动态创建了一个table
for (int i = 0; i < arrayList.size(); i++) {
TextView name = new TextView(this);
TextView time = new TextView(this);
TableRow row = new TableRow(this);
// Set event name and remaining time
name.setText(arrayList.get(i).name);
time.setText("...");
// Add text views to row
row.addView(time, layoutParams);
row.addView(name, layoutParams);
// Add row to table
tableLayout.addView(row, i);
}
现在,如果我想在某个条件下编辑或删除某些行,我将必须访问该行,但是如何访问?
outerloop:
for(int i = 0; i < arrayList.size(); i++ ) {
if(// row's time <= 0 ...) {
tableLayout.removeViewAt(i); // this doesn't seem to work properly
// it removes the wrong rows
}
else {
// ...
break outerloop;
}
}
出于某种原因 tableLayout.removeViewAt(i);
删除了不正确的行。或者,我更愿意编辑该行的 name
,但原则适用,我只需要找到一种方法来访问 table 行。有什么办法吗?
像这样创建您的 table:
ArrayList<TableRow> rows = new ArrayList<>();
for (int i = 0; i < arrayList.size(); i++) {
TextView name = new TextView(this);
TextView time = new TextView(this);
TableRow row = new TableRow(this);
rows.add(row);
// Set event name and remaining time
name.setText(arrayList.get(i).name);
time.setText("...");
// Add text views to row
row.addView(time, layoutParams);
row.addView(name, layoutParams);
// Add row to table
tableLayout.addView(row, i);
}
如果你现在想删除一行,你可以通过它在 ArrayList 中的索引来实现:
row = rows.get(i);
table.removeView(row);
rows.remove(i);
如果您想删除多行,这可能是适合您的解决方案:
ArrayList<TableRow> removeRows = new ArrayList<>();
for(int i = 0; i < rows.size(); i++) {
if(....) {
removeRows.add(rows.get(i));
}
}
// now delete those rows
for(TableRow remove : removeRows) {
tableLayout.removeView(row);
rows.remove(remove);
}
希望这对你有用!
我已经从数组列表
动态创建了一个table for (int i = 0; i < arrayList.size(); i++) {
TextView name = new TextView(this);
TextView time = new TextView(this);
TableRow row = new TableRow(this);
// Set event name and remaining time
name.setText(arrayList.get(i).name);
time.setText("...");
// Add text views to row
row.addView(time, layoutParams);
row.addView(name, layoutParams);
// Add row to table
tableLayout.addView(row, i);
}
现在,如果我想在某个条件下编辑或删除某些行,我将必须访问该行,但是如何访问?
outerloop:
for(int i = 0; i < arrayList.size(); i++ ) {
if(// row's time <= 0 ...) {
tableLayout.removeViewAt(i); // this doesn't seem to work properly
// it removes the wrong rows
}
else {
// ...
break outerloop;
}
}
出于某种原因 tableLayout.removeViewAt(i);
删除了不正确的行。或者,我更愿意编辑该行的 name
,但原则适用,我只需要找到一种方法来访问 table 行。有什么办法吗?
像这样创建您的 table:
ArrayList<TableRow> rows = new ArrayList<>();
for (int i = 0; i < arrayList.size(); i++) {
TextView name = new TextView(this);
TextView time = new TextView(this);
TableRow row = new TableRow(this);
rows.add(row);
// Set event name and remaining time
name.setText(arrayList.get(i).name);
time.setText("...");
// Add text views to row
row.addView(time, layoutParams);
row.addView(name, layoutParams);
// Add row to table
tableLayout.addView(row, i);
}
如果你现在想删除一行,你可以通过它在 ArrayList 中的索引来实现:
row = rows.get(i);
table.removeView(row);
rows.remove(i);
如果您想删除多行,这可能是适合您的解决方案:
ArrayList<TableRow> removeRows = new ArrayList<>();
for(int i = 0; i < rows.size(); i++) {
if(....) {
removeRows.add(rows.get(i));
}
}
// now delete those rows
for(TableRow remove : removeRows) {
tableLayout.removeView(row);
rows.remove(remove);
}
希望这对你有用!