Netlogo:如何为列表中的每只海龟创建一个 link?

Netlogo: How to create a link with every turtle of a list?

我正在尝试 link 一个品种 (a) 最近孵化的海龟与另一个品种 (b) 的前 N ​​只海龟。我尝试了很多东西,但现在我被卡住了......我最后的想法是从我孵化的海龟到列表中的每只海龟创建一个 link,但它不起作用......这是我的一些试用代码:

(我)

set rank (sort-by [[feat] of ?1 > [feat] of ?2] breed-b)
;;; creates a concatenated list of turtles from breed-b on 
;;; descending order of [feat] like: [[(turtle 6) (turtle 2) (turtle 0)]]

hatch-breed-a 1 [
         let n 3
         ;;; I want to create-link-with the top n turtles of rank

         repeat n [
           ask self [ create-link-with item 0 (item 0 rank) ]
           set rank remove-item 1 rank
         ] ]

        ;;; my idea was to create a link with the first turtle of the list, 
        ;;; then remove that turtle form the list before the next iteration
        ;;; so that the next link would be created with the turtle
        ;;; that was originally the second, but I receive an error message:
        ;;; ITEM expected input to be a string or list 
        ;;; but got the turtle (turtle 6) instead.

(二)

set rank (sort-by [[feat] of ?1 > [feat] of ?2] breed-b)
;;; creates a concatenated list of turtles from breed-b 
;;; on descending order of [feat] like: [[(turtle 6) (turtle 2) (turtle 0)]]


hatch-breed-a 1 [
         let n 3
         ;;; I want to create-link-with the top n turtles of rank

         let i 0  
         while [i < n] [
           ask self [ create-link-with item i rank ]
           set i i + 1
         ] ]

        ;;; my idea here was to create an index (i) so that the while
        ;;; would only take the first n items of rank, but apparently
        ;;; item don't accept a variable (i) only numbers.

感谢您对此的帮助,谢谢!

听起来你想要孵化出来

create-links-with max-n-of n breed-b [feat]

我找到了代码 (I) 的工作方式:

repeat n [ 
  ask self [ 
    create-share-with (first rank) ] 
  set rank but-first rank 
  ]