使用 NSPredicate 按关键字过滤 NSArray
Using NSPredicate to filter NSArray by keywords
我有一个名为 myArray
的 NSArray。我想过滤 myArray
个对象,以便我从该数组中排除与另一个数组 keywords
.
中的关键字相对应的所有元素
所以,这是我的伪代码:
keywords = @[@"one", @"three"];
myArray = @[@"textzero", @"textone", @"texttwo", @"textthree", @"textfour"];
predicate = [NSPredicate predicateWithFormat:@"NOT (SELF CONTAINS_ANY_OF[cd] %@), keywords];
myArray = [myArray filteredArrayUsingPredicate:predicate];
这就是我想通过 NSLog(@"%@", myArray)
得到的
>> ("textzero", "texttwo", "textfour")
我应该怎么做?
使用此代码:
NSArray *keywords = @[@"one", @"three"];
NSArray *myArray = @[@"textzero", @"textone", @"texttwo", @"textthree", @"textfour"];
NSString * string = [NSString stringWithFormat:@"NOT SELF CONTAINS[c] '%@'", [keywords componentsJoinedByString:@"' AND NOT SELF CONTAINS[c] '"]];
NSPredicate* predicate = [NSPredicate predicateWithFormat:string];
NSArray* filteredData = [myArray filteredArrayUsingPredicate:predicate];
NSLog(@"Complete array %@", filteredData);
您可以使用块来过滤数组。通常一个块更快。
keywords = @[@"one", @"three"];
myArray = @[@"textzero", @"textone", @"texttwo", @"textthree", @"textfour"];
predicate = [NSPredicate predicateWithBlock:^(NSString *evaluatedObject, NSDictionary<NSString *,id> *bindings){
for (NSString *key in keywords)
if ([evaluatedObject rangeOfString:key options:NSCaseInsensitiveSearch | NSDiacriticInsensitiveSearch].location != NSNotFound)
return NO;
return YES;
}];
myArray = [myArray filteredArrayUsingPredicate:predicate];
或
keywords = @[@"one", @"three"];
myArray = @[@"textzero", @"textone", @"texttwo", @"textthree", @"textfour"];
NSIndexSet *indices = [myArray indexesOfObjectsPassingTest:^(NSString *obj, NSUInteger idx, BOOL *stop){
for (NSString *key in keywords)
if ([obj rangeOfString:key options:NSCaseInsensitiveSearch | NSDiacriticInsensitiveSearch].location != NSNotFound)
return NO;
return YES;
}];
myArray = [myArray objectsAtIndexes:indices];
我有一个名为 myArray
的 NSArray。我想过滤 myArray
个对象,以便我从该数组中排除与另一个数组 keywords
.
所以,这是我的伪代码:
keywords = @[@"one", @"three"];
myArray = @[@"textzero", @"textone", @"texttwo", @"textthree", @"textfour"];
predicate = [NSPredicate predicateWithFormat:@"NOT (SELF CONTAINS_ANY_OF[cd] %@), keywords];
myArray = [myArray filteredArrayUsingPredicate:predicate];
这就是我想通过 NSLog(@"%@", myArray)
>> ("textzero", "texttwo", "textfour")
我应该怎么做?
使用此代码:
NSArray *keywords = @[@"one", @"three"];
NSArray *myArray = @[@"textzero", @"textone", @"texttwo", @"textthree", @"textfour"];
NSString * string = [NSString stringWithFormat:@"NOT SELF CONTAINS[c] '%@'", [keywords componentsJoinedByString:@"' AND NOT SELF CONTAINS[c] '"]];
NSPredicate* predicate = [NSPredicate predicateWithFormat:string];
NSArray* filteredData = [myArray filteredArrayUsingPredicate:predicate];
NSLog(@"Complete array %@", filteredData);
您可以使用块来过滤数组。通常一个块更快。
keywords = @[@"one", @"three"];
myArray = @[@"textzero", @"textone", @"texttwo", @"textthree", @"textfour"];
predicate = [NSPredicate predicateWithBlock:^(NSString *evaluatedObject, NSDictionary<NSString *,id> *bindings){
for (NSString *key in keywords)
if ([evaluatedObject rangeOfString:key options:NSCaseInsensitiveSearch | NSDiacriticInsensitiveSearch].location != NSNotFound)
return NO;
return YES;
}];
myArray = [myArray filteredArrayUsingPredicate:predicate];
或
keywords = @[@"one", @"three"];
myArray = @[@"textzero", @"textone", @"texttwo", @"textthree", @"textfour"];
NSIndexSet *indices = [myArray indexesOfObjectsPassingTest:^(NSString *obj, NSUInteger idx, BOOL *stop){
for (NSString *key in keywords)
if ([obj rangeOfString:key options:NSCaseInsensitiveSearch | NSDiacriticInsensitiveSearch].location != NSNotFound)
return NO;
return YES;
}];
myArray = [myArray objectsAtIndexes:indices];