如何显示 iOS 中 String 服务器响应中数字格式的新行

Question

我收到服务器响应 "We've organizations in following something locations. 1. First test 2. Second test 3. Third test 4. Fourth test. Choose one for more information";

我正在研究 Objective-C 并尝试在 UILabel 中显示，但问题是我想显示为段落。喜欢按以下分割字符串。

我们在以下位置组织。

第一次测试
第二次测试
第三次测试
第四次测试选择一项了解更多信息。

以上是示例，但数据是完全动态的，不知道响应字符串中会有多少个点。

任何人都知道这个。

Answer 1

试试这个：

       NSString *str = @"We've organizations in following something locations. 1. First test 2. Second test 3. Third test 4. Fourth test.";
       str =  [str stringByReplacingOccurrencesOfString:@"1." withString:@"\n 1."];
       str = [str stringByReplacingOccurrencesOfString:@"2" withString:@"\n 2"];
       str = [str stringByReplacingOccurrencesOfString:@"3" withString:@"\n 3"];
       str = [str stringByReplacingOccurrencesOfString:@"4" withString:@"\n 4"];
       yourlbl.text = str;

动态方式

NSString *str = @"We've organizations in following something locations. 1. First test 2. Second test 3. Third test 4. Fourth test.";
    NSCharacterSet *numberCharset = [NSCharacterSet characterSetWithCharactersInString:@"0123456789"];
    NSScanner *theScanner = [NSScanner scannerWithString:str];
    while (![theScanner isAtEnd]) {
        // Eat non-digits and negative sign
        [theScanner scanUpToCharactersFromSet:numberCharset
                                   intoString:NULL];
        int aInt;
        if ([theScanner scanInt:&aInt]) {
         str = [str stringByReplacingOccurrencesOfString:[NSString stringWithFormat:@"%d",aInt] withString:[NSString stringWithFormat:@"\n %d",aInt]];
        }
    }

Answer 2

你可以这样使用

 NSArray *array = [NSArray arrayWithObjects:@"First test",@"Second test",@"Third test" , @"Fourth test Choose one for more information.", nil];

 __block NSString *strConcate = [NSString new];
 [array enumerateObjectsUsingBlock:^(id  _Nonnull obj, NSUInteger idx, BOOL * _Nonnull stop) {

      strConcate = [strConcate stringByAppendingString:[NSString stringWithFormat:@"%lu. %@\n",(unsigned long)(idx + 1),obj]];
 }];

 self.labelString.text = strConcate;

Answer 3

终于，我找到了解决办法，就在这里。这可能对将来的某人有所帮助。

    NSArray *pointsArray = [trimmedString componentsSeparatedByString:@"."];
    NSString *strOccurence, *strReplacing;
    for (int i=1; i<pointsArray.count; i++){
        strOccurence = [NSString stringWithFormat:@"%d.",i];
        strReplacing = [NSString stringWithFormat:@"\n%d.",i];
        trimmedString = [trimmedString stringByReplacingOccurrencesOfString:strOccurence withString:strReplacing];
    }
    cell.textLabel.text  = trimmedString;

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