时间表内的 datediff

Question

我需要在某些类型的活动之间计算 datedif(ss, start_time, end_time)，我很清楚该怎么做。我的代码是：

WITH WorkDates AS (
SELECT 
    ROW_NUMBER() OVER (PARTITION BY A.NUMBER ORDER BY datestamp DESC) AS RowNumber,
    p2.affected_item as Service,
    p1.close_time as close_time,
    datestamp,
    description,
    a.type,
    a.number as number
from ACTIVITYM1 a
left outer join probsummarym1 p1 on a.number = p1.number
inner join probsummarym2 p2 on p1.number = p2.number
where ((a.type like 'status%'
and (description like '%to Work In Progress%'
or description like '%from Work In Progress%'))  or a.type like 'Closed')
)
SELECT
O1.Service,
O1.number,
O1.close_time,
    sum(DATEDIFF(ss, O2.datestamp, O1.datestamp)) AS sum_of_time
FROM WorkDates O1
LEFT JOIN WorkDates O2
    ON O2.RowNumber = O1.RowNumber + 1
    and O2.number = O1.number
where O2.description like '%to Work In Progress%' 
and (O1.description like '%from Work In Progress%' or O1.type like 'Closed')
group by O1.Service, O1.number, O1.close_time
order by O1.Service, O1.number

我是这样做的，因为我需要在某些类型的活动之间计算它，而许多这样的 'time windows' 应该计算的地方并不是常数。而且它工作得很好，但它计算全职，包括假期，周末

但是我还需要在这里完成一件事。

我想计算 datediff(ss, start_date, end_date) 但仅限于周一至周五。这意味着，例如，如果 start_date 是星期五的 16:00 和 end_date 星期一的 7:00，datediff 应该是 (24:00 - 16:00) + (07:00 - 00:00) = 15 小时。可能吗？

Answer 1

你应该计算周差，然后将其转换为秒，然后从 datediff 中扣除。像这样：

sum(DATEDIFF(ss, O2.datestamp, O1.datestamp) - abs(DATEPART(ww,O2.datestamp) - DATEPART(ww,O1.datestamp)) * 2 * 24 * 60 * 60 ) AS sum_of_time

时间表内的 datediff

datediff inside the time schedule

sql-server

datediff