如何替换 php 中的某个字符

Question

我需要可以输出以下单个字符串的人

[{"mobile":"XXX-XXX-XXXX","permaddress":"{\"country\":\"country\",\"state\":\"state\",\"city\":\"city\",\"street\":\"street\"}","tempaddress":"{\"country\":\"country\",\"state\":\"state\",\"city\":\"city\",\"street\":\"street\"}"}]1

到

{"mobile":"XXX-XXX-XXXX", "permaddress":"{\"country\":\"country\",\"state\":\"state\",\"city\":\"city\",\"street\":\"street\"}", "tempaddress":"{\"country\":\"country\",\"state\":\"state\",\"city\":\"city\",\"street\":\"street\"}"}

帮我删除上面字符串中的第一个“[”和最后一个“]1”。提前致谢

Answer 1

这将从您的字符串中删除第一个和最后一个字符

$result = substr($string, 1, -2);

如果您想探索更多，请点击 link： https://www.w3schools.com/php/func_string_substr.asp

Answer 2

您可以使用 str_replace 或 preg_replace 将关键字替换为空字符串。

Answer 3

尝试ltrim() and rtrim()

$str = '[{"mobile":"XXX-XXX-XXXX","permaddress":"{\"country\":\"country\",\"state\":\"state\",\"city\":\"city\",\"street\":\"street\"}","tempaddress":"{\"country\":\"country\",\"state\":\"state\",\"city\":\"city\",\"street\":\"street\"}"}]1';
$getTrim = ltrim($str, '[');
$getTrim =  rtrim($getTrim, ']1');
echo $getTrim;

或

$getTrim =  rtrim(ltrim($str, '['), ']1');

Answer 4

试试下面的代码，

<?php
$str = '[{"mobile":"XXX-XXX-XXXX","permaddress":"{\"country\":\"country\",\"state\":\"state\",\"city\":\"city\",\"street\":\"street\"}","tempaddress":"{\"country\":\"country\",\"state\":\"state\",\"city\":\"city\",\"street\":\"street\"}"}]1';
$temp_str = preg_replace('/\[/',"",$str);
$new_str = str_replace("]1","",$temp_str);
echo $new_str;
?>

输出，

{"mobile":"XXX-XXX-XXXX","permaddress":"{\"country\":\"country\",\"state\":\"state\",\"city\":\"city\",\"street\":\"street\"}","tempaddress":"{\"country\":\"country\",\"state\":\"state\",\"city\":\"city\",\"street\":\"street\"}"}

Answer 5

这应该适合你。

$final_str =  rtrim(ltrim($your_str, '['), ']1');

如何替换 php 中的某个字符

How to replace certain character in php

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str-replace